107 lines
3.1 KiB
Python
Executable File
107 lines
3.1 KiB
Python
Executable File
#! /usr/bin/env python
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# Calculate your unbirthday count (see Alice in Wonderland).
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# This is defined as the number of days from your birth until today
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# that weren't your birthday. (The day you were born is not counted).
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# Leap years make it interesting.
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import sys
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import time
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import calendar
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def main():
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if sys.argv[1:]:
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year = int(sys.argv[1])
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else:
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year = int(input('In which year were you born? '))
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if 0 <= year < 100:
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print("I'll assume that by", year, end=' ')
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year = year + 1900
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print('you mean', year, 'and not the early Christian era')
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elif not (1850 <= year <= time.localtime()[0]):
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print("It's hard to believe you were born in", year)
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return
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if sys.argv[2:]:
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month = int(sys.argv[2])
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else:
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month = int(input('And in which month? (1-12) '))
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if not (1 <= month <= 12):
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print('There is no month numbered', month)
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return
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if sys.argv[3:]:
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day = int(sys.argv[3])
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else:
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day = int(input('And on what day of that month? (1-31) '))
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if month == 2 and calendar.isleap(year):
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maxday = 29
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else:
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maxday = calendar.mdays[month]
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if not (1 <= day <= maxday):
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print('There are no', day, 'days in that month!')
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return
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bdaytuple = (year, month, day)
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bdaydate = mkdate(bdaytuple)
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print('You were born on', format(bdaytuple))
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todaytuple = time.localtime()[:3]
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todaydate = mkdate(todaytuple)
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print('Today is', format(todaytuple))
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if bdaytuple > todaytuple:
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print('You are a time traveler. Go back to the future!')
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return
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if bdaytuple == todaytuple:
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print('You were born today. Have a nice life!')
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return
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days = todaydate - bdaydate
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print('You have lived', days, 'days')
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age = 0
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for y in range(year, todaytuple[0] + 1):
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if bdaytuple < (y, month, day) <= todaytuple:
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age = age + 1
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print('You are', age, 'years old')
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if todaytuple[1:] == bdaytuple[1:]:
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print('Congratulations! Today is your', nth(age), 'birthday')
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print('Yesterday was your', end=' ')
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else:
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print('Today is your', end=' ')
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print(nth(days - age), 'unbirthday')
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def format(date):
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(year, month, day) = date
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return '%d %s %d' % (day, calendar.month_name[month], year)
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def nth(n):
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if n == 1: return '1st'
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if n == 2: return '2nd'
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if n == 3: return '3rd'
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return '%dth' % n
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def mkdate(date):
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# January 1st, in 0 A.D. is arbitrarily defined to be day 1,
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# even though that day never actually existed and the calendar
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# was different then...
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(year, month, day) = date
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days = year*365 # years, roughly
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days = days + (year+3)//4 # plus leap years, roughly
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days = days - (year+99)//100 # minus non-leap years every century
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days = days + (year+399)//400 # plus leap years every 4 centirues
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for i in range(1, month):
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if i == 2 and calendar.isleap(year):
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days = days + 29
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else:
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days = days + calendar.mdays[i]
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days = days + day
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return days
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if __name__ == "__main__":
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main()
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