2013-10-19 15:50:09 -03:00
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"""
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Basic statistics module.
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This module provides functions for calculating statistics of data, including
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averages, variance, and standard deviation.
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Calculating averages
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--------------------
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2019-04-23 04:06:35 -03:00
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================== ==================================================
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2013-10-19 15:50:09 -03:00
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Function Description
|
2019-04-23 04:06:35 -03:00
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================== ==================================================
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2013-10-19 15:50:09 -03:00
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mean Arithmetic mean (average) of data.
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2019-04-23 05:35:16 -03:00
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fmean Fast, floating point arithmetic mean.
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2019-04-07 13:20:03 -03:00
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geometric_mean Geometric mean of data.
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2016-08-08 23:49:01 -03:00
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harmonic_mean Harmonic mean of data.
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2013-10-19 15:50:09 -03:00
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median Median (middle value) of data.
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median_low Low median of data.
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median_high High median of data.
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median_grouped Median, or 50th percentile, of grouped data.
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mode Mode (most common value) of data.
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2019-04-07 13:20:03 -03:00
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multimode List of modes (most common values of data).
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2019-04-23 04:06:35 -03:00
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quantiles Divide data into intervals with equal probability.
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================== ==================================================
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2013-10-19 15:50:09 -03:00
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Calculate the arithmetic mean ("the average") of data:
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>>> mean([-1.0, 2.5, 3.25, 5.75])
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2.625
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Calculate the standard median of discrete data:
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>>> median([2, 3, 4, 5])
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3.5
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Calculate the median, or 50th percentile, of data grouped into class intervals
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centred on the data values provided. E.g. if your data points are rounded to
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the nearest whole number:
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>>> median_grouped([2, 2, 3, 3, 3, 4]) #doctest: +ELLIPSIS
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2.8333333333...
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This should be interpreted in this way: you have two data points in the class
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interval 1.5-2.5, three data points in the class interval 2.5-3.5, and one in
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the class interval 3.5-4.5. The median of these data points is 2.8333...
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Calculating variability or spread
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---------------------------------
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================== =============================================
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Function Description
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================== =============================================
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pvariance Population variance of data.
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variance Sample variance of data.
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pstdev Population standard deviation of data.
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stdev Sample standard deviation of data.
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================== =============================================
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Calculate the standard deviation of sample data:
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>>> stdev([2.5, 3.25, 5.5, 11.25, 11.75]) #doctest: +ELLIPSIS
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4.38961843444...
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If you have previously calculated the mean, you can pass it as the optional
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second argument to the four "spread" functions to avoid recalculating it:
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>>> data = [1, 2, 2, 4, 4, 4, 5, 6]
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>>> mu = mean(data)
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>>> pvariance(data, mu)
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2.5
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2021-04-25 08:45:09 -03:00
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Statistics for relations between two inputs
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-------------------------------------------
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================== ====================================================
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Function Description
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================== ====================================================
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covariance Sample covariance for two variables.
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correlation Pearson's correlation coefficient for two variables.
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linear_regression Intercept and slope for simple linear regression.
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================== ====================================================
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Calculate covariance, Pearson's correlation, and simple linear regression
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for two inputs:
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>>> x = [1, 2, 3, 4, 5, 6, 7, 8, 9]
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>>> y = [1, 2, 3, 1, 2, 3, 1, 2, 3]
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>>> covariance(x, y)
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0.75
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>>> correlation(x, y) #doctest: +ELLIPSIS
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0.31622776601...
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>>> linear_regression(x, y) #doctest:
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2021-05-24 21:30:58 -03:00
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LinearRegression(slope=0.1, intercept=1.5)
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2021-04-25 08:45:09 -03:00
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2013-10-19 15:50:09 -03:00
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Exceptions
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----------
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A single exception is defined: StatisticsError is a subclass of ValueError.
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"""
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2019-07-21 16:13:07 -03:00
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__all__ = [
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'NormalDist',
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'StatisticsError',
|
2021-05-15 15:00:51 -03:00
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'correlation',
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'covariance',
|
2019-07-21 16:13:07 -03:00
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'fmean',
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'geometric_mean',
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'harmonic_mean',
|
2021-05-15 15:00:51 -03:00
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'linear_regression',
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2019-07-21 16:13:07 -03:00
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'mean',
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'median',
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'median_grouped',
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'median_high',
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'median_low',
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'mode',
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'multimode',
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'pstdev',
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'pvariance',
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'quantiles',
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'stdev',
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'variance',
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]
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2013-10-19 15:50:09 -03:00
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import math
|
2016-08-08 23:49:01 -03:00
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import numbers
|
2019-02-23 18:44:07 -04:00
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import random
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2021-11-27 01:54:50 -04:00
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import sys
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2013-10-19 15:50:09 -03:00
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from fractions import Fraction
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from decimal import Decimal
|
2022-08-18 15:48:27 -03:00
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from itertools import count, groupby, repeat
|
2016-05-04 14:54:29 -03:00
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from bisect import bisect_left, bisect_right
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2023-03-12 14:48:25 -03:00
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from math import hypot, sqrt, fabs, exp, erf, tau, log, fsum, sumprod
|
2023-08-11 13:19:19 -03:00
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from math import isfinite, isinf
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2022-02-28 13:43:52 -04:00
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from functools import reduce
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2023-03-12 14:48:25 -03:00
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from operator import itemgetter
|
2022-01-05 11:39:10 -04:00
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from collections import Counter, namedtuple, defaultdict
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2013-10-19 15:50:09 -03:00
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2021-11-09 12:30:06 -04:00
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_SQRT2 = sqrt(2.0)
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2013-10-19 15:50:09 -03:00
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# === Exceptions ===
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class StatisticsError(ValueError):
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pass
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# === Private utilities ===
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2021-09-09 00:00:12 -03:00
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def _sum(data):
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"""_sum(data) -> (type, sum, count)
|
2015-12-01 04:59:53 -04:00
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Return a high-precision sum of the given numeric data as a fraction,
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together with the type to be converted to and the count of items.
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2013-10-19 15:50:09 -03:00
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Examples
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--------
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2021-09-09 00:00:12 -03:00
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>>> _sum([3, 2.25, 4.5, -0.5, 0.25])
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(<class 'float'>, Fraction(19, 2), 5)
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2013-10-19 15:50:09 -03:00
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Some sources of round-off error will be avoided:
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2016-08-08 23:49:01 -03:00
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# Built-in sum returns zero.
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>>> _sum([1e50, 1, -1e50] * 1000)
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2016-07-14 01:13:29 -03:00
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(<class 'float'>, Fraction(1000, 1), 3000)
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2013-10-19 15:50:09 -03:00
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Fractions and Decimals are also supported:
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>>> from fractions import Fraction as F
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>>> _sum([F(2, 3), F(7, 5), F(1, 4), F(5, 6)])
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2016-07-14 01:13:29 -03:00
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(<class 'fractions.Fraction'>, Fraction(63, 20), 4)
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2013-10-19 15:50:09 -03:00
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>>> from decimal import Decimal as D
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>>> data = [D("0.1375"), D("0.2108"), D("0.3061"), D("0.0419")]
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>>> _sum(data)
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2016-07-14 01:13:29 -03:00
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(<class 'decimal.Decimal'>, Fraction(6963, 10000), 4)
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2013-10-19 15:50:09 -03:00
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2014-02-08 05:58:04 -04:00
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Mixed types are currently treated as an error, except that int is
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allowed.
|
2013-10-19 15:50:09 -03:00
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"""
|
2015-12-01 04:59:53 -04:00
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count = 0
|
2022-02-28 13:43:52 -04:00
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types = set()
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types_add = types.add
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2021-09-09 00:00:12 -03:00
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partials = {}
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2013-10-19 15:50:09 -03:00
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partials_get = partials.get
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2015-12-01 04:59:53 -04:00
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for typ, values in groupby(data, type):
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2022-02-28 13:43:52 -04:00
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types_add(typ)
|
2020-06-13 23:17:28 -03:00
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for n, d in map(_exact_ratio, values):
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2015-12-01 04:59:53 -04:00
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count += 1
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partials[d] = partials_get(d, 0) + n
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2013-10-19 15:50:09 -03:00
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if None in partials:
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2015-12-01 04:59:53 -04:00
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# The sum will be a NAN or INF. We can ignore all the finite
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# partials, and just look at this special one.
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total = partials[None]
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assert not _isfinite(total)
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else:
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# Sum all the partial sums using builtin sum.
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2021-09-09 00:00:12 -03:00
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total = sum(Fraction(n, d) for d, n in partials.items())
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2022-02-28 13:43:52 -04:00
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T = reduce(_coerce, types, int) # or raise TypeError
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2015-12-01 04:59:53 -04:00
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return (T, total, count)
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2022-01-05 11:39:10 -04:00
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def _ss(data, c=None):
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2022-05-03 23:22:26 -03:00
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"""Return the exact mean and sum of square deviations of sequence data.
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Calculations are done in a single pass, allowing the input to be an iterator.
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If given *c* is used the mean; otherwise, it is calculated from the data.
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Use the *c* argument with care, as it can lead to garbage results.
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2022-01-05 11:39:10 -04:00
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"""
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if c is not None:
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2022-05-03 23:22:26 -03:00
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T, ssd, count = _sum((d := x - c) * d for x in data)
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return (T, ssd, c, count)
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2022-01-05 11:39:10 -04:00
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count = 0
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2022-02-28 13:43:52 -04:00
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types = set()
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types_add = types.add
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2022-01-05 11:39:10 -04:00
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sx_partials = defaultdict(int)
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sxx_partials = defaultdict(int)
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for typ, values in groupby(data, type):
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2022-02-28 13:43:52 -04:00
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types_add(typ)
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2022-01-05 11:39:10 -04:00
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for n, d in map(_exact_ratio, values):
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count += 1
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sx_partials[d] += n
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sxx_partials[d] += n * n
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if not count:
|
2022-05-03 23:22:26 -03:00
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ssd = c = Fraction(0)
|
2022-01-05 11:39:10 -04:00
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elif None in sx_partials:
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# The sum will be a NAN or INF. We can ignore all the finite
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# partials, and just look at this special one.
|
2022-05-03 23:22:26 -03:00
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ssd = c = sx_partials[None]
|
2022-05-04 01:22:04 -03:00
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assert not _isfinite(ssd)
|
2022-01-05 11:39:10 -04:00
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else:
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sx = sum(Fraction(n, d) for d, n in sx_partials.items())
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|
sxx = sum(Fraction(n, d*d) for d, n in sxx_partials.items())
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# This formula has poor numeric properties for floats,
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# but with fractions it is exact.
|
2022-05-03 23:22:26 -03:00
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ssd = (count * sxx - sx * sx) / count
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|
c = sx / count
|
2022-02-28 13:43:52 -04:00
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T = reduce(_coerce, types, int) # or raise TypeError
|
2022-05-03 23:22:26 -03:00
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return (T, ssd, c, count)
|
2022-01-05 11:39:10 -04:00
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|
2015-12-01 04:59:53 -04:00
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|
def _isfinite(x):
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try:
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return x.is_finite() # Likely a Decimal.
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|
|
except AttributeError:
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|
return math.isfinite(x) # Coerces to float first.
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|
def _coerce(T, S):
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|
|
"""Coerce types T and S to a common type, or raise TypeError.
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|
Coercion rules are currently an implementation detail. See the CoerceTest
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|
test class in test_statistics for details.
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|
"""
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|
|
# See http://bugs.python.org/issue24068.
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|
|
assert T is not bool, "initial type T is bool"
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|
|
# If the types are the same, no need to coerce anything. Put this
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|
# first, so that the usual case (no coercion needed) happens as soon
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|
# as possible.
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|
if T is S: return T
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|
# Mixed int & other coerce to the other type.
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|
if S is int or S is bool: return T
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|
if T is int: return S
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|
|
# If one is a (strict) subclass of the other, coerce to the subclass.
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|
|
if issubclass(S, T): return S
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|
if issubclass(T, S): return T
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|
|
# Ints coerce to the other type.
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|
|
if issubclass(T, int): return S
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|
|
if issubclass(S, int): return T
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|
|
# Mixed fraction & float coerces to float (or float subclass).
|
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|
|
if issubclass(T, Fraction) and issubclass(S, float):
|
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|
|
return S
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|
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|
|
if issubclass(T, float) and issubclass(S, Fraction):
|
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|
|
return T
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|
|
# Any other combination is disallowed.
|
|
|
|
|
msg = "don't know how to coerce %s and %s"
|
|
|
|
|
raise TypeError(msg % (T.__name__, S.__name__))
|
2014-02-08 05:58:04 -04:00
|
|
|
|
|
|
|
|
|
|
2013-10-19 15:50:09 -03:00
|
|
|
|
def _exact_ratio(x):
|
2015-12-01 04:59:53 -04:00
|
|
|
|
"""Return Real number x to exact (numerator, denominator) pair.
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
|
|
|
|
>>> _exact_ratio(0.25)
|
|
|
|
|
(1, 4)
|
|
|
|
|
|
|
|
|
|
x is expected to be an int, Fraction, Decimal or float.
|
|
|
|
|
"""
|
2021-11-30 20:20:08 -04:00
|
|
|
|
|
|
|
|
|
# XXX We should revisit whether using fractions to accumulate exact
|
|
|
|
|
# ratios is the right way to go.
|
|
|
|
|
|
|
|
|
|
# The integer ratios for binary floats can have numerators or
|
|
|
|
|
# denominators with over 300 decimal digits. The problem is more
|
2022-07-12 18:34:23 -03:00
|
|
|
|
# acute with decimal floats where the default decimal context
|
2021-11-30 20:20:08 -04:00
|
|
|
|
# supports a huge range of exponents from Emin=-999999 to
|
|
|
|
|
# Emax=999999. When expanded with as_integer_ratio(), numbers like
|
|
|
|
|
# Decimal('3.14E+5000') and Decimal('3.14E-5000') have large
|
|
|
|
|
# numerators or denominators that will slow computation.
|
|
|
|
|
|
|
|
|
|
# When the integer ratios are accumulated as fractions, the size
|
|
|
|
|
# grows to cover the full range from the smallest magnitude to the
|
|
|
|
|
# largest. For example, Fraction(3.14E+300) + Fraction(3.14E-300),
|
|
|
|
|
# has a 616 digit numerator. Likewise,
|
|
|
|
|
# Fraction(Decimal('3.14E+5000')) + Fraction(Decimal('3.14E-5000'))
|
|
|
|
|
# has 10,003 digit numerator.
|
|
|
|
|
|
|
|
|
|
# This doesn't seem to have been problem in practice, but it is a
|
|
|
|
|
# potential pitfall.
|
|
|
|
|
|
2013-10-19 15:50:09 -03:00
|
|
|
|
try:
|
2021-09-09 00:00:12 -03:00
|
|
|
|
return x.as_integer_ratio()
|
|
|
|
|
except AttributeError:
|
|
|
|
|
pass
|
2013-10-19 15:50:09 -03:00
|
|
|
|
except (OverflowError, ValueError):
|
2015-12-01 04:59:53 -04:00
|
|
|
|
# float NAN or INF.
|
2016-05-04 14:54:29 -03:00
|
|
|
|
assert not _isfinite(x)
|
2013-10-19 15:50:09 -03:00
|
|
|
|
return (x, None)
|
2021-09-09 00:00:12 -03:00
|
|
|
|
try:
|
|
|
|
|
# x may be an Integral ABC.
|
|
|
|
|
return (x.numerator, x.denominator)
|
|
|
|
|
except AttributeError:
|
|
|
|
|
msg = f"can't convert type '{type(x).__name__}' to numerator/denominator"
|
|
|
|
|
raise TypeError(msg)
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
|
|
|
|
|
2015-12-01 04:59:53 -04:00
|
|
|
|
def _convert(value, T):
|
|
|
|
|
"""Convert value to given numeric type T."""
|
|
|
|
|
if type(value) is T:
|
|
|
|
|
# This covers the cases where T is Fraction, or where value is
|
|
|
|
|
# a NAN or INF (Decimal or float).
|
|
|
|
|
return value
|
|
|
|
|
if issubclass(T, int) and value.denominator != 1:
|
|
|
|
|
T = float
|
|
|
|
|
try:
|
|
|
|
|
# FIXME: what do we do if this overflows?
|
|
|
|
|
return T(value)
|
|
|
|
|
except TypeError:
|
|
|
|
|
if issubclass(T, Decimal):
|
2020-06-13 23:17:28 -03:00
|
|
|
|
return T(value.numerator) / T(value.denominator)
|
2015-12-01 04:59:53 -04:00
|
|
|
|
else:
|
|
|
|
|
raise
|
|
|
|
|
|
|
|
|
|
|
2016-08-08 23:49:01 -03:00
|
|
|
|
def _fail_neg(values, errmsg='negative value'):
|
|
|
|
|
"""Iterate over values, failing if any are less than zero."""
|
|
|
|
|
for x in values:
|
|
|
|
|
if x < 0:
|
|
|
|
|
raise StatisticsError(errmsg)
|
|
|
|
|
yield x
|
|
|
|
|
|
2022-08-29 01:41:58 -03:00
|
|
|
|
|
|
|
|
|
def _rank(data, /, *, key=None, reverse=False, ties='average', start=1) -> list[float]:
|
2022-08-18 15:48:27 -03:00
|
|
|
|
"""Rank order a dataset. The lowest value has rank 1.
|
|
|
|
|
|
|
|
|
|
Ties are averaged so that equal values receive the same rank:
|
|
|
|
|
|
|
|
|
|
>>> data = [31, 56, 31, 25, 75, 18]
|
|
|
|
|
>>> _rank(data)
|
|
|
|
|
[3.5, 5.0, 3.5, 2.0, 6.0, 1.0]
|
|
|
|
|
|
|
|
|
|
The operation is idempotent:
|
|
|
|
|
|
|
|
|
|
>>> _rank([3.5, 5.0, 3.5, 2.0, 6.0, 1.0])
|
|
|
|
|
[3.5, 5.0, 3.5, 2.0, 6.0, 1.0]
|
|
|
|
|
|
2022-08-29 01:41:58 -03:00
|
|
|
|
It is possible to rank the data in reverse order so that the
|
|
|
|
|
highest value has rank 1. Also, a key-function can extract
|
|
|
|
|
the field to be ranked:
|
2022-08-18 15:48:27 -03:00
|
|
|
|
|
|
|
|
|
>>> goals = [('eagles', 45), ('bears', 48), ('lions', 44)]
|
|
|
|
|
>>> _rank(goals, key=itemgetter(1), reverse=True)
|
|
|
|
|
[2.0, 1.0, 3.0]
|
|
|
|
|
|
2022-08-29 01:41:58 -03:00
|
|
|
|
Ranks are conventionally numbered starting from one; however,
|
2022-08-29 14:19:48 -03:00
|
|
|
|
setting *start* to zero allows the ranks to be used as array indices:
|
2022-08-29 01:41:58 -03:00
|
|
|
|
|
|
|
|
|
>>> prize = ['Gold', 'Silver', 'Bronze', 'Certificate']
|
|
|
|
|
>>> scores = [8.1, 7.3, 9.4, 8.3]
|
|
|
|
|
>>> [prize[int(i)] for i in _rank(scores, start=0, reverse=True)]
|
|
|
|
|
['Bronze', 'Certificate', 'Gold', 'Silver']
|
|
|
|
|
|
2022-08-18 15:48:27 -03:00
|
|
|
|
"""
|
|
|
|
|
# If this function becomes public at some point, more thought
|
|
|
|
|
# needs to be given to the signature. A list of ints is
|
|
|
|
|
# plausible when ties is "min" or "max". When ties is "average",
|
|
|
|
|
# either list[float] or list[Fraction] is plausible.
|
|
|
|
|
|
|
|
|
|
# Default handling of ties matches scipy.stats.mstats.spearmanr.
|
|
|
|
|
if ties != 'average':
|
|
|
|
|
raise ValueError(f'Unknown tie resolution method: {ties!r}')
|
|
|
|
|
if key is not None:
|
|
|
|
|
data = map(key, data)
|
|
|
|
|
val_pos = sorted(zip(data, count()), reverse=reverse)
|
2022-08-29 01:41:58 -03:00
|
|
|
|
i = start - 1
|
2022-08-18 15:48:27 -03:00
|
|
|
|
result = [0] * len(val_pos)
|
|
|
|
|
for _, g in groupby(val_pos, key=itemgetter(0)):
|
|
|
|
|
group = list(g)
|
|
|
|
|
size = len(group)
|
|
|
|
|
rank = i + (size + 1) / 2
|
|
|
|
|
for value, orig_pos in group:
|
|
|
|
|
result[orig_pos] = rank
|
|
|
|
|
i += size
|
|
|
|
|
return result
|
2021-11-30 20:20:08 -04:00
|
|
|
|
|
2022-08-29 01:41:58 -03:00
|
|
|
|
|
2021-11-30 20:20:08 -04:00
|
|
|
|
def _integer_sqrt_of_frac_rto(n: int, m: int) -> int:
|
2021-11-27 01:54:50 -04:00
|
|
|
|
"""Square root of n/m, rounded to the nearest integer using round-to-odd."""
|
|
|
|
|
# Reference: https://www.lri.fr/~melquion/doc/05-imacs17_1-expose.pdf
|
|
|
|
|
a = math.isqrt(n // m)
|
|
|
|
|
return a | (a*a*m != n)
|
|
|
|
|
|
|
|
|
|
|
2021-11-30 20:20:08 -04:00
|
|
|
|
# For 53 bit precision floats, the bit width used in
|
|
|
|
|
# _float_sqrt_of_frac() is 109.
|
|
|
|
|
_sqrt_bit_width: int = 2 * sys.float_info.mant_dig + 3
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def _float_sqrt_of_frac(n: int, m: int) -> float:
|
2021-11-27 01:54:50 -04:00
|
|
|
|
"""Square root of n/m as a float, correctly rounded."""
|
|
|
|
|
# See principle and proof sketch at: https://bugs.python.org/msg407078
|
2021-11-30 20:20:08 -04:00
|
|
|
|
q = (n.bit_length() - m.bit_length() - _sqrt_bit_width) // 2
|
2021-11-27 01:54:50 -04:00
|
|
|
|
if q >= 0:
|
2021-11-30 20:20:08 -04:00
|
|
|
|
numerator = _integer_sqrt_of_frac_rto(n, m << 2 * q) << q
|
2021-11-27 01:54:50 -04:00
|
|
|
|
denominator = 1
|
|
|
|
|
else:
|
2021-11-30 20:20:08 -04:00
|
|
|
|
numerator = _integer_sqrt_of_frac_rto(n << -2 * q, m)
|
2021-11-27 01:54:50 -04:00
|
|
|
|
denominator = 1 << -q
|
|
|
|
|
return numerator / denominator # Convert to float
|
|
|
|
|
|
2016-08-08 23:49:01 -03:00
|
|
|
|
|
2021-11-30 20:20:08 -04:00
|
|
|
|
def _decimal_sqrt_of_frac(n: int, m: int) -> Decimal:
|
|
|
|
|
"""Square root of n/m as a Decimal, correctly rounded."""
|
|
|
|
|
# Premise: For decimal, computing (n/m).sqrt() can be off
|
|
|
|
|
# by 1 ulp from the correctly rounded result.
|
|
|
|
|
# Method: Check the result, moving up or down a step if needed.
|
|
|
|
|
if n <= 0:
|
|
|
|
|
if not n:
|
|
|
|
|
return Decimal('0.0')
|
|
|
|
|
n, m = -n, -m
|
|
|
|
|
|
|
|
|
|
root = (Decimal(n) / Decimal(m)).sqrt()
|
|
|
|
|
nr, dr = root.as_integer_ratio()
|
|
|
|
|
|
|
|
|
|
plus = root.next_plus()
|
|
|
|
|
np, dp = plus.as_integer_ratio()
|
|
|
|
|
# test: n / m > ((root + plus) / 2) ** 2
|
|
|
|
|
if 4 * n * (dr*dp)**2 > m * (dr*np + dp*nr)**2:
|
|
|
|
|
return plus
|
|
|
|
|
|
|
|
|
|
minus = root.next_minus()
|
|
|
|
|
nm, dm = minus.as_integer_ratio()
|
|
|
|
|
# test: n / m < ((root + minus) / 2) ** 2
|
|
|
|
|
if 4 * n * (dr*dm)**2 < m * (dr*nm + dm*nr)**2:
|
|
|
|
|
return minus
|
|
|
|
|
|
|
|
|
|
return root
|
|
|
|
|
|
|
|
|
|
|
2013-10-19 15:50:09 -03:00
|
|
|
|
# === Measures of central tendency (averages) ===
|
|
|
|
|
|
|
|
|
|
def mean(data):
|
|
|
|
|
"""Return the sample arithmetic mean of data.
|
|
|
|
|
|
|
|
|
|
>>> mean([1, 2, 3, 4, 4])
|
|
|
|
|
2.8
|
|
|
|
|
|
|
|
|
|
>>> from fractions import Fraction as F
|
|
|
|
|
>>> mean([F(3, 7), F(1, 21), F(5, 3), F(1, 3)])
|
|
|
|
|
Fraction(13, 21)
|
|
|
|
|
|
|
|
|
|
>>> from decimal import Decimal as D
|
|
|
|
|
>>> mean([D("0.5"), D("0.75"), D("0.625"), D("0.375")])
|
|
|
|
|
Decimal('0.5625')
|
|
|
|
|
|
|
|
|
|
If ``data`` is empty, StatisticsError will be raised.
|
|
|
|
|
"""
|
2022-01-05 11:39:10 -04:00
|
|
|
|
T, total, n = _sum(data)
|
2013-10-19 15:50:09 -03:00
|
|
|
|
if n < 1:
|
|
|
|
|
raise StatisticsError('mean requires at least one data point')
|
2020-06-13 23:17:28 -03:00
|
|
|
|
return _convert(total / n, T)
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
2019-07-21 16:13:07 -03:00
|
|
|
|
|
2021-05-21 00:22:26 -03:00
|
|
|
|
def fmean(data, weights=None):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""Convert data to floats and compute the arithmetic mean.
|
2019-02-21 19:06:29 -04:00
|
|
|
|
|
|
|
|
|
This runs faster than the mean() function and it always returns a float.
|
|
|
|
|
If the input dataset is empty, it raises a StatisticsError.
|
|
|
|
|
|
|
|
|
|
>>> fmean([3.5, 4.0, 5.25])
|
|
|
|
|
4.25
|
|
|
|
|
"""
|
2021-05-21 00:22:26 -03:00
|
|
|
|
if weights is None:
|
2023-03-12 14:48:25 -03:00
|
|
|
|
try:
|
|
|
|
|
n = len(data)
|
|
|
|
|
except TypeError:
|
|
|
|
|
# Handle iterators that do not define __len__().
|
|
|
|
|
n = 0
|
|
|
|
|
def count(iterable):
|
|
|
|
|
nonlocal n
|
|
|
|
|
for n, x in enumerate(iterable, start=1):
|
|
|
|
|
yield x
|
|
|
|
|
data = count(data)
|
2019-03-12 04:43:27 -03:00
|
|
|
|
total = fsum(data)
|
2021-05-21 00:22:26 -03:00
|
|
|
|
if not n:
|
|
|
|
|
raise StatisticsError('fmean requires at least one data point')
|
2019-02-21 19:06:29 -04:00
|
|
|
|
return total / n
|
2023-03-12 14:48:25 -03:00
|
|
|
|
if not isinstance(weights, (list, tuple)):
|
2021-05-21 00:22:26 -03:00
|
|
|
|
weights = list(weights)
|
2023-03-12 14:48:25 -03:00
|
|
|
|
try:
|
|
|
|
|
num = sumprod(data, weights)
|
|
|
|
|
except ValueError:
|
2021-05-21 00:22:26 -03:00
|
|
|
|
raise StatisticsError('data and weights must be the same length')
|
|
|
|
|
den = fsum(weights)
|
|
|
|
|
if not den:
|
|
|
|
|
raise StatisticsError('sum of weights must be non-zero')
|
|
|
|
|
return num / den
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
2019-07-21 16:13:07 -03:00
|
|
|
|
|
2019-04-07 13:20:03 -03:00
|
|
|
|
def geometric_mean(data):
|
|
|
|
|
"""Convert data to floats and compute the geometric mean.
|
|
|
|
|
|
2023-12-08 14:05:56 -04:00
|
|
|
|
Raises a StatisticsError if the input dataset is empty
|
|
|
|
|
or if it contains a negative value.
|
|
|
|
|
|
|
|
|
|
Returns zero if the product of inputs is zero.
|
2019-04-07 13:20:03 -03:00
|
|
|
|
|
|
|
|
|
No special efforts are made to achieve exact results.
|
|
|
|
|
(However, this may change in the future.)
|
|
|
|
|
|
|
|
|
|
>>> round(geometric_mean([54, 24, 36]), 9)
|
|
|
|
|
36.0
|
|
|
|
|
"""
|
2023-12-08 14:05:56 -04:00
|
|
|
|
n = 0
|
|
|
|
|
found_zero = False
|
|
|
|
|
def count_positive(iterable):
|
|
|
|
|
nonlocal n, found_zero
|
|
|
|
|
for n, x in enumerate(iterable, start=1):
|
|
|
|
|
if x > 0.0 or math.isnan(x):
|
|
|
|
|
yield x
|
|
|
|
|
elif x == 0.0:
|
|
|
|
|
found_zero = True
|
|
|
|
|
else:
|
|
|
|
|
raise StatisticsError('No negative inputs allowed', x)
|
|
|
|
|
total = fsum(map(log, count_positive(data)))
|
|
|
|
|
if not n:
|
|
|
|
|
raise StatisticsError('Must have a non-empty dataset')
|
|
|
|
|
if math.isnan(total):
|
|
|
|
|
return math.nan
|
|
|
|
|
if found_zero:
|
|
|
|
|
return math.nan if total == math.inf else 0.0
|
|
|
|
|
return exp(total / n)
|
2019-04-07 13:20:03 -03:00
|
|
|
|
|
2019-07-21 16:13:07 -03:00
|
|
|
|
|
2020-12-23 23:52:09 -04:00
|
|
|
|
def harmonic_mean(data, weights=None):
|
2016-08-08 23:49:01 -03:00
|
|
|
|
"""Return the harmonic mean of data.
|
|
|
|
|
|
2021-02-07 20:44:42 -04:00
|
|
|
|
The harmonic mean is the reciprocal of the arithmetic mean of the
|
|
|
|
|
reciprocals of the data. It can be used for averaging ratios or
|
|
|
|
|
rates, for example speeds.
|
2016-08-08 23:49:01 -03:00
|
|
|
|
|
2020-12-23 23:52:09 -04:00
|
|
|
|
Suppose a car travels 40 km/hr for 5 km and then speeds-up to
|
|
|
|
|
60 km/hr for another 5 km. What is the average speed?
|
2016-08-08 23:49:01 -03:00
|
|
|
|
|
2020-12-23 23:52:09 -04:00
|
|
|
|
>>> harmonic_mean([40, 60])
|
|
|
|
|
48.0
|
2016-08-08 23:49:01 -03:00
|
|
|
|
|
2020-12-23 23:52:09 -04:00
|
|
|
|
Suppose a car travels 40 km/hr for 5 km, and when traffic clears,
|
|
|
|
|
speeds-up to 60 km/hr for the remaining 30 km of the journey. What
|
|
|
|
|
is the average speed?
|
|
|
|
|
|
|
|
|
|
>>> harmonic_mean([40, 60], weights=[5, 30])
|
|
|
|
|
56.0
|
2016-08-08 23:49:01 -03:00
|
|
|
|
|
|
|
|
|
If ``data`` is empty, or any element is less than zero,
|
|
|
|
|
``harmonic_mean`` will raise ``StatisticsError``.
|
|
|
|
|
"""
|
|
|
|
|
if iter(data) is data:
|
|
|
|
|
data = list(data)
|
|
|
|
|
errmsg = 'harmonic mean does not support negative values'
|
|
|
|
|
n = len(data)
|
|
|
|
|
if n < 1:
|
|
|
|
|
raise StatisticsError('harmonic_mean requires at least one data point')
|
2020-12-23 23:52:09 -04:00
|
|
|
|
elif n == 1 and weights is None:
|
2016-08-08 23:49:01 -03:00
|
|
|
|
x = data[0]
|
|
|
|
|
if isinstance(x, (numbers.Real, Decimal)):
|
|
|
|
|
if x < 0:
|
|
|
|
|
raise StatisticsError(errmsg)
|
|
|
|
|
return x
|
|
|
|
|
else:
|
|
|
|
|
raise TypeError('unsupported type')
|
2020-12-23 23:52:09 -04:00
|
|
|
|
if weights is None:
|
|
|
|
|
weights = repeat(1, n)
|
|
|
|
|
sum_weights = n
|
|
|
|
|
else:
|
|
|
|
|
if iter(weights) is weights:
|
|
|
|
|
weights = list(weights)
|
|
|
|
|
if len(weights) != n:
|
|
|
|
|
raise StatisticsError('Number of weights does not match data size')
|
|
|
|
|
_, sum_weights, _ = _sum(w for w in _fail_neg(weights, errmsg))
|
2016-08-08 23:49:01 -03:00
|
|
|
|
try:
|
2020-12-23 23:52:09 -04:00
|
|
|
|
data = _fail_neg(data, errmsg)
|
|
|
|
|
T, total, count = _sum(w / x if w else 0 for w, x in zip(weights, data))
|
2016-08-08 23:49:01 -03:00
|
|
|
|
except ZeroDivisionError:
|
|
|
|
|
return 0
|
2020-12-23 23:52:09 -04:00
|
|
|
|
if total <= 0:
|
|
|
|
|
raise StatisticsError('Weighted sum must be positive')
|
|
|
|
|
return _convert(sum_weights / total, T)
|
2016-08-08 23:49:01 -03:00
|
|
|
|
|
2013-10-19 15:50:09 -03:00
|
|
|
|
# FIXME: investigate ways to calculate medians without sorting? Quickselect?
|
|
|
|
|
def median(data):
|
|
|
|
|
"""Return the median (middle value) of numeric data.
|
|
|
|
|
|
|
|
|
|
When the number of data points is odd, return the middle data point.
|
|
|
|
|
When the number of data points is even, the median is interpolated by
|
|
|
|
|
taking the average of the two middle values:
|
|
|
|
|
|
|
|
|
|
>>> median([1, 3, 5])
|
|
|
|
|
3
|
|
|
|
|
>>> median([1, 3, 5, 7])
|
|
|
|
|
4.0
|
|
|
|
|
|
|
|
|
|
"""
|
|
|
|
|
data = sorted(data)
|
|
|
|
|
n = len(data)
|
|
|
|
|
if n == 0:
|
|
|
|
|
raise StatisticsError("no median for empty data")
|
2020-06-13 23:17:28 -03:00
|
|
|
|
if n % 2 == 1:
|
|
|
|
|
return data[n // 2]
|
2013-10-19 15:50:09 -03:00
|
|
|
|
else:
|
2020-06-13 23:17:28 -03:00
|
|
|
|
i = n // 2
|
|
|
|
|
return (data[i - 1] + data[i]) / 2
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def median_low(data):
|
|
|
|
|
"""Return the low median of numeric data.
|
|
|
|
|
|
|
|
|
|
When the number of data points is odd, the middle value is returned.
|
|
|
|
|
When it is even, the smaller of the two middle values is returned.
|
|
|
|
|
|
|
|
|
|
>>> median_low([1, 3, 5])
|
|
|
|
|
3
|
|
|
|
|
>>> median_low([1, 3, 5, 7])
|
|
|
|
|
3
|
|
|
|
|
|
|
|
|
|
"""
|
|
|
|
|
data = sorted(data)
|
|
|
|
|
n = len(data)
|
|
|
|
|
if n == 0:
|
|
|
|
|
raise StatisticsError("no median for empty data")
|
2020-06-13 23:17:28 -03:00
|
|
|
|
if n % 2 == 1:
|
|
|
|
|
return data[n // 2]
|
2013-10-19 15:50:09 -03:00
|
|
|
|
else:
|
2020-06-13 23:17:28 -03:00
|
|
|
|
return data[n // 2 - 1]
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def median_high(data):
|
|
|
|
|
"""Return the high median of data.
|
|
|
|
|
|
|
|
|
|
When the number of data points is odd, the middle value is returned.
|
|
|
|
|
When it is even, the larger of the two middle values is returned.
|
|
|
|
|
|
|
|
|
|
>>> median_high([1, 3, 5])
|
|
|
|
|
3
|
|
|
|
|
>>> median_high([1, 3, 5, 7])
|
|
|
|
|
5
|
|
|
|
|
|
|
|
|
|
"""
|
|
|
|
|
data = sorted(data)
|
|
|
|
|
n = len(data)
|
|
|
|
|
if n == 0:
|
|
|
|
|
raise StatisticsError("no median for empty data")
|
2020-06-13 23:17:28 -03:00
|
|
|
|
return data[n // 2]
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
|
|
|
|
|
2022-05-09 04:08:41 -03:00
|
|
|
|
def median_grouped(data, interval=1.0):
|
2022-05-05 05:01:07 -03:00
|
|
|
|
"""Estimates the median for numeric data binned around the midpoints
|
|
|
|
|
of consecutive, fixed-width intervals.
|
|
|
|
|
|
|
|
|
|
The *data* can be any iterable of numeric data with each value being
|
|
|
|
|
exactly the midpoint of a bin. At least one value must be present.
|
|
|
|
|
|
|
|
|
|
The *interval* is width of each bin.
|
|
|
|
|
|
|
|
|
|
For example, demographic information may have been summarized into
|
|
|
|
|
consecutive ten-year age groups with each group being represented
|
|
|
|
|
by the 5-year midpoints of the intervals:
|
|
|
|
|
|
|
|
|
|
>>> demographics = Counter({
|
|
|
|
|
... 25: 172, # 20 to 30 years old
|
|
|
|
|
... 35: 484, # 30 to 40 years old
|
|
|
|
|
... 45: 387, # 40 to 50 years old
|
|
|
|
|
... 55: 22, # 50 to 60 years old
|
|
|
|
|
... 65: 6, # 60 to 70 years old
|
|
|
|
|
... })
|
|
|
|
|
|
|
|
|
|
The 50th percentile (median) is the 536th person out of the 1071
|
|
|
|
|
member cohort. That person is in the 30 to 40 year old age group.
|
|
|
|
|
|
|
|
|
|
The regular median() function would assume that everyone in the
|
|
|
|
|
tricenarian age group was exactly 35 years old. A more tenable
|
|
|
|
|
assumption is that the 484 members of that age group are evenly
|
|
|
|
|
distributed between 30 and 40. For that, we use median_grouped().
|
|
|
|
|
|
|
|
|
|
>>> data = list(demographics.elements())
|
|
|
|
|
>>> median(data)
|
|
|
|
|
35
|
|
|
|
|
>>> round(median_grouped(data, interval=10), 1)
|
|
|
|
|
37.5
|
|
|
|
|
|
|
|
|
|
The caller is responsible for making sure the data points are separated
|
|
|
|
|
by exact multiples of *interval*. This is essential for getting a
|
|
|
|
|
correct result. The function does not check this precondition.
|
|
|
|
|
|
2022-05-09 04:08:41 -03:00
|
|
|
|
Inputs may be any numeric type that can be coerced to a float during
|
|
|
|
|
the interpolation step.
|
|
|
|
|
|
2013-10-19 15:50:09 -03:00
|
|
|
|
"""
|
|
|
|
|
data = sorted(data)
|
|
|
|
|
n = len(data)
|
2022-05-09 04:08:41 -03:00
|
|
|
|
if not n:
|
2013-10-19 15:50:09 -03:00
|
|
|
|
raise StatisticsError("no median for empty data")
|
2022-05-05 05:01:07 -03:00
|
|
|
|
|
2013-10-19 15:50:09 -03:00
|
|
|
|
# Find the value at the midpoint. Remember this corresponds to the
|
2022-05-05 05:01:07 -03:00
|
|
|
|
# midpoint of the class interval.
|
2020-06-13 23:17:28 -03:00
|
|
|
|
x = data[n // 2]
|
2022-05-05 05:01:07 -03:00
|
|
|
|
|
|
|
|
|
# Using O(log n) bisection, find where all the x values occur in the data.
|
|
|
|
|
# All x will lie within data[i:j].
|
|
|
|
|
i = bisect_left(data, x)
|
|
|
|
|
j = bisect_right(data, x, lo=i)
|
|
|
|
|
|
2022-05-09 04:08:41 -03:00
|
|
|
|
# Coerce to floats, raising a TypeError if not possible
|
|
|
|
|
try:
|
|
|
|
|
interval = float(interval)
|
|
|
|
|
x = float(x)
|
|
|
|
|
except ValueError:
|
|
|
|
|
raise TypeError(f'Value cannot be converted to a float')
|
|
|
|
|
|
2022-05-05 05:01:07 -03:00
|
|
|
|
# Interpolate the median using the formula found at:
|
|
|
|
|
# https://www.cuemath.com/data/median-of-grouped-data/
|
2022-05-09 04:08:41 -03:00
|
|
|
|
L = x - interval / 2.0 # Lower limit of the median interval
|
2022-05-05 05:01:07 -03:00
|
|
|
|
cf = i # Cumulative frequency of the preceding interval
|
|
|
|
|
f = j - i # Number of elements in the median internal
|
2020-06-13 23:17:28 -03:00
|
|
|
|
return L + interval * (n / 2 - cf) / f
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def mode(data):
|
|
|
|
|
"""Return the most common data point from discrete or nominal data.
|
|
|
|
|
|
|
|
|
|
``mode`` assumes discrete data, and returns a single value. This is the
|
|
|
|
|
standard treatment of the mode as commonly taught in schools:
|
|
|
|
|
|
2019-09-05 04:18:47 -03:00
|
|
|
|
>>> mode([1, 1, 2, 3, 3, 3, 3, 4])
|
|
|
|
|
3
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
|
|
|
|
This also works with nominal (non-numeric) data:
|
|
|
|
|
|
2019-09-05 04:18:47 -03:00
|
|
|
|
>>> mode(["red", "blue", "blue", "red", "green", "red", "red"])
|
|
|
|
|
'red'
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
2019-09-05 04:18:47 -03:00
|
|
|
|
If there are multiple modes with same frequency, return the first one
|
|
|
|
|
encountered:
|
2019-03-12 04:43:27 -03:00
|
|
|
|
|
|
|
|
|
>>> mode(['red', 'red', 'green', 'blue', 'blue'])
|
|
|
|
|
'red'
|
|
|
|
|
|
|
|
|
|
If *data* is empty, ``mode``, raises StatisticsError.
|
|
|
|
|
|
2013-10-19 15:50:09 -03:00
|
|
|
|
"""
|
2020-06-13 23:17:28 -03:00
|
|
|
|
pairs = Counter(iter(data)).most_common(1)
|
2019-03-12 04:43:27 -03:00
|
|
|
|
try:
|
2019-09-21 01:46:52 -03:00
|
|
|
|
return pairs[0][0]
|
2019-03-12 04:43:27 -03:00
|
|
|
|
except IndexError:
|
|
|
|
|
raise StatisticsError('no mode for empty data') from None
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def multimode(data):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""Return a list of the most frequently occurring values.
|
2019-03-12 04:43:27 -03:00
|
|
|
|
|
2019-07-21 16:13:07 -03:00
|
|
|
|
Will return more than one result if there are multiple modes
|
|
|
|
|
or an empty list if *data* is empty.
|
2019-03-12 04:43:27 -03:00
|
|
|
|
|
2019-07-21 16:13:07 -03:00
|
|
|
|
>>> multimode('aabbbbbbbbcc')
|
|
|
|
|
['b']
|
|
|
|
|
>>> multimode('aabbbbccddddeeffffgg')
|
|
|
|
|
['b', 'd', 'f']
|
|
|
|
|
>>> multimode('')
|
|
|
|
|
[]
|
2019-03-12 04:43:27 -03:00
|
|
|
|
"""
|
2021-11-20 12:04:37 -04:00
|
|
|
|
counts = Counter(iter(data))
|
|
|
|
|
if not counts:
|
|
|
|
|
return []
|
|
|
|
|
maxcount = max(counts.values())
|
|
|
|
|
return [value for value, count in counts.items() if count == maxcount]
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
2019-07-21 16:13:07 -03:00
|
|
|
|
|
2019-06-03 01:07:43 -03:00
|
|
|
|
# Notes on methods for computing quantiles
|
|
|
|
|
# ----------------------------------------
|
|
|
|
|
#
|
|
|
|
|
# There is no one perfect way to compute quantiles. Here we offer
|
|
|
|
|
# two methods that serve common needs. Most other packages
|
|
|
|
|
# surveyed offered at least one or both of these two, making them
|
|
|
|
|
# "standard" in the sense of "widely-adopted and reproducible".
|
|
|
|
|
# They are also easy to explain, easy to compute manually, and have
|
|
|
|
|
# straight-forward interpretations that aren't surprising.
|
|
|
|
|
|
|
|
|
|
# The default method is known as "R6", "PERCENTILE.EXC", or "expected
|
|
|
|
|
# value of rank order statistics". The alternative method is known as
|
|
|
|
|
# "R7", "PERCENTILE.INC", or "mode of rank order statistics".
|
|
|
|
|
|
|
|
|
|
# For sample data where there is a positive probability for values
|
|
|
|
|
# beyond the range of the data, the R6 exclusive method is a
|
|
|
|
|
# reasonable choice. Consider a random sample of nine values from a
|
2020-06-13 23:17:28 -03:00
|
|
|
|
# population with a uniform distribution from 0.0 to 1.0. The
|
2019-06-03 01:07:43 -03:00
|
|
|
|
# distribution of the third ranked sample point is described by
|
|
|
|
|
# betavariate(alpha=3, beta=7) which has mode=0.250, median=0.286, and
|
|
|
|
|
# mean=0.300. Only the latter (which corresponds with R6) gives the
|
|
|
|
|
# desired cut point with 30% of the population falling below that
|
|
|
|
|
# value, making it comparable to a result from an inv_cdf() function.
|
2019-09-21 01:46:52 -03:00
|
|
|
|
# The R6 exclusive method is also idempotent.
|
2019-06-03 01:07:43 -03:00
|
|
|
|
|
|
|
|
|
# For describing population data where the end points are known to
|
|
|
|
|
# be included in the data, the R7 inclusive method is a reasonable
|
|
|
|
|
# choice. Instead of the mean, it uses the mode of the beta
|
|
|
|
|
# distribution for the interior points. Per Hyndman & Fan, "One nice
|
|
|
|
|
# property is that the vertices of Q7(p) divide the range into n - 1
|
|
|
|
|
# intervals, and exactly 100p% of the intervals lie to the left of
|
|
|
|
|
# Q7(p) and 100(1 - p)% of the intervals lie to the right of Q7(p)."
|
|
|
|
|
|
2019-07-19 05:57:22 -03:00
|
|
|
|
# If needed, other methods could be added. However, for now, the
|
|
|
|
|
# position is that fewer options make for easier choices and that
|
|
|
|
|
# external packages can be used for anything more advanced.
|
2019-06-03 01:07:43 -03:00
|
|
|
|
|
2019-09-18 00:45:05 -03:00
|
|
|
|
def quantiles(data, *, n=4, method='exclusive'):
|
2019-09-05 04:18:47 -03:00
|
|
|
|
"""Divide *data* into *n* continuous intervals with equal probability.
|
2019-04-23 04:06:35 -03:00
|
|
|
|
|
|
|
|
|
Returns a list of (n - 1) cut points separating the intervals.
|
|
|
|
|
|
|
|
|
|
Set *n* to 4 for quartiles (the default). Set *n* to 10 for deciles.
|
|
|
|
|
Set *n* to 100 for percentiles which gives the 99 cuts points that
|
2019-09-05 04:18:47 -03:00
|
|
|
|
separate *data* in to 100 equal sized groups.
|
2019-04-23 04:06:35 -03:00
|
|
|
|
|
2019-09-08 20:57:58 -03:00
|
|
|
|
The *data* can be any iterable containing sample.
|
|
|
|
|
The cut points are linearly interpolated between data points.
|
2019-04-23 04:06:35 -03:00
|
|
|
|
|
2019-09-05 04:18:47 -03:00
|
|
|
|
If *method* is set to *inclusive*, *data* is treated as population
|
2019-04-23 04:06:35 -03:00
|
|
|
|
data. The minimum value is treated as the 0th percentile and the
|
|
|
|
|
maximum value is treated as the 100th percentile.
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""
|
2019-04-23 04:06:35 -03:00
|
|
|
|
if n < 1:
|
|
|
|
|
raise StatisticsError('n must be at least 1')
|
2019-09-05 04:18:47 -03:00
|
|
|
|
data = sorted(data)
|
2019-04-23 04:06:35 -03:00
|
|
|
|
ld = len(data)
|
|
|
|
|
if ld < 2:
|
2023-10-01 01:35:54 -03:00
|
|
|
|
if ld == 1:
|
|
|
|
|
return data * (n - 1)
|
|
|
|
|
raise StatisticsError('must have at least one data point')
|
2019-04-23 04:06:35 -03:00
|
|
|
|
if method == 'inclusive':
|
|
|
|
|
m = ld - 1
|
|
|
|
|
result = []
|
|
|
|
|
for i in range(1, n):
|
2020-06-13 23:17:28 -03:00
|
|
|
|
j, delta = divmod(i * m, n)
|
|
|
|
|
interpolated = (data[j] * (n - delta) + data[j + 1] * delta) / n
|
2019-04-23 04:06:35 -03:00
|
|
|
|
result.append(interpolated)
|
|
|
|
|
return result
|
|
|
|
|
if method == 'exclusive':
|
|
|
|
|
m = ld + 1
|
|
|
|
|
result = []
|
|
|
|
|
for i in range(1, n):
|
|
|
|
|
j = i * m // n # rescale i to m/n
|
|
|
|
|
j = 1 if j < 1 else ld-1 if j > ld-1 else j # clamp to 1 .. ld-1
|
|
|
|
|
delta = i*m - j*n # exact integer math
|
2020-06-13 23:17:28 -03:00
|
|
|
|
interpolated = (data[j - 1] * (n - delta) + data[j] * delta) / n
|
2019-04-23 04:06:35 -03:00
|
|
|
|
result.append(interpolated)
|
|
|
|
|
return result
|
|
|
|
|
raise ValueError(f'Unknown method: {method!r}')
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
2019-07-21 16:13:07 -03:00
|
|
|
|
|
2013-10-19 15:50:09 -03:00
|
|
|
|
# === Measures of spread ===
|
|
|
|
|
|
|
|
|
|
# See http://mathworld.wolfram.com/Variance.html
|
|
|
|
|
# http://mathworld.wolfram.com/SampleVariance.html
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def variance(data, xbar=None):
|
|
|
|
|
"""Return the sample variance of data.
|
|
|
|
|
|
|
|
|
|
data should be an iterable of Real-valued numbers, with at least two
|
|
|
|
|
values. The optional argument xbar, if given, should be the mean of
|
|
|
|
|
the data. If it is missing or None, the mean is automatically calculated.
|
|
|
|
|
|
|
|
|
|
Use this function when your data is a sample from a population. To
|
|
|
|
|
calculate the variance from the entire population, see ``pvariance``.
|
|
|
|
|
|
|
|
|
|
Examples:
|
|
|
|
|
|
|
|
|
|
>>> data = [2.75, 1.75, 1.25, 0.25, 0.5, 1.25, 3.5]
|
|
|
|
|
>>> variance(data)
|
|
|
|
|
1.3720238095238095
|
|
|
|
|
|
|
|
|
|
If you have already calculated the mean of your data, you can pass it as
|
|
|
|
|
the optional second argument ``xbar`` to avoid recalculating it:
|
|
|
|
|
|
|
|
|
|
>>> m = mean(data)
|
|
|
|
|
>>> variance(data, m)
|
|
|
|
|
1.3720238095238095
|
|
|
|
|
|
|
|
|
|
This function does not check that ``xbar`` is actually the mean of
|
|
|
|
|
``data``. Giving arbitrary values for ``xbar`` may lead to invalid or
|
|
|
|
|
impossible results.
|
|
|
|
|
|
|
|
|
|
Decimals and Fractions are supported:
|
|
|
|
|
|
|
|
|
|
>>> from decimal import Decimal as D
|
|
|
|
|
>>> variance([D("27.5"), D("30.25"), D("30.25"), D("34.5"), D("41.75")])
|
|
|
|
|
Decimal('31.01875')
|
|
|
|
|
|
|
|
|
|
>>> from fractions import Fraction as F
|
|
|
|
|
>>> variance([F(1, 6), F(1, 2), F(5, 3)])
|
|
|
|
|
Fraction(67, 108)
|
|
|
|
|
|
|
|
|
|
"""
|
2022-05-03 23:22:26 -03:00
|
|
|
|
T, ss, c, n = _ss(data, xbar)
|
2013-10-19 15:50:09 -03:00
|
|
|
|
if n < 2:
|
|
|
|
|
raise StatisticsError('variance requires at least two data points')
|
2020-06-13 23:17:28 -03:00
|
|
|
|
return _convert(ss / (n - 1), T)
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def pvariance(data, mu=None):
|
|
|
|
|
"""Return the population variance of ``data``.
|
|
|
|
|
|
2019-11-12 03:35:06 -04:00
|
|
|
|
data should be a sequence or iterable of Real-valued numbers, with at least one
|
2013-10-19 15:50:09 -03:00
|
|
|
|
value. The optional argument mu, if given, should be the mean of
|
|
|
|
|
the data. If it is missing or None, the mean is automatically calculated.
|
|
|
|
|
|
|
|
|
|
Use this function to calculate the variance from the entire population.
|
|
|
|
|
To estimate the variance from a sample, the ``variance`` function is
|
|
|
|
|
usually a better choice.
|
|
|
|
|
|
|
|
|
|
Examples:
|
|
|
|
|
|
|
|
|
|
>>> data = [0.0, 0.25, 0.25, 1.25, 1.5, 1.75, 2.75, 3.25]
|
|
|
|
|
>>> pvariance(data)
|
|
|
|
|
1.25
|
|
|
|
|
|
|
|
|
|
If you have already calculated the mean of the data, you can pass it as
|
|
|
|
|
the optional second argument to avoid recalculating it:
|
|
|
|
|
|
|
|
|
|
>>> mu = mean(data)
|
|
|
|
|
>>> pvariance(data, mu)
|
|
|
|
|
1.25
|
|
|
|
|
|
|
|
|
|
Decimals and Fractions are supported:
|
|
|
|
|
|
|
|
|
|
>>> from decimal import Decimal as D
|
|
|
|
|
>>> pvariance([D("27.5"), D("30.25"), D("30.25"), D("34.5"), D("41.75")])
|
|
|
|
|
Decimal('24.815')
|
|
|
|
|
|
|
|
|
|
>>> from fractions import Fraction as F
|
|
|
|
|
>>> pvariance([F(1, 4), F(5, 4), F(1, 2)])
|
|
|
|
|
Fraction(13, 72)
|
|
|
|
|
|
|
|
|
|
"""
|
2022-05-03 23:22:26 -03:00
|
|
|
|
T, ss, c, n = _ss(data, mu)
|
2013-10-19 15:50:09 -03:00
|
|
|
|
if n < 1:
|
|
|
|
|
raise StatisticsError('pvariance requires at least one data point')
|
2020-06-13 23:17:28 -03:00
|
|
|
|
return _convert(ss / n, T)
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def stdev(data, xbar=None):
|
|
|
|
|
"""Return the square root of the sample variance.
|
|
|
|
|
|
|
|
|
|
See ``variance`` for arguments and other details.
|
|
|
|
|
|
|
|
|
|
>>> stdev([1.5, 2.5, 2.5, 2.75, 3.25, 4.75])
|
|
|
|
|
1.0810874155219827
|
|
|
|
|
|
|
|
|
|
"""
|
2022-05-03 23:22:26 -03:00
|
|
|
|
T, ss, c, n = _ss(data, xbar)
|
2021-11-27 01:54:50 -04:00
|
|
|
|
if n < 2:
|
|
|
|
|
raise StatisticsError('stdev requires at least two data points')
|
|
|
|
|
mss = ss / (n - 1)
|
2021-11-30 21:25:57 -04:00
|
|
|
|
if issubclass(T, Decimal):
|
|
|
|
|
return _decimal_sqrt_of_frac(mss.numerator, mss.denominator)
|
2021-11-30 20:20:08 -04:00
|
|
|
|
return _float_sqrt_of_frac(mss.numerator, mss.denominator)
|
2013-10-19 15:50:09 -03:00
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def pstdev(data, mu=None):
|
|
|
|
|
"""Return the square root of the population variance.
|
|
|
|
|
|
|
|
|
|
See ``pvariance`` for arguments and other details.
|
|
|
|
|
|
|
|
|
|
>>> pstdev([1.5, 2.5, 2.5, 2.75, 3.25, 4.75])
|
|
|
|
|
0.986893273527251
|
|
|
|
|
|
|
|
|
|
"""
|
2022-05-03 23:22:26 -03:00
|
|
|
|
T, ss, c, n = _ss(data, mu)
|
2021-11-27 01:54:50 -04:00
|
|
|
|
if n < 1:
|
|
|
|
|
raise StatisticsError('pstdev requires at least one data point')
|
|
|
|
|
mss = ss / n
|
2021-11-30 20:20:08 -04:00
|
|
|
|
if issubclass(T, Decimal):
|
|
|
|
|
return _decimal_sqrt_of_frac(mss.numerator, mss.denominator)
|
|
|
|
|
return _float_sqrt_of_frac(mss.numerator, mss.denominator)
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
2019-07-21 16:13:07 -03:00
|
|
|
|
|
2022-05-03 23:22:26 -03:00
|
|
|
|
def _mean_stdev(data):
|
|
|
|
|
"""In one pass, compute the mean and sample standard deviation as floats."""
|
|
|
|
|
T, ss, xbar, n = _ss(data)
|
|
|
|
|
if n < 2:
|
|
|
|
|
raise StatisticsError('stdev requires at least two data points')
|
|
|
|
|
mss = ss / (n - 1)
|
2022-05-04 01:22:04 -03:00
|
|
|
|
try:
|
|
|
|
|
return float(xbar), _float_sqrt_of_frac(mss.numerator, mss.denominator)
|
|
|
|
|
except AttributeError:
|
|
|
|
|
# Handle Nans and Infs gracefully
|
|
|
|
|
return float(xbar), float(xbar) / float(ss)
|
2022-05-03 23:22:26 -03:00
|
|
|
|
|
2023-08-08 13:12:52 -03:00
|
|
|
|
def _sqrtprod(x: float, y: float) -> float:
|
2023-08-11 13:19:19 -03:00
|
|
|
|
"Return sqrt(x * y) computed with improved accuracy and without overflow/underflow."
|
2023-08-08 13:12:52 -03:00
|
|
|
|
h = sqrt(x * y)
|
2023-08-11 13:19:19 -03:00
|
|
|
|
if not isfinite(h):
|
|
|
|
|
if isinf(h) and not isinf(x) and not isinf(y):
|
|
|
|
|
# Finite inputs overflowed, so scale down, and recompute.
|
|
|
|
|
scale = 2.0 ** -512 # sqrt(1 / sys.float_info.max)
|
|
|
|
|
return _sqrtprod(scale * x, scale * y) / scale
|
|
|
|
|
return h
|
2023-08-09 04:44:43 -03:00
|
|
|
|
if not h:
|
2023-08-11 13:19:19 -03:00
|
|
|
|
if x and y:
|
|
|
|
|
# Non-zero inputs underflowed, so scale up, and recompute.
|
|
|
|
|
# Scale: 1 / sqrt(sys.float_info.min * sys.float_info.epsilon)
|
|
|
|
|
scale = 2.0 ** 537
|
|
|
|
|
return _sqrtprod(scale * x, scale * y) / scale
|
|
|
|
|
return h
|
|
|
|
|
# Improve accuracy with a differential correction.
|
|
|
|
|
# https://www.wolframalpha.com/input/?i=Maclaurin+series+sqrt%28h**2+%2B+x%29+at+x%3D0
|
|
|
|
|
d = sumprod((x, h), (y, -h))
|
|
|
|
|
return h + d / (2.0 * h)
|
2023-08-08 13:12:52 -03:00
|
|
|
|
|
2022-05-03 23:22:26 -03:00
|
|
|
|
|
2021-04-25 08:45:09 -03:00
|
|
|
|
# === Statistics for relations between two inputs ===
|
|
|
|
|
|
|
|
|
|
# See https://en.wikipedia.org/wiki/Covariance
|
|
|
|
|
# https://en.wikipedia.org/wiki/Pearson_correlation_coefficient
|
|
|
|
|
# https://en.wikipedia.org/wiki/Simple_linear_regression
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
def covariance(x, y, /):
|
|
|
|
|
"""Covariance
|
|
|
|
|
|
|
|
|
|
Return the sample covariance of two inputs *x* and *y*. Covariance
|
|
|
|
|
is a measure of the joint variability of two inputs.
|
|
|
|
|
|
|
|
|
|
>>> x = [1, 2, 3, 4, 5, 6, 7, 8, 9]
|
|
|
|
|
>>> y = [1, 2, 3, 1, 2, 3, 1, 2, 3]
|
|
|
|
|
>>> covariance(x, y)
|
|
|
|
|
0.75
|
|
|
|
|
>>> z = [9, 8, 7, 6, 5, 4, 3, 2, 1]
|
|
|
|
|
>>> covariance(x, z)
|
|
|
|
|
-7.5
|
|
|
|
|
>>> covariance(z, x)
|
|
|
|
|
-7.5
|
|
|
|
|
|
|
|
|
|
"""
|
|
|
|
|
n = len(x)
|
|
|
|
|
if len(y) != n:
|
|
|
|
|
raise StatisticsError('covariance requires that both inputs have same number of data points')
|
|
|
|
|
if n < 2:
|
|
|
|
|
raise StatisticsError('covariance requires at least two data points')
|
2021-05-15 15:00:51 -03:00
|
|
|
|
xbar = fsum(x) / n
|
|
|
|
|
ybar = fsum(y) / n
|
2023-03-13 22:06:43 -03:00
|
|
|
|
sxy = sumprod((xi - xbar for xi in x), (yi - ybar for yi in y))
|
2021-05-15 15:00:51 -03:00
|
|
|
|
return sxy / (n - 1)
|
2021-04-25 08:45:09 -03:00
|
|
|
|
|
|
|
|
|
|
2022-08-18 15:48:27 -03:00
|
|
|
|
def correlation(x, y, /, *, method='linear'):
|
2021-04-25 08:45:09 -03:00
|
|
|
|
"""Pearson's correlation coefficient
|
|
|
|
|
|
|
|
|
|
Return the Pearson's correlation coefficient for two inputs. Pearson's
|
2022-08-18 15:48:27 -03:00
|
|
|
|
correlation coefficient *r* takes values between -1 and +1. It measures
|
|
|
|
|
the strength and direction of a linear relationship.
|
2021-04-25 08:45:09 -03:00
|
|
|
|
|
|
|
|
|
>>> x = [1, 2, 3, 4, 5, 6, 7, 8, 9]
|
|
|
|
|
>>> y = [9, 8, 7, 6, 5, 4, 3, 2, 1]
|
|
|
|
|
>>> correlation(x, x)
|
|
|
|
|
1.0
|
|
|
|
|
>>> correlation(x, y)
|
|
|
|
|
-1.0
|
|
|
|
|
|
2022-08-18 15:48:27 -03:00
|
|
|
|
If *method* is "ranked", computes Spearman's rank correlation coefficient
|
|
|
|
|
for two inputs. The data is replaced by ranks. Ties are averaged
|
|
|
|
|
so that equal values receive the same rank. The resulting coefficient
|
|
|
|
|
measures the strength of a monotonic relationship.
|
|
|
|
|
|
|
|
|
|
Spearman's rank correlation coefficient is appropriate for ordinal
|
|
|
|
|
data or for continuous data that doesn't meet the linear proportion
|
|
|
|
|
requirement for Pearson's correlation coefficient.
|
2021-04-25 08:45:09 -03:00
|
|
|
|
"""
|
|
|
|
|
n = len(x)
|
|
|
|
|
if len(y) != n:
|
|
|
|
|
raise StatisticsError('correlation requires that both inputs have same number of data points')
|
|
|
|
|
if n < 2:
|
|
|
|
|
raise StatisticsError('correlation requires at least two data points')
|
2022-08-18 15:48:27 -03:00
|
|
|
|
if method not in {'linear', 'ranked'}:
|
|
|
|
|
raise ValueError(f'Unknown method: {method!r}')
|
|
|
|
|
if method == 'ranked':
|
2022-08-29 14:19:48 -03:00
|
|
|
|
start = (n - 1) / -2 # Center rankings around zero
|
|
|
|
|
x = _rank(x, start=start)
|
|
|
|
|
y = _rank(y, start=start)
|
2023-03-13 22:06:43 -03:00
|
|
|
|
else:
|
|
|
|
|
xbar = fsum(x) / n
|
|
|
|
|
ybar = fsum(y) / n
|
|
|
|
|
x = [xi - xbar for xi in x]
|
|
|
|
|
y = [yi - ybar for yi in y]
|
|
|
|
|
sxy = sumprod(x, y)
|
|
|
|
|
sxx = sumprod(x, x)
|
|
|
|
|
syy = sumprod(y, y)
|
2021-04-25 08:45:09 -03:00
|
|
|
|
try:
|
2023-08-08 13:12:52 -03:00
|
|
|
|
return sxy / _sqrtprod(sxx, syy)
|
2021-04-25 08:45:09 -03:00
|
|
|
|
except ZeroDivisionError:
|
|
|
|
|
raise StatisticsError('at least one of the inputs is constant')
|
|
|
|
|
|
|
|
|
|
|
2021-05-24 21:30:58 -03:00
|
|
|
|
LinearRegression = namedtuple('LinearRegression', ('slope', 'intercept'))
|
2021-04-25 08:45:09 -03:00
|
|
|
|
|
|
|
|
|
|
2021-11-21 10:39:26 -04:00
|
|
|
|
def linear_regression(x, y, /, *, proportional=False):
|
2021-05-25 03:04:04 -03:00
|
|
|
|
"""Slope and intercept for simple linear regression.
|
2021-04-25 08:45:09 -03:00
|
|
|
|
|
2021-05-25 03:04:04 -03:00
|
|
|
|
Return the slope and intercept of simple linear regression
|
2021-04-25 08:45:09 -03:00
|
|
|
|
parameters estimated using ordinary least squares. Simple linear
|
2021-05-25 03:04:04 -03:00
|
|
|
|
regression describes relationship between an independent variable
|
2021-11-21 10:39:26 -04:00
|
|
|
|
*x* and a dependent variable *y* in terms of a linear function:
|
2021-04-25 08:45:09 -03:00
|
|
|
|
|
2021-05-25 03:04:04 -03:00
|
|
|
|
y = slope * x + intercept + noise
|
2021-04-25 08:45:09 -03:00
|
|
|
|
|
2021-05-25 03:04:04 -03:00
|
|
|
|
where *slope* and *intercept* are the regression parameters that are
|
2021-05-16 23:21:14 -03:00
|
|
|
|
estimated, and noise represents the variability of the data that was
|
|
|
|
|
not explained by the linear regression (it is equal to the
|
2021-05-25 03:04:04 -03:00
|
|
|
|
difference between predicted and actual values of the dependent
|
2021-05-16 23:21:14 -03:00
|
|
|
|
variable).
|
2021-04-25 08:45:09 -03:00
|
|
|
|
|
|
|
|
|
The parameters are returned as a named tuple.
|
|
|
|
|
|
2021-05-24 21:30:58 -03:00
|
|
|
|
>>> x = [1, 2, 3, 4, 5]
|
2021-04-25 08:45:09 -03:00
|
|
|
|
>>> noise = NormalDist().samples(5, seed=42)
|
2021-05-25 03:04:04 -03:00
|
|
|
|
>>> y = [3 * x[i] + 2 + noise[i] for i in range(5)]
|
2021-05-24 21:30:58 -03:00
|
|
|
|
>>> linear_regression(x, y) #doctest: +ELLIPSIS
|
2023-08-27 10:59:40 -03:00
|
|
|
|
LinearRegression(slope=3.17495..., intercept=1.00925...)
|
2021-04-25 08:45:09 -03:00
|
|
|
|
|
2021-11-21 10:39:26 -04:00
|
|
|
|
If *proportional* is true, the independent variable *x* and the
|
|
|
|
|
dependent variable *y* are assumed to be directly proportional.
|
|
|
|
|
The data is fit to a line passing through the origin.
|
|
|
|
|
|
|
|
|
|
Since the *intercept* will always be 0.0, the underlying linear
|
|
|
|
|
function simplifies to:
|
|
|
|
|
|
|
|
|
|
y = slope * x + noise
|
|
|
|
|
|
|
|
|
|
>>> y = [3 * x[i] + noise[i] for i in range(5)]
|
|
|
|
|
>>> linear_regression(x, y, proportional=True) #doctest: +ELLIPSIS
|
2023-08-27 10:59:40 -03:00
|
|
|
|
LinearRegression(slope=2.90475..., intercept=0.0)
|
2021-11-21 10:39:26 -04:00
|
|
|
|
|
2021-04-25 08:45:09 -03:00
|
|
|
|
"""
|
2021-05-24 21:30:58 -03:00
|
|
|
|
n = len(x)
|
|
|
|
|
if len(y) != n:
|
2021-04-25 08:45:09 -03:00
|
|
|
|
raise StatisticsError('linear regression requires that both inputs have same number of data points')
|
|
|
|
|
if n < 2:
|
|
|
|
|
raise StatisticsError('linear regression requires at least two data points')
|
2023-03-13 22:06:43 -03:00
|
|
|
|
if not proportional:
|
2021-11-21 10:39:26 -04:00
|
|
|
|
xbar = fsum(x) / n
|
|
|
|
|
ybar = fsum(y) / n
|
2023-03-13 22:06:43 -03:00
|
|
|
|
x = [xi - xbar for xi in x] # List because used three times below
|
|
|
|
|
y = (yi - ybar for yi in y) # Generator because only used once below
|
|
|
|
|
sxy = sumprod(x, y) + 0.0 # Add zero to coerce result to a float
|
|
|
|
|
sxx = sumprod(x, x)
|
2021-04-25 08:45:09 -03:00
|
|
|
|
try:
|
2021-06-04 20:28:31 -03:00
|
|
|
|
slope = sxy / sxx # equivalent to: covariance(x, y) / variance(x)
|
2021-04-25 08:45:09 -03:00
|
|
|
|
except ZeroDivisionError:
|
2021-05-24 21:30:58 -03:00
|
|
|
|
raise StatisticsError('x is constant')
|
2021-11-21 10:39:26 -04:00
|
|
|
|
intercept = 0.0 if proportional else ybar - slope * xbar
|
2021-05-24 21:30:58 -03:00
|
|
|
|
return LinearRegression(slope=slope, intercept=intercept)
|
2021-04-25 08:45:09 -03:00
|
|
|
|
|
|
|
|
|
|
2019-02-23 18:44:07 -04:00
|
|
|
|
## Normal Distribution #####################################################
|
|
|
|
|
|
2019-08-23 19:20:30 -03:00
|
|
|
|
|
|
|
|
|
def _normal_dist_inv_cdf(p, mu, sigma):
|
|
|
|
|
# There is no closed-form solution to the inverse CDF for the normal
|
|
|
|
|
# distribution, so we use a rational approximation instead:
|
|
|
|
|
# Wichura, M.J. (1988). "Algorithm AS241: The Percentage Points of the
|
|
|
|
|
# Normal Distribution". Applied Statistics. Blackwell Publishing. 37
|
|
|
|
|
# (3): 477–484. doi:10.2307/2347330. JSTOR 2347330.
|
|
|
|
|
q = p - 0.5
|
|
|
|
|
if fabs(q) <= 0.425:
|
|
|
|
|
r = 0.180625 - q * q
|
|
|
|
|
# Hash sum: 55.88319_28806_14901_4439
|
|
|
|
|
num = (((((((2.50908_09287_30122_6727e+3 * r +
|
|
|
|
|
3.34305_75583_58812_8105e+4) * r +
|
|
|
|
|
6.72657_70927_00870_0853e+4) * r +
|
|
|
|
|
4.59219_53931_54987_1457e+4) * r +
|
|
|
|
|
1.37316_93765_50946_1125e+4) * r +
|
|
|
|
|
1.97159_09503_06551_4427e+3) * r +
|
|
|
|
|
1.33141_66789_17843_7745e+2) * r +
|
|
|
|
|
3.38713_28727_96366_6080e+0) * q
|
|
|
|
|
den = (((((((5.22649_52788_52854_5610e+3 * r +
|
|
|
|
|
2.87290_85735_72194_2674e+4) * r +
|
|
|
|
|
3.93078_95800_09271_0610e+4) * r +
|
|
|
|
|
2.12137_94301_58659_5867e+4) * r +
|
|
|
|
|
5.39419_60214_24751_1077e+3) * r +
|
|
|
|
|
6.87187_00749_20579_0830e+2) * r +
|
|
|
|
|
4.23133_30701_60091_1252e+1) * r +
|
|
|
|
|
1.0)
|
|
|
|
|
x = num / den
|
|
|
|
|
return mu + (x * sigma)
|
|
|
|
|
r = p if q <= 0.0 else 1.0 - p
|
|
|
|
|
r = sqrt(-log(r))
|
|
|
|
|
if r <= 5.0:
|
|
|
|
|
r = r - 1.6
|
|
|
|
|
# Hash sum: 49.33206_50330_16102_89036
|
|
|
|
|
num = (((((((7.74545_01427_83414_07640e-4 * r +
|
|
|
|
|
2.27238_44989_26918_45833e-2) * r +
|
|
|
|
|
2.41780_72517_74506_11770e-1) * r +
|
|
|
|
|
1.27045_82524_52368_38258e+0) * r +
|
|
|
|
|
3.64784_83247_63204_60504e+0) * r +
|
|
|
|
|
5.76949_72214_60691_40550e+0) * r +
|
|
|
|
|
4.63033_78461_56545_29590e+0) * r +
|
|
|
|
|
1.42343_71107_49683_57734e+0)
|
|
|
|
|
den = (((((((1.05075_00716_44416_84324e-9 * r +
|
|
|
|
|
5.47593_80849_95344_94600e-4) * r +
|
|
|
|
|
1.51986_66563_61645_71966e-2) * r +
|
|
|
|
|
1.48103_97642_74800_74590e-1) * r +
|
|
|
|
|
6.89767_33498_51000_04550e-1) * r +
|
|
|
|
|
1.67638_48301_83803_84940e+0) * r +
|
|
|
|
|
2.05319_16266_37758_82187e+0) * r +
|
|
|
|
|
1.0)
|
|
|
|
|
else:
|
|
|
|
|
r = r - 5.0
|
|
|
|
|
# Hash sum: 47.52583_31754_92896_71629
|
|
|
|
|
num = (((((((2.01033_43992_92288_13265e-7 * r +
|
|
|
|
|
2.71155_55687_43487_57815e-5) * r +
|
|
|
|
|
1.24266_09473_88078_43860e-3) * r +
|
|
|
|
|
2.65321_89526_57612_30930e-2) * r +
|
|
|
|
|
2.96560_57182_85048_91230e-1) * r +
|
|
|
|
|
1.78482_65399_17291_33580e+0) * r +
|
|
|
|
|
5.46378_49111_64114_36990e+0) * r +
|
|
|
|
|
6.65790_46435_01103_77720e+0)
|
|
|
|
|
den = (((((((2.04426_31033_89939_78564e-15 * r +
|
|
|
|
|
1.42151_17583_16445_88870e-7) * r +
|
|
|
|
|
1.84631_83175_10054_68180e-5) * r +
|
|
|
|
|
7.86869_13114_56132_59100e-4) * r +
|
|
|
|
|
1.48753_61290_85061_48525e-2) * r +
|
|
|
|
|
1.36929_88092_27358_05310e-1) * r +
|
|
|
|
|
5.99832_20655_58879_37690e-1) * r +
|
|
|
|
|
1.0)
|
|
|
|
|
x = num / den
|
|
|
|
|
if q < 0.0:
|
|
|
|
|
x = -x
|
|
|
|
|
return mu + (x * sigma)
|
|
|
|
|
|
|
|
|
|
|
2020-05-02 23:30:24 -03:00
|
|
|
|
# If available, use C implementation
|
|
|
|
|
try:
|
|
|
|
|
from _statistics import _normal_dist_inv_cdf
|
|
|
|
|
except ImportError:
|
|
|
|
|
pass
|
|
|
|
|
|
|
|
|
|
|
2019-02-23 18:44:07 -04:00
|
|
|
|
class NormalDist:
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"Normal distribution of a random variable"
|
2019-02-23 18:44:07 -04:00
|
|
|
|
# https://en.wikipedia.org/wiki/Normal_distribution
|
|
|
|
|
# https://en.wikipedia.org/wiki/Variance#Properties
|
|
|
|
|
|
2019-07-21 16:13:07 -03:00
|
|
|
|
__slots__ = {
|
|
|
|
|
'_mu': 'Arithmetic mean of a normal distribution',
|
|
|
|
|
'_sigma': 'Standard deviation of a normal distribution',
|
|
|
|
|
}
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
|
|
|
|
def __init__(self, mu=0.0, sigma=1.0):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"NormalDist where mu is the mean and sigma is the standard deviation."
|
2019-02-23 18:44:07 -04:00
|
|
|
|
if sigma < 0.0:
|
|
|
|
|
raise StatisticsError('sigma must be non-negative')
|
2019-09-05 04:18:47 -03:00
|
|
|
|
self._mu = float(mu)
|
|
|
|
|
self._sigma = float(sigma)
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
|
|
|
|
@classmethod
|
|
|
|
|
def from_samples(cls, data):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"Make a normal distribution instance from sample data."
|
2022-05-03 23:22:26 -03:00
|
|
|
|
return cls(*_mean_stdev(data))
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
2019-04-23 05:46:18 -03:00
|
|
|
|
def samples(self, n, *, seed=None):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"Generate *n* samples for a given mean and standard deviation."
|
2023-08-27 10:59:40 -03:00
|
|
|
|
rnd = random.random if seed is None else random.Random(seed).random
|
|
|
|
|
inv_cdf = _normal_dist_inv_cdf
|
|
|
|
|
mu = self._mu
|
|
|
|
|
sigma = self._sigma
|
|
|
|
|
return [inv_cdf(rnd(), mu, sigma) for _ in repeat(None, n)]
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
|
|
|
|
def pdf(self, x):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"Probability density function. P(x <= X < x+dx) / dx"
|
2021-08-30 22:57:30 -03:00
|
|
|
|
variance = self._sigma * self._sigma
|
2019-02-23 18:44:07 -04:00
|
|
|
|
if not variance:
|
|
|
|
|
raise StatisticsError('pdf() not defined when sigma is zero')
|
2021-08-30 22:57:30 -03:00
|
|
|
|
diff = x - self._mu
|
|
|
|
|
return exp(diff * diff / (-2.0 * variance)) / sqrt(tau * variance)
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
|
|
|
|
def cdf(self, x):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"Cumulative distribution function. P(X <= x)"
|
2019-07-21 04:34:47 -03:00
|
|
|
|
if not self._sigma:
|
2019-02-23 18:44:07 -04:00
|
|
|
|
raise StatisticsError('cdf() not defined when sigma is zero')
|
2021-11-09 12:30:06 -04:00
|
|
|
|
return 0.5 * (1.0 + erf((x - self._mu) / (self._sigma * _SQRT2)))
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
2019-03-19 00:17:14 -03:00
|
|
|
|
def inv_cdf(self, p):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""Inverse cumulative distribution function. x : P(X <= x) = p
|
2019-03-19 00:17:14 -03:00
|
|
|
|
|
2019-07-21 16:13:07 -03:00
|
|
|
|
Finds the value of the random variable such that the probability of
|
|
|
|
|
the variable being less than or equal to that value equals the given
|
|
|
|
|
probability.
|
2019-03-19 00:17:14 -03:00
|
|
|
|
|
2019-07-21 16:13:07 -03:00
|
|
|
|
This function is also called the percent point function or quantile
|
|
|
|
|
function.
|
|
|
|
|
"""
|
|
|
|
|
if p <= 0.0 or p >= 1.0:
|
2019-03-19 00:17:14 -03:00
|
|
|
|
raise StatisticsError('p must be in the range 0.0 < p < 1.0')
|
2019-08-23 19:20:30 -03:00
|
|
|
|
return _normal_dist_inv_cdf(p, self._mu, self._sigma)
|
2019-03-19 00:17:14 -03:00
|
|
|
|
|
2019-09-08 20:57:58 -03:00
|
|
|
|
def quantiles(self, n=4):
|
|
|
|
|
"""Divide into *n* continuous intervals with equal probability.
|
|
|
|
|
|
|
|
|
|
Returns a list of (n - 1) cut points separating the intervals.
|
|
|
|
|
|
|
|
|
|
Set *n* to 4 for quartiles (the default). Set *n* to 10 for deciles.
|
|
|
|
|
Set *n* to 100 for percentiles which gives the 99 cuts points that
|
|
|
|
|
separate the normal distribution in to 100 equal sized groups.
|
|
|
|
|
"""
|
|
|
|
|
return [self.inv_cdf(i / n) for i in range(1, n)]
|
|
|
|
|
|
2019-03-07 02:59:40 -04:00
|
|
|
|
def overlap(self, other):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""Compute the overlapping coefficient (OVL) between two normal distributions.
|
2019-03-07 02:59:40 -04:00
|
|
|
|
|
|
|
|
|
Measures the agreement between two normal probability distributions.
|
|
|
|
|
Returns a value between 0.0 and 1.0 giving the overlapping area in
|
|
|
|
|
the two underlying probability density functions.
|
|
|
|
|
|
|
|
|
|
>>> N1 = NormalDist(2.4, 1.6)
|
|
|
|
|
>>> N2 = NormalDist(3.2, 2.0)
|
|
|
|
|
>>> N1.overlap(N2)
|
|
|
|
|
0.8035050657330205
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""
|
2019-03-07 02:59:40 -04:00
|
|
|
|
# See: "The overlapping coefficient as a measure of agreement between
|
|
|
|
|
# probability distributions and point estimation of the overlap of two
|
|
|
|
|
# normal densities" -- Henry F. Inman and Edwin L. Bradley Jr
|
|
|
|
|
# http://dx.doi.org/10.1080/03610928908830127
|
|
|
|
|
if not isinstance(other, NormalDist):
|
|
|
|
|
raise TypeError('Expected another NormalDist instance')
|
|
|
|
|
X, Y = self, other
|
2020-06-13 23:17:28 -03:00
|
|
|
|
if (Y._sigma, Y._mu) < (X._sigma, X._mu): # sort to assure commutativity
|
2019-03-07 02:59:40 -04:00
|
|
|
|
X, Y = Y, X
|
|
|
|
|
X_var, Y_var = X.variance, Y.variance
|
|
|
|
|
if not X_var or not Y_var:
|
|
|
|
|
raise StatisticsError('overlap() not defined when sigma is zero')
|
|
|
|
|
dv = Y_var - X_var
|
2019-07-21 04:34:47 -03:00
|
|
|
|
dm = fabs(Y._mu - X._mu)
|
2019-03-07 02:59:40 -04:00
|
|
|
|
if not dv:
|
2021-11-09 12:30:06 -04:00
|
|
|
|
return 1.0 - erf(dm / (2.0 * X._sigma * _SQRT2))
|
2019-07-21 04:34:47 -03:00
|
|
|
|
a = X._mu * Y_var - Y._mu * X_var
|
2021-08-30 22:57:30 -03:00
|
|
|
|
b = X._sigma * Y._sigma * sqrt(dm * dm + dv * log(Y_var / X_var))
|
2019-03-07 02:59:40 -04:00
|
|
|
|
x1 = (a + b) / dv
|
|
|
|
|
x2 = (a - b) / dv
|
|
|
|
|
return 1.0 - (fabs(Y.cdf(x1) - X.cdf(x1)) + fabs(Y.cdf(x2) - X.cdf(x2)))
|
|
|
|
|
|
2020-04-16 14:25:14 -03:00
|
|
|
|
def zscore(self, x):
|
|
|
|
|
"""Compute the Standard Score. (x - mean) / stdev
|
|
|
|
|
|
|
|
|
|
Describes *x* in terms of the number of standard deviations
|
|
|
|
|
above or below the mean of the normal distribution.
|
|
|
|
|
"""
|
|
|
|
|
# https://www.statisticshowto.com/probability-and-statistics/z-score/
|
|
|
|
|
if not self._sigma:
|
|
|
|
|
raise StatisticsError('zscore() not defined when sigma is zero')
|
|
|
|
|
return (x - self._mu) / self._sigma
|
|
|
|
|
|
2019-02-24 15:44:55 -04:00
|
|
|
|
@property
|
|
|
|
|
def mean(self):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"Arithmetic mean of the normal distribution."
|
2019-07-21 04:34:47 -03:00
|
|
|
|
return self._mu
|
2019-02-24 15:44:55 -04:00
|
|
|
|
|
2019-09-08 20:57:58 -03:00
|
|
|
|
@property
|
|
|
|
|
def median(self):
|
|
|
|
|
"Return the median of the normal distribution"
|
|
|
|
|
return self._mu
|
|
|
|
|
|
|
|
|
|
@property
|
|
|
|
|
def mode(self):
|
|
|
|
|
"""Return the mode of the normal distribution
|
|
|
|
|
|
|
|
|
|
The mode is the value x where which the probability density
|
|
|
|
|
function (pdf) takes its maximum value.
|
|
|
|
|
"""
|
|
|
|
|
return self._mu
|
|
|
|
|
|
2019-02-24 15:44:55 -04:00
|
|
|
|
@property
|
|
|
|
|
def stdev(self):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"Standard deviation of the normal distribution."
|
2019-07-21 04:34:47 -03:00
|
|
|
|
return self._sigma
|
2019-02-24 15:44:55 -04:00
|
|
|
|
|
2019-02-23 18:44:07 -04:00
|
|
|
|
@property
|
|
|
|
|
def variance(self):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"Square of the standard deviation."
|
2021-08-30 22:57:30 -03:00
|
|
|
|
return self._sigma * self._sigma
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
|
|
|
|
def __add__(x1, x2):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""Add a constant or another NormalDist instance.
|
2019-03-19 02:24:15 -03:00
|
|
|
|
|
|
|
|
|
If *other* is a constant, translate mu by the constant,
|
|
|
|
|
leaving sigma unchanged.
|
|
|
|
|
|
|
|
|
|
If *other* is a NormalDist, add both the means and the variances.
|
|
|
|
|
Mathematically, this works only if the two distributions are
|
|
|
|
|
independent or if they are jointly normally distributed.
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""
|
2019-02-23 18:44:07 -04:00
|
|
|
|
if isinstance(x2, NormalDist):
|
2019-07-21 04:34:47 -03:00
|
|
|
|
return NormalDist(x1._mu + x2._mu, hypot(x1._sigma, x2._sigma))
|
|
|
|
|
return NormalDist(x1._mu + x2, x1._sigma)
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
|
|
|
|
def __sub__(x1, x2):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""Subtract a constant or another NormalDist instance.
|
2019-03-19 02:24:15 -03:00
|
|
|
|
|
|
|
|
|
If *other* is a constant, translate by the constant mu,
|
|
|
|
|
leaving sigma unchanged.
|
|
|
|
|
|
|
|
|
|
If *other* is a NormalDist, subtract the means and add the variances.
|
|
|
|
|
Mathematically, this works only if the two distributions are
|
|
|
|
|
independent or if they are jointly normally distributed.
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""
|
2019-02-23 18:44:07 -04:00
|
|
|
|
if isinstance(x2, NormalDist):
|
2019-07-21 04:34:47 -03:00
|
|
|
|
return NormalDist(x1._mu - x2._mu, hypot(x1._sigma, x2._sigma))
|
|
|
|
|
return NormalDist(x1._mu - x2, x1._sigma)
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
|
|
|
|
def __mul__(x1, x2):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""Multiply both mu and sigma by a constant.
|
2019-03-19 02:24:15 -03:00
|
|
|
|
|
|
|
|
|
Used for rescaling, perhaps to change measurement units.
|
|
|
|
|
Sigma is scaled with the absolute value of the constant.
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""
|
2019-07-21 04:34:47 -03:00
|
|
|
|
return NormalDist(x1._mu * x2, x1._sigma * fabs(x2))
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
|
|
|
|
def __truediv__(x1, x2):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""Divide both mu and sigma by a constant.
|
2019-03-19 02:24:15 -03:00
|
|
|
|
|
|
|
|
|
Used for rescaling, perhaps to change measurement units.
|
|
|
|
|
Sigma is scaled with the absolute value of the constant.
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"""
|
2019-07-21 04:34:47 -03:00
|
|
|
|
return NormalDist(x1._mu / x2, x1._sigma / fabs(x2))
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
|
|
|
|
def __pos__(x1):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"Return a copy of the instance."
|
2019-07-21 04:34:47 -03:00
|
|
|
|
return NormalDist(x1._mu, x1._sigma)
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
|
|
|
|
def __neg__(x1):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"Negates mu while keeping sigma the same."
|
2019-07-21 04:34:47 -03:00
|
|
|
|
return NormalDist(-x1._mu, x1._sigma)
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
|
|
|
|
__radd__ = __add__
|
|
|
|
|
|
|
|
|
|
def __rsub__(x1, x2):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"Subtract a NormalDist from a constant or another NormalDist."
|
2019-02-23 18:44:07 -04:00
|
|
|
|
return -(x1 - x2)
|
|
|
|
|
|
|
|
|
|
__rmul__ = __mul__
|
|
|
|
|
|
|
|
|
|
def __eq__(x1, x2):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"Two NormalDist objects are equal if their mu and sigma are both equal."
|
2019-02-23 18:44:07 -04:00
|
|
|
|
if not isinstance(x2, NormalDist):
|
|
|
|
|
return NotImplemented
|
2019-10-18 18:20:35 -03:00
|
|
|
|
return x1._mu == x2._mu and x1._sigma == x2._sigma
|
2019-07-21 04:34:47 -03:00
|
|
|
|
|
|
|
|
|
def __hash__(self):
|
2019-07-21 16:13:07 -03:00
|
|
|
|
"NormalDist objects hash equal if their mu and sigma are both equal."
|
2019-07-21 04:34:47 -03:00
|
|
|
|
return hash((self._mu, self._sigma))
|
2019-02-23 18:44:07 -04:00
|
|
|
|
|
|
|
|
|
def __repr__(self):
|
2019-07-21 04:34:47 -03:00
|
|
|
|
return f'{type(self).__name__}(mu={self._mu!r}, sigma={self._sigma!r})'
|
2022-11-06 22:56:41 -04:00
|
|
|
|
|
|
|
|
|
def __getstate__(self):
|
|
|
|
|
return self._mu, self._sigma
|
|
|
|
|
|
|
|
|
|
def __setstate__(self, state):
|
|
|
|
|
self._mu, self._sigma = state
|