3390 lines
99 KiB
C
3390 lines
99 KiB
C
/* Math module -- standard C math library functions, pi and e */
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/* Here are some comments from Tim Peters, extracted from the
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discussion attached to http://bugs.python.org/issue1640. They
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describe the general aims of the math module with respect to
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special values, IEEE-754 floating-point exceptions, and Python
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exceptions.
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These are the "spirit of 754" rules:
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1. If the mathematical result is a real number, but of magnitude too
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large to approximate by a machine float, overflow is signaled and the
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result is an infinity (with the appropriate sign).
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2. If the mathematical result is a real number, but of magnitude too
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small to approximate by a machine float, underflow is signaled and the
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result is a zero (with the appropriate sign).
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3. At a singularity (a value x such that the limit of f(y) as y
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approaches x exists and is an infinity), "divide by zero" is signaled
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and the result is an infinity (with the appropriate sign). This is
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complicated a little by that the left-side and right-side limits may
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not be the same; e.g., 1/x approaches +inf or -inf as x approaches 0
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from the positive or negative directions. In that specific case, the
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sign of the zero determines the result of 1/0.
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4. At a point where a function has no defined result in the extended
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reals (i.e., the reals plus an infinity or two), invalid operation is
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signaled and a NaN is returned.
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And these are what Python has historically /tried/ to do (but not
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always successfully, as platform libm behavior varies a lot):
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For #1, raise OverflowError.
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For #2, return a zero (with the appropriate sign if that happens by
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accident ;-)).
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For #3 and #4, raise ValueError. It may have made sense to raise
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Python's ZeroDivisionError in #3, but historically that's only been
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raised for division by zero and mod by zero.
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*/
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/*
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In general, on an IEEE-754 platform the aim is to follow the C99
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standard, including Annex 'F', whenever possible. Where the
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standard recommends raising the 'divide-by-zero' or 'invalid'
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floating-point exceptions, Python should raise a ValueError. Where
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the standard recommends raising 'overflow', Python should raise an
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OverflowError. In all other circumstances a value should be
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returned.
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*/
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#include "Python.h"
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#include "_math.h"
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#include "clinic/mathmodule.c.h"
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/*[clinic input]
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module math
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[clinic start generated code]*/
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/*[clinic end generated code: output=da39a3ee5e6b4b0d input=76bc7002685dd942]*/
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/*
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sin(pi*x), giving accurate results for all finite x (especially x
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integral or close to an integer). This is here for use in the
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reflection formula for the gamma function. It conforms to IEEE
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754-2008 for finite arguments, but not for infinities or nans.
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*/
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static const double pi = 3.141592653589793238462643383279502884197;
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static const double logpi = 1.144729885849400174143427351353058711647;
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#if !defined(HAVE_ERF) || !defined(HAVE_ERFC)
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static const double sqrtpi = 1.772453850905516027298167483341145182798;
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#endif /* !defined(HAVE_ERF) || !defined(HAVE_ERFC) */
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/* Version of PyFloat_AsDouble() with in-line fast paths
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for exact floats and integers. Gives a substantial
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speed improvement for extracting float arguments.
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*/
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#define ASSIGN_DOUBLE(target_var, obj, error_label) \
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if (PyFloat_CheckExact(obj)) { \
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target_var = PyFloat_AS_DOUBLE(obj); \
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} \
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else if (PyLong_CheckExact(obj)) { \
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target_var = PyLong_AsDouble(obj); \
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if (target_var == -1.0 && PyErr_Occurred()) { \
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goto error_label; \
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} \
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} \
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else { \
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target_var = PyFloat_AsDouble(obj); \
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if (target_var == -1.0 && PyErr_Occurred()) { \
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goto error_label; \
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} \
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}
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static double
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m_sinpi(double x)
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{
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double y, r;
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int n;
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/* this function should only ever be called for finite arguments */
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assert(Py_IS_FINITE(x));
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y = fmod(fabs(x), 2.0);
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n = (int)round(2.0*y);
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assert(0 <= n && n <= 4);
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switch (n) {
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case 0:
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r = sin(pi*y);
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break;
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case 1:
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r = cos(pi*(y-0.5));
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break;
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case 2:
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/* N.B. -sin(pi*(y-1.0)) is *not* equivalent: it would give
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-0.0 instead of 0.0 when y == 1.0. */
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r = sin(pi*(1.0-y));
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break;
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case 3:
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r = -cos(pi*(y-1.5));
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break;
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case 4:
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r = sin(pi*(y-2.0));
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break;
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default:
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Py_UNREACHABLE();
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}
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return copysign(1.0, x)*r;
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}
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/* Implementation of the real gamma function. In extensive but non-exhaustive
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random tests, this function proved accurate to within <= 10 ulps across the
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entire float domain. Note that accuracy may depend on the quality of the
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system math functions, the pow function in particular. Special cases
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follow C99 annex F. The parameters and method are tailored to platforms
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whose double format is the IEEE 754 binary64 format.
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Method: for x > 0.0 we use the Lanczos approximation with parameters N=13
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and g=6.024680040776729583740234375; these parameters are amongst those
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used by the Boost library. Following Boost (again), we re-express the
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Lanczos sum as a rational function, and compute it that way. The
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coefficients below were computed independently using MPFR, and have been
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double-checked against the coefficients in the Boost source code.
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For x < 0.0 we use the reflection formula.
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There's one minor tweak that deserves explanation: Lanczos' formula for
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Gamma(x) involves computing pow(x+g-0.5, x-0.5) / exp(x+g-0.5). For many x
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values, x+g-0.5 can be represented exactly. However, in cases where it
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can't be represented exactly the small error in x+g-0.5 can be magnified
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significantly by the pow and exp calls, especially for large x. A cheap
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correction is to multiply by (1 + e*g/(x+g-0.5)), where e is the error
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involved in the computation of x+g-0.5 (that is, e = computed value of
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x+g-0.5 - exact value of x+g-0.5). Here's the proof:
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Correction factor
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-----------------
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Write x+g-0.5 = y-e, where y is exactly representable as an IEEE 754
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double, and e is tiny. Then:
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pow(x+g-0.5,x-0.5)/exp(x+g-0.5) = pow(y-e, x-0.5)/exp(y-e)
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= pow(y, x-0.5)/exp(y) * C,
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where the correction_factor C is given by
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C = pow(1-e/y, x-0.5) * exp(e)
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Since e is tiny, pow(1-e/y, x-0.5) ~ 1-(x-0.5)*e/y, and exp(x) ~ 1+e, so:
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C ~ (1-(x-0.5)*e/y) * (1+e) ~ 1 + e*(y-(x-0.5))/y
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But y-(x-0.5) = g+e, and g+e ~ g. So we get C ~ 1 + e*g/y, and
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pow(x+g-0.5,x-0.5)/exp(x+g-0.5) ~ pow(y, x-0.5)/exp(y) * (1 + e*g/y),
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Note that for accuracy, when computing r*C it's better to do
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r + e*g/y*r;
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than
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r * (1 + e*g/y);
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since the addition in the latter throws away most of the bits of
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information in e*g/y.
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*/
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#define LANCZOS_N 13
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static const double lanczos_g = 6.024680040776729583740234375;
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static const double lanczos_g_minus_half = 5.524680040776729583740234375;
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static const double lanczos_num_coeffs[LANCZOS_N] = {
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23531376880.410759688572007674451636754734846804940,
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42919803642.649098768957899047001988850926355848959,
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35711959237.355668049440185451547166705960488635843,
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17921034426.037209699919755754458931112671403265390,
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6039542586.3520280050642916443072979210699388420708,
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1439720407.3117216736632230727949123939715485786772,
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248874557.86205415651146038641322942321632125127801,
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31426415.585400194380614231628318205362874684987640,
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2876370.6289353724412254090516208496135991145378768,
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186056.26539522349504029498971604569928220784236328,
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8071.6720023658162106380029022722506138218516325024,
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210.82427775157934587250973392071336271166969580291,
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2.5066282746310002701649081771338373386264310793408
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};
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/* denominator is x*(x+1)*...*(x+LANCZOS_N-2) */
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static const double lanczos_den_coeffs[LANCZOS_N] = {
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0.0, 39916800.0, 120543840.0, 150917976.0, 105258076.0, 45995730.0,
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13339535.0, 2637558.0, 357423.0, 32670.0, 1925.0, 66.0, 1.0};
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/* gamma values for small positive integers, 1 though NGAMMA_INTEGRAL */
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#define NGAMMA_INTEGRAL 23
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static const double gamma_integral[NGAMMA_INTEGRAL] = {
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1.0, 1.0, 2.0, 6.0, 24.0, 120.0, 720.0, 5040.0, 40320.0, 362880.0,
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3628800.0, 39916800.0, 479001600.0, 6227020800.0, 87178291200.0,
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1307674368000.0, 20922789888000.0, 355687428096000.0,
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6402373705728000.0, 121645100408832000.0, 2432902008176640000.0,
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51090942171709440000.0, 1124000727777607680000.0,
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};
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/* Lanczos' sum L_g(x), for positive x */
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static double
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lanczos_sum(double x)
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{
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double num = 0.0, den = 0.0;
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int i;
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assert(x > 0.0);
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/* evaluate the rational function lanczos_sum(x). For large
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x, the obvious algorithm risks overflow, so we instead
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rescale the denominator and numerator of the rational
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function by x**(1-LANCZOS_N) and treat this as a
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rational function in 1/x. This also reduces the error for
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larger x values. The choice of cutoff point (5.0 below) is
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somewhat arbitrary; in tests, smaller cutoff values than
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this resulted in lower accuracy. */
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if (x < 5.0) {
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for (i = LANCZOS_N; --i >= 0; ) {
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num = num * x + lanczos_num_coeffs[i];
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den = den * x + lanczos_den_coeffs[i];
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}
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}
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else {
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for (i = 0; i < LANCZOS_N; i++) {
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num = num / x + lanczos_num_coeffs[i];
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den = den / x + lanczos_den_coeffs[i];
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}
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}
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return num/den;
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}
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/* Constant for +infinity, generated in the same way as float('inf'). */
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static double
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m_inf(void)
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{
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#ifndef PY_NO_SHORT_FLOAT_REPR
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return _Py_dg_infinity(0);
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#else
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return Py_HUGE_VAL;
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#endif
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}
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/* Constant nan value, generated in the same way as float('nan'). */
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/* We don't currently assume that Py_NAN is defined everywhere. */
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#if !defined(PY_NO_SHORT_FLOAT_REPR) || defined(Py_NAN)
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static double
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m_nan(void)
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{
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#ifndef PY_NO_SHORT_FLOAT_REPR
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return _Py_dg_stdnan(0);
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#else
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return Py_NAN;
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#endif
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}
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#endif
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static double
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m_tgamma(double x)
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{
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double absx, r, y, z, sqrtpow;
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/* special cases */
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if (!Py_IS_FINITE(x)) {
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if (Py_IS_NAN(x) || x > 0.0)
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return x; /* tgamma(nan) = nan, tgamma(inf) = inf */
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else {
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errno = EDOM;
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return Py_NAN; /* tgamma(-inf) = nan, invalid */
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}
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}
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if (x == 0.0) {
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errno = EDOM;
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/* tgamma(+-0.0) = +-inf, divide-by-zero */
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return copysign(Py_HUGE_VAL, x);
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}
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/* integer arguments */
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if (x == floor(x)) {
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if (x < 0.0) {
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errno = EDOM; /* tgamma(n) = nan, invalid for */
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return Py_NAN; /* negative integers n */
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}
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if (x <= NGAMMA_INTEGRAL)
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return gamma_integral[(int)x - 1];
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}
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absx = fabs(x);
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/* tiny arguments: tgamma(x) ~ 1/x for x near 0 */
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if (absx < 1e-20) {
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r = 1.0/x;
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if (Py_IS_INFINITY(r))
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errno = ERANGE;
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return r;
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}
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/* large arguments: assuming IEEE 754 doubles, tgamma(x) overflows for
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x > 200, and underflows to +-0.0 for x < -200, not a negative
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integer. */
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if (absx > 200.0) {
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if (x < 0.0) {
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return 0.0/m_sinpi(x);
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}
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else {
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errno = ERANGE;
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return Py_HUGE_VAL;
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}
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}
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y = absx + lanczos_g_minus_half;
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/* compute error in sum */
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if (absx > lanczos_g_minus_half) {
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/* note: the correction can be foiled by an optimizing
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compiler that (incorrectly) thinks that an expression like
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a + b - a - b can be optimized to 0.0. This shouldn't
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happen in a standards-conforming compiler. */
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double q = y - absx;
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z = q - lanczos_g_minus_half;
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}
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else {
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double q = y - lanczos_g_minus_half;
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z = q - absx;
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}
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z = z * lanczos_g / y;
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if (x < 0.0) {
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r = -pi / m_sinpi(absx) / absx * exp(y) / lanczos_sum(absx);
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r -= z * r;
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if (absx < 140.0) {
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r /= pow(y, absx - 0.5);
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}
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else {
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sqrtpow = pow(y, absx / 2.0 - 0.25);
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r /= sqrtpow;
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r /= sqrtpow;
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}
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}
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else {
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r = lanczos_sum(absx) / exp(y);
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r += z * r;
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if (absx < 140.0) {
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r *= pow(y, absx - 0.5);
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}
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else {
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sqrtpow = pow(y, absx / 2.0 - 0.25);
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r *= sqrtpow;
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r *= sqrtpow;
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}
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}
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if (Py_IS_INFINITY(r))
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errno = ERANGE;
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return r;
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}
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/*
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lgamma: natural log of the absolute value of the Gamma function.
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For large arguments, Lanczos' formula works extremely well here.
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*/
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static double
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m_lgamma(double x)
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{
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double r;
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double absx;
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/* special cases */
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if (!Py_IS_FINITE(x)) {
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if (Py_IS_NAN(x))
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return x; /* lgamma(nan) = nan */
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else
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return Py_HUGE_VAL; /* lgamma(+-inf) = +inf */
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}
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|
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/* integer arguments */
|
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if (x == floor(x) && x <= 2.0) {
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if (x <= 0.0) {
|
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errno = EDOM; /* lgamma(n) = inf, divide-by-zero for */
|
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return Py_HUGE_VAL; /* integers n <= 0 */
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}
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else {
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return 0.0; /* lgamma(1) = lgamma(2) = 0.0 */
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}
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}
|
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|
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absx = fabs(x);
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/* tiny arguments: lgamma(x) ~ -log(fabs(x)) for small x */
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if (absx < 1e-20)
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return -log(absx);
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|
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/* Lanczos' formula. We could save a fraction of a ulp in accuracy by
|
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having a second set of numerator coefficients for lanczos_sum that
|
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absorbed the exp(-lanczos_g) term, and throwing out the lanczos_g
|
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subtraction below; it's probably not worth it. */
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r = log(lanczos_sum(absx)) - lanczos_g;
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r += (absx - 0.5) * (log(absx + lanczos_g - 0.5) - 1);
|
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if (x < 0.0)
|
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/* Use reflection formula to get value for negative x. */
|
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r = logpi - log(fabs(m_sinpi(absx))) - log(absx) - r;
|
|
if (Py_IS_INFINITY(r))
|
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errno = ERANGE;
|
|
return r;
|
|
}
|
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|
|
#if !defined(HAVE_ERF) || !defined(HAVE_ERFC)
|
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|
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/*
|
|
Implementations of the error function erf(x) and the complementary error
|
|
function erfc(x).
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|
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Method: we use a series approximation for erf for small x, and a continued
|
|
fraction approximation for erfc(x) for larger x;
|
|
combined with the relations erf(-x) = -erf(x) and erfc(x) = 1.0 - erf(x),
|
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this gives us erf(x) and erfc(x) for all x.
|
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|
|
The series expansion used is:
|
|
|
|
erf(x) = x*exp(-x*x)/sqrt(pi) * [
|
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2/1 + 4/3 x**2 + 8/15 x**4 + 16/105 x**6 + ...]
|
|
|
|
The coefficient of x**(2k-2) here is 4**k*factorial(k)/factorial(2*k).
|
|
This series converges well for smallish x, but slowly for larger x.
|
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|
|
The continued fraction expansion used is:
|
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|
|
erfc(x) = x*exp(-x*x)/sqrt(pi) * [1/(0.5 + x**2 -) 0.5/(2.5 + x**2 - )
|
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3.0/(4.5 + x**2 - ) 7.5/(6.5 + x**2 - ) ...]
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|
|
after the first term, the general term has the form:
|
|
|
|
k*(k-0.5)/(2*k+0.5 + x**2 - ...).
|
|
|
|
This expansion converges fast for larger x, but convergence becomes
|
|
infinitely slow as x approaches 0.0. The (somewhat naive) continued
|
|
fraction evaluation algorithm used below also risks overflow for large x;
|
|
but for large x, erfc(x) == 0.0 to within machine precision. (For
|
|
example, erfc(30.0) is approximately 2.56e-393).
|
|
|
|
Parameters: use series expansion for abs(x) < ERF_SERIES_CUTOFF and
|
|
continued fraction expansion for ERF_SERIES_CUTOFF <= abs(x) <
|
|
ERFC_CONTFRAC_CUTOFF. ERFC_SERIES_TERMS and ERFC_CONTFRAC_TERMS are the
|
|
numbers of terms to use for the relevant expansions. */
|
|
|
|
#define ERF_SERIES_CUTOFF 1.5
|
|
#define ERF_SERIES_TERMS 25
|
|
#define ERFC_CONTFRAC_CUTOFF 30.0
|
|
#define ERFC_CONTFRAC_TERMS 50
|
|
|
|
/*
|
|
Error function, via power series.
|
|
|
|
Given a finite float x, return an approximation to erf(x).
|
|
Converges reasonably fast for small x.
|
|
*/
|
|
|
|
static double
|
|
m_erf_series(double x)
|
|
{
|
|
double x2, acc, fk, result;
|
|
int i, saved_errno;
|
|
|
|
x2 = x * x;
|
|
acc = 0.0;
|
|
fk = (double)ERF_SERIES_TERMS + 0.5;
|
|
for (i = 0; i < ERF_SERIES_TERMS; i++) {
|
|
acc = 2.0 + x2 * acc / fk;
|
|
fk -= 1.0;
|
|
}
|
|
/* Make sure the exp call doesn't affect errno;
|
|
see m_erfc_contfrac for more. */
|
|
saved_errno = errno;
|
|
result = acc * x * exp(-x2) / sqrtpi;
|
|
errno = saved_errno;
|
|
return result;
|
|
}
|
|
|
|
/*
|
|
Complementary error function, via continued fraction expansion.
|
|
|
|
Given a positive float x, return an approximation to erfc(x). Converges
|
|
reasonably fast for x large (say, x > 2.0), and should be safe from
|
|
overflow if x and nterms are not too large. On an IEEE 754 machine, with x
|
|
<= 30.0, we're safe up to nterms = 100. For x >= 30.0, erfc(x) is smaller
|
|
than the smallest representable nonzero float. */
|
|
|
|
static double
|
|
m_erfc_contfrac(double x)
|
|
{
|
|
double x2, a, da, p, p_last, q, q_last, b, result;
|
|
int i, saved_errno;
|
|
|
|
if (x >= ERFC_CONTFRAC_CUTOFF)
|
|
return 0.0;
|
|
|
|
x2 = x*x;
|
|
a = 0.0;
|
|
da = 0.5;
|
|
p = 1.0; p_last = 0.0;
|
|
q = da + x2; q_last = 1.0;
|
|
for (i = 0; i < ERFC_CONTFRAC_TERMS; i++) {
|
|
double temp;
|
|
a += da;
|
|
da += 2.0;
|
|
b = da + x2;
|
|
temp = p; p = b*p - a*p_last; p_last = temp;
|
|
temp = q; q = b*q - a*q_last; q_last = temp;
|
|
}
|
|
/* Issue #8986: On some platforms, exp sets errno on underflow to zero;
|
|
save the current errno value so that we can restore it later. */
|
|
saved_errno = errno;
|
|
result = p / q * x * exp(-x2) / sqrtpi;
|
|
errno = saved_errno;
|
|
return result;
|
|
}
|
|
|
|
#endif /* !defined(HAVE_ERF) || !defined(HAVE_ERFC) */
|
|
|
|
/* Error function erf(x), for general x */
|
|
|
|
static double
|
|
m_erf(double x)
|
|
{
|
|
#ifdef HAVE_ERF
|
|
return erf(x);
|
|
#else
|
|
double absx, cf;
|
|
|
|
if (Py_IS_NAN(x))
|
|
return x;
|
|
absx = fabs(x);
|
|
if (absx < ERF_SERIES_CUTOFF)
|
|
return m_erf_series(x);
|
|
else {
|
|
cf = m_erfc_contfrac(absx);
|
|
return x > 0.0 ? 1.0 - cf : cf - 1.0;
|
|
}
|
|
#endif
|
|
}
|
|
|
|
/* Complementary error function erfc(x), for general x. */
|
|
|
|
static double
|
|
m_erfc(double x)
|
|
{
|
|
#ifdef HAVE_ERFC
|
|
return erfc(x);
|
|
#else
|
|
double absx, cf;
|
|
|
|
if (Py_IS_NAN(x))
|
|
return x;
|
|
absx = fabs(x);
|
|
if (absx < ERF_SERIES_CUTOFF)
|
|
return 1.0 - m_erf_series(x);
|
|
else {
|
|
cf = m_erfc_contfrac(absx);
|
|
return x > 0.0 ? cf : 2.0 - cf;
|
|
}
|
|
#endif
|
|
}
|
|
|
|
/*
|
|
wrapper for atan2 that deals directly with special cases before
|
|
delegating to the platform libm for the remaining cases. This
|
|
is necessary to get consistent behaviour across platforms.
|
|
Windows, FreeBSD and alpha Tru64 are amongst platforms that don't
|
|
always follow C99.
|
|
*/
|
|
|
|
static double
|
|
m_atan2(double y, double x)
|
|
{
|
|
if (Py_IS_NAN(x) || Py_IS_NAN(y))
|
|
return Py_NAN;
|
|
if (Py_IS_INFINITY(y)) {
|
|
if (Py_IS_INFINITY(x)) {
|
|
if (copysign(1., x) == 1.)
|
|
/* atan2(+-inf, +inf) == +-pi/4 */
|
|
return copysign(0.25*Py_MATH_PI, y);
|
|
else
|
|
/* atan2(+-inf, -inf) == +-pi*3/4 */
|
|
return copysign(0.75*Py_MATH_PI, y);
|
|
}
|
|
/* atan2(+-inf, x) == +-pi/2 for finite x */
|
|
return copysign(0.5*Py_MATH_PI, y);
|
|
}
|
|
if (Py_IS_INFINITY(x) || y == 0.) {
|
|
if (copysign(1., x) == 1.)
|
|
/* atan2(+-y, +inf) = atan2(+-0, +x) = +-0. */
|
|
return copysign(0., y);
|
|
else
|
|
/* atan2(+-y, -inf) = atan2(+-0., -x) = +-pi. */
|
|
return copysign(Py_MATH_PI, y);
|
|
}
|
|
return atan2(y, x);
|
|
}
|
|
|
|
|
|
/* IEEE 754-style remainder operation: x - n*y where n*y is the nearest
|
|
multiple of y to x, taking n even in the case of a tie. Assuming an IEEE 754
|
|
binary floating-point format, the result is always exact. */
|
|
|
|
static double
|
|
m_remainder(double x, double y)
|
|
{
|
|
/* Deal with most common case first. */
|
|
if (Py_IS_FINITE(x) && Py_IS_FINITE(y)) {
|
|
double absx, absy, c, m, r;
|
|
|
|
if (y == 0.0) {
|
|
return Py_NAN;
|
|
}
|
|
|
|
absx = fabs(x);
|
|
absy = fabs(y);
|
|
m = fmod(absx, absy);
|
|
|
|
/*
|
|
Warning: some subtlety here. What we *want* to know at this point is
|
|
whether the remainder m is less than, equal to, or greater than half
|
|
of absy. However, we can't do that comparison directly because we
|
|
can't be sure that 0.5*absy is representable (the multiplication
|
|
might incur precision loss due to underflow). So instead we compare
|
|
m with the complement c = absy - m: m < 0.5*absy if and only if m <
|
|
c, and so on. The catch is that absy - m might also not be
|
|
representable, but it turns out that it doesn't matter:
|
|
|
|
- if m > 0.5*absy then absy - m is exactly representable, by
|
|
Sterbenz's lemma, so m > c
|
|
- if m == 0.5*absy then again absy - m is exactly representable
|
|
and m == c
|
|
- if m < 0.5*absy then either (i) 0.5*absy is exactly representable,
|
|
in which case 0.5*absy < absy - m, so 0.5*absy <= c and hence m <
|
|
c, or (ii) absy is tiny, either subnormal or in the lowest normal
|
|
binade. Then absy - m is exactly representable and again m < c.
|
|
*/
|
|
|
|
c = absy - m;
|
|
if (m < c) {
|
|
r = m;
|
|
}
|
|
else if (m > c) {
|
|
r = -c;
|
|
}
|
|
else {
|
|
/*
|
|
Here absx is exactly halfway between two multiples of absy,
|
|
and we need to choose the even multiple. x now has the form
|
|
|
|
absx = n * absy + m
|
|
|
|
for some integer n (recalling that m = 0.5*absy at this point).
|
|
If n is even we want to return m; if n is odd, we need to
|
|
return -m.
|
|
|
|
So
|
|
|
|
0.5 * (absx - m) = (n/2) * absy
|
|
|
|
and now reducing modulo absy gives us:
|
|
|
|
| m, if n is odd
|
|
fmod(0.5 * (absx - m), absy) = |
|
|
| 0, if n is even
|
|
|
|
Now m - 2.0 * fmod(...) gives the desired result: m
|
|
if n is even, -m if m is odd.
|
|
|
|
Note that all steps in fmod(0.5 * (absx - m), absy)
|
|
will be computed exactly, with no rounding error
|
|
introduced.
|
|
*/
|
|
assert(m == c);
|
|
r = m - 2.0 * fmod(0.5 * (absx - m), absy);
|
|
}
|
|
return copysign(1.0, x) * r;
|
|
}
|
|
|
|
/* Special values. */
|
|
if (Py_IS_NAN(x)) {
|
|
return x;
|
|
}
|
|
if (Py_IS_NAN(y)) {
|
|
return y;
|
|
}
|
|
if (Py_IS_INFINITY(x)) {
|
|
return Py_NAN;
|
|
}
|
|
assert(Py_IS_INFINITY(y));
|
|
return x;
|
|
}
|
|
|
|
|
|
/*
|
|
Various platforms (Solaris, OpenBSD) do nonstandard things for log(0),
|
|
log(-ve), log(NaN). Here are wrappers for log and log10 that deal with
|
|
special values directly, passing positive non-special values through to
|
|
the system log/log10.
|
|
*/
|
|
|
|
static double
|
|
m_log(double x)
|
|
{
|
|
if (Py_IS_FINITE(x)) {
|
|
if (x > 0.0)
|
|
return log(x);
|
|
errno = EDOM;
|
|
if (x == 0.0)
|
|
return -Py_HUGE_VAL; /* log(0) = -inf */
|
|
else
|
|
return Py_NAN; /* log(-ve) = nan */
|
|
}
|
|
else if (Py_IS_NAN(x))
|
|
return x; /* log(nan) = nan */
|
|
else if (x > 0.0)
|
|
return x; /* log(inf) = inf */
|
|
else {
|
|
errno = EDOM;
|
|
return Py_NAN; /* log(-inf) = nan */
|
|
}
|
|
}
|
|
|
|
/*
|
|
log2: log to base 2.
|
|
|
|
Uses an algorithm that should:
|
|
|
|
(a) produce exact results for powers of 2, and
|
|
(b) give a monotonic log2 (for positive finite floats),
|
|
assuming that the system log is monotonic.
|
|
*/
|
|
|
|
static double
|
|
m_log2(double x)
|
|
{
|
|
if (!Py_IS_FINITE(x)) {
|
|
if (Py_IS_NAN(x))
|
|
return x; /* log2(nan) = nan */
|
|
else if (x > 0.0)
|
|
return x; /* log2(+inf) = +inf */
|
|
else {
|
|
errno = EDOM;
|
|
return Py_NAN; /* log2(-inf) = nan, invalid-operation */
|
|
}
|
|
}
|
|
|
|
if (x > 0.0) {
|
|
#ifdef HAVE_LOG2
|
|
return log2(x);
|
|
#else
|
|
double m;
|
|
int e;
|
|
m = frexp(x, &e);
|
|
/* We want log2(m * 2**e) == log(m) / log(2) + e. Care is needed when
|
|
* x is just greater than 1.0: in that case e is 1, log(m) is negative,
|
|
* and we get significant cancellation error from the addition of
|
|
* log(m) / log(2) to e. The slight rewrite of the expression below
|
|
* avoids this problem.
|
|
*/
|
|
if (x >= 1.0) {
|
|
return log(2.0 * m) / log(2.0) + (e - 1);
|
|
}
|
|
else {
|
|
return log(m) / log(2.0) + e;
|
|
}
|
|
#endif
|
|
}
|
|
else if (x == 0.0) {
|
|
errno = EDOM;
|
|
return -Py_HUGE_VAL; /* log2(0) = -inf, divide-by-zero */
|
|
}
|
|
else {
|
|
errno = EDOM;
|
|
return Py_NAN; /* log2(-inf) = nan, invalid-operation */
|
|
}
|
|
}
|
|
|
|
static double
|
|
m_log10(double x)
|
|
{
|
|
if (Py_IS_FINITE(x)) {
|
|
if (x > 0.0)
|
|
return log10(x);
|
|
errno = EDOM;
|
|
if (x == 0.0)
|
|
return -Py_HUGE_VAL; /* log10(0) = -inf */
|
|
else
|
|
return Py_NAN; /* log10(-ve) = nan */
|
|
}
|
|
else if (Py_IS_NAN(x))
|
|
return x; /* log10(nan) = nan */
|
|
else if (x > 0.0)
|
|
return x; /* log10(inf) = inf */
|
|
else {
|
|
errno = EDOM;
|
|
return Py_NAN; /* log10(-inf) = nan */
|
|
}
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.gcd
|
|
|
|
x as a: object
|
|
y as b: object
|
|
/
|
|
|
|
greatest common divisor of x and y
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_gcd_impl(PyObject *module, PyObject *a, PyObject *b)
|
|
/*[clinic end generated code: output=7b2e0c151bd7a5d8 input=c2691e57fb2a98fa]*/
|
|
{
|
|
PyObject *g;
|
|
|
|
a = PyNumber_Index(a);
|
|
if (a == NULL)
|
|
return NULL;
|
|
b = PyNumber_Index(b);
|
|
if (b == NULL) {
|
|
Py_DECREF(a);
|
|
return NULL;
|
|
}
|
|
g = _PyLong_GCD(a, b);
|
|
Py_DECREF(a);
|
|
Py_DECREF(b);
|
|
return g;
|
|
}
|
|
|
|
|
|
/* Call is_error when errno != 0, and where x is the result libm
|
|
* returned. is_error will usually set up an exception and return
|
|
* true (1), but may return false (0) without setting up an exception.
|
|
*/
|
|
static int
|
|
is_error(double x)
|
|
{
|
|
int result = 1; /* presumption of guilt */
|
|
assert(errno); /* non-zero errno is a precondition for calling */
|
|
if (errno == EDOM)
|
|
PyErr_SetString(PyExc_ValueError, "math domain error");
|
|
|
|
else if (errno == ERANGE) {
|
|
/* ANSI C generally requires libm functions to set ERANGE
|
|
* on overflow, but also generally *allows* them to set
|
|
* ERANGE on underflow too. There's no consistency about
|
|
* the latter across platforms.
|
|
* Alas, C99 never requires that errno be set.
|
|
* Here we suppress the underflow errors (libm functions
|
|
* should return a zero on underflow, and +- HUGE_VAL on
|
|
* overflow, so testing the result for zero suffices to
|
|
* distinguish the cases).
|
|
*
|
|
* On some platforms (Ubuntu/ia64) it seems that errno can be
|
|
* set to ERANGE for subnormal results that do *not* underflow
|
|
* to zero. So to be safe, we'll ignore ERANGE whenever the
|
|
* function result is less than one in absolute value.
|
|
*/
|
|
if (fabs(x) < 1.0)
|
|
result = 0;
|
|
else
|
|
PyErr_SetString(PyExc_OverflowError,
|
|
"math range error");
|
|
}
|
|
else
|
|
/* Unexpected math error */
|
|
PyErr_SetFromErrno(PyExc_ValueError);
|
|
return result;
|
|
}
|
|
|
|
/*
|
|
math_1 is used to wrap a libm function f that takes a double
|
|
argument and returns a double.
|
|
|
|
The error reporting follows these rules, which are designed to do
|
|
the right thing on C89/C99 platforms and IEEE 754/non IEEE 754
|
|
platforms.
|
|
|
|
- a NaN result from non-NaN inputs causes ValueError to be raised
|
|
- an infinite result from finite inputs causes OverflowError to be
|
|
raised if can_overflow is 1, or raises ValueError if can_overflow
|
|
is 0.
|
|
- if the result is finite and errno == EDOM then ValueError is
|
|
raised
|
|
- if the result is finite and nonzero and errno == ERANGE then
|
|
OverflowError is raised
|
|
|
|
The last rule is used to catch overflow on platforms which follow
|
|
C89 but for which HUGE_VAL is not an infinity.
|
|
|
|
For the majority of one-argument functions these rules are enough
|
|
to ensure that Python's functions behave as specified in 'Annex F'
|
|
of the C99 standard, with the 'invalid' and 'divide-by-zero'
|
|
floating-point exceptions mapping to Python's ValueError and the
|
|
'overflow' floating-point exception mapping to OverflowError.
|
|
math_1 only works for functions that don't have singularities *and*
|
|
the possibility of overflow; fortunately, that covers everything we
|
|
care about right now.
|
|
*/
|
|
|
|
static PyObject *
|
|
math_1_to_whatever(PyObject *arg, double (*func) (double),
|
|
PyObject *(*from_double_func) (double),
|
|
int can_overflow)
|
|
{
|
|
double x, r;
|
|
x = PyFloat_AsDouble(arg);
|
|
if (x == -1.0 && PyErr_Occurred())
|
|
return NULL;
|
|
errno = 0;
|
|
r = (*func)(x);
|
|
if (Py_IS_NAN(r) && !Py_IS_NAN(x)) {
|
|
PyErr_SetString(PyExc_ValueError,
|
|
"math domain error"); /* invalid arg */
|
|
return NULL;
|
|
}
|
|
if (Py_IS_INFINITY(r) && Py_IS_FINITE(x)) {
|
|
if (can_overflow)
|
|
PyErr_SetString(PyExc_OverflowError,
|
|
"math range error"); /* overflow */
|
|
else
|
|
PyErr_SetString(PyExc_ValueError,
|
|
"math domain error"); /* singularity */
|
|
return NULL;
|
|
}
|
|
if (Py_IS_FINITE(r) && errno && is_error(r))
|
|
/* this branch unnecessary on most platforms */
|
|
return NULL;
|
|
|
|
return (*from_double_func)(r);
|
|
}
|
|
|
|
/* variant of math_1, to be used when the function being wrapped is known to
|
|
set errno properly (that is, errno = EDOM for invalid or divide-by-zero,
|
|
errno = ERANGE for overflow). */
|
|
|
|
static PyObject *
|
|
math_1a(PyObject *arg, double (*func) (double))
|
|
{
|
|
double x, r;
|
|
x = PyFloat_AsDouble(arg);
|
|
if (x == -1.0 && PyErr_Occurred())
|
|
return NULL;
|
|
errno = 0;
|
|
r = (*func)(x);
|
|
if (errno && is_error(r))
|
|
return NULL;
|
|
return PyFloat_FromDouble(r);
|
|
}
|
|
|
|
/*
|
|
math_2 is used to wrap a libm function f that takes two double
|
|
arguments and returns a double.
|
|
|
|
The error reporting follows these rules, which are designed to do
|
|
the right thing on C89/C99 platforms and IEEE 754/non IEEE 754
|
|
platforms.
|
|
|
|
- a NaN result from non-NaN inputs causes ValueError to be raised
|
|
- an infinite result from finite inputs causes OverflowError to be
|
|
raised.
|
|
- if the result is finite and errno == EDOM then ValueError is
|
|
raised
|
|
- if the result is finite and nonzero and errno == ERANGE then
|
|
OverflowError is raised
|
|
|
|
The last rule is used to catch overflow on platforms which follow
|
|
C89 but for which HUGE_VAL is not an infinity.
|
|
|
|
For most two-argument functions (copysign, fmod, hypot, atan2)
|
|
these rules are enough to ensure that Python's functions behave as
|
|
specified in 'Annex F' of the C99 standard, with the 'invalid' and
|
|
'divide-by-zero' floating-point exceptions mapping to Python's
|
|
ValueError and the 'overflow' floating-point exception mapping to
|
|
OverflowError.
|
|
*/
|
|
|
|
static PyObject *
|
|
math_1(PyObject *arg, double (*func) (double), int can_overflow)
|
|
{
|
|
return math_1_to_whatever(arg, func, PyFloat_FromDouble, can_overflow);
|
|
}
|
|
|
|
static PyObject *
|
|
math_2(PyObject *const *args, Py_ssize_t nargs,
|
|
double (*func) (double, double), const char *funcname)
|
|
{
|
|
double x, y, r;
|
|
if (!_PyArg_CheckPositional(funcname, nargs, 2, 2))
|
|
return NULL;
|
|
x = PyFloat_AsDouble(args[0]);
|
|
y = PyFloat_AsDouble(args[1]);
|
|
if ((x == -1.0 || y == -1.0) && PyErr_Occurred())
|
|
return NULL;
|
|
errno = 0;
|
|
r = (*func)(x, y);
|
|
if (Py_IS_NAN(r)) {
|
|
if (!Py_IS_NAN(x) && !Py_IS_NAN(y))
|
|
errno = EDOM;
|
|
else
|
|
errno = 0;
|
|
}
|
|
else if (Py_IS_INFINITY(r)) {
|
|
if (Py_IS_FINITE(x) && Py_IS_FINITE(y))
|
|
errno = ERANGE;
|
|
else
|
|
errno = 0;
|
|
}
|
|
if (errno && is_error(r))
|
|
return NULL;
|
|
else
|
|
return PyFloat_FromDouble(r);
|
|
}
|
|
|
|
#define FUNC1(funcname, func, can_overflow, docstring) \
|
|
static PyObject * math_##funcname(PyObject *self, PyObject *args) { \
|
|
return math_1(args, func, can_overflow); \
|
|
}\
|
|
PyDoc_STRVAR(math_##funcname##_doc, docstring);
|
|
|
|
#define FUNC1A(funcname, func, docstring) \
|
|
static PyObject * math_##funcname(PyObject *self, PyObject *args) { \
|
|
return math_1a(args, func); \
|
|
}\
|
|
PyDoc_STRVAR(math_##funcname##_doc, docstring);
|
|
|
|
#define FUNC2(funcname, func, docstring) \
|
|
static PyObject * math_##funcname(PyObject *self, PyObject *const *args, Py_ssize_t nargs) { \
|
|
return math_2(args, nargs, func, #funcname); \
|
|
}\
|
|
PyDoc_STRVAR(math_##funcname##_doc, docstring);
|
|
|
|
FUNC1(acos, acos, 0,
|
|
"acos($module, x, /)\n--\n\n"
|
|
"Return the arc cosine (measured in radians) of x.\n\n"
|
|
"The result is between 0 and pi.")
|
|
FUNC1(acosh, m_acosh, 0,
|
|
"acosh($module, x, /)\n--\n\n"
|
|
"Return the inverse hyperbolic cosine of x.")
|
|
FUNC1(asin, asin, 0,
|
|
"asin($module, x, /)\n--\n\n"
|
|
"Return the arc sine (measured in radians) of x.\n\n"
|
|
"The result is between -pi/2 and pi/2.")
|
|
FUNC1(asinh, m_asinh, 0,
|
|
"asinh($module, x, /)\n--\n\n"
|
|
"Return the inverse hyperbolic sine of x.")
|
|
FUNC1(atan, atan, 0,
|
|
"atan($module, x, /)\n--\n\n"
|
|
"Return the arc tangent (measured in radians) of x.\n\n"
|
|
"The result is between -pi/2 and pi/2.")
|
|
FUNC2(atan2, m_atan2,
|
|
"atan2($module, y, x, /)\n--\n\n"
|
|
"Return the arc tangent (measured in radians) of y/x.\n\n"
|
|
"Unlike atan(y/x), the signs of both x and y are considered.")
|
|
FUNC1(atanh, m_atanh, 0,
|
|
"atanh($module, x, /)\n--\n\n"
|
|
"Return the inverse hyperbolic tangent of x.")
|
|
|
|
/*[clinic input]
|
|
math.ceil
|
|
|
|
x as number: object
|
|
/
|
|
|
|
Return the ceiling of x as an Integral.
|
|
|
|
This is the smallest integer >= x.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_ceil(PyObject *module, PyObject *number)
|
|
/*[clinic end generated code: output=6c3b8a78bc201c67 input=2725352806399cab]*/
|
|
{
|
|
_Py_IDENTIFIER(__ceil__);
|
|
|
|
if (!PyFloat_CheckExact(number)) {
|
|
PyObject *method = _PyObject_LookupSpecial(number, &PyId___ceil__);
|
|
if (method != NULL) {
|
|
PyObject *result = _PyObject_CallNoArg(method);
|
|
Py_DECREF(method);
|
|
return result;
|
|
}
|
|
if (PyErr_Occurred())
|
|
return NULL;
|
|
}
|
|
double x = PyFloat_AsDouble(number);
|
|
if (x == -1.0 && PyErr_Occurred())
|
|
return NULL;
|
|
|
|
return PyLong_FromDouble(ceil(x));
|
|
}
|
|
|
|
FUNC2(copysign, copysign,
|
|
"copysign($module, x, y, /)\n--\n\n"
|
|
"Return a float with the magnitude (absolute value) of x but the sign of y.\n\n"
|
|
"On platforms that support signed zeros, copysign(1.0, -0.0)\n"
|
|
"returns -1.0.\n")
|
|
FUNC1(cos, cos, 0,
|
|
"cos($module, x, /)\n--\n\n"
|
|
"Return the cosine of x (measured in radians).")
|
|
FUNC1(cosh, cosh, 1,
|
|
"cosh($module, x, /)\n--\n\n"
|
|
"Return the hyperbolic cosine of x.")
|
|
FUNC1A(erf, m_erf,
|
|
"erf($module, x, /)\n--\n\n"
|
|
"Error function at x.")
|
|
FUNC1A(erfc, m_erfc,
|
|
"erfc($module, x, /)\n--\n\n"
|
|
"Complementary error function at x.")
|
|
FUNC1(exp, exp, 1,
|
|
"exp($module, x, /)\n--\n\n"
|
|
"Return e raised to the power of x.")
|
|
FUNC1(expm1, m_expm1, 1,
|
|
"expm1($module, x, /)\n--\n\n"
|
|
"Return exp(x)-1.\n\n"
|
|
"This function avoids the loss of precision involved in the direct "
|
|
"evaluation of exp(x)-1 for small x.")
|
|
FUNC1(fabs, fabs, 0,
|
|
"fabs($module, x, /)\n--\n\n"
|
|
"Return the absolute value of the float x.")
|
|
|
|
/*[clinic input]
|
|
math.floor
|
|
|
|
x as number: object
|
|
/
|
|
|
|
Return the floor of x as an Integral.
|
|
|
|
This is the largest integer <= x.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_floor(PyObject *module, PyObject *number)
|
|
/*[clinic end generated code: output=c6a65c4884884b8a input=63af6b5d7ebcc3d6]*/
|
|
{
|
|
_Py_IDENTIFIER(__floor__);
|
|
|
|
if (!PyFloat_CheckExact(number)) {
|
|
PyObject *method = _PyObject_LookupSpecial(number, &PyId___floor__);
|
|
if (method != NULL) {
|
|
PyObject *result = _PyObject_CallNoArg(method);
|
|
Py_DECREF(method);
|
|
return result;
|
|
}
|
|
if (PyErr_Occurred())
|
|
return NULL;
|
|
}
|
|
double x = PyFloat_AsDouble(number);
|
|
if (x == -1.0 && PyErr_Occurred())
|
|
return NULL;
|
|
|
|
return PyLong_FromDouble(floor(x));
|
|
}
|
|
|
|
FUNC1A(gamma, m_tgamma,
|
|
"gamma($module, x, /)\n--\n\n"
|
|
"Gamma function at x.")
|
|
FUNC1A(lgamma, m_lgamma,
|
|
"lgamma($module, x, /)\n--\n\n"
|
|
"Natural logarithm of absolute value of Gamma function at x.")
|
|
FUNC1(log1p, m_log1p, 0,
|
|
"log1p($module, x, /)\n--\n\n"
|
|
"Return the natural logarithm of 1+x (base e).\n\n"
|
|
"The result is computed in a way which is accurate for x near zero.")
|
|
FUNC2(remainder, m_remainder,
|
|
"remainder($module, x, y, /)\n--\n\n"
|
|
"Difference between x and the closest integer multiple of y.\n\n"
|
|
"Return x - n*y where n*y is the closest integer multiple of y.\n"
|
|
"In the case where x is exactly halfway between two multiples of\n"
|
|
"y, the nearest even value of n is used. The result is always exact.")
|
|
FUNC1(sin, sin, 0,
|
|
"sin($module, x, /)\n--\n\n"
|
|
"Return the sine of x (measured in radians).")
|
|
FUNC1(sinh, sinh, 1,
|
|
"sinh($module, x, /)\n--\n\n"
|
|
"Return the hyperbolic sine of x.")
|
|
FUNC1(sqrt, sqrt, 0,
|
|
"sqrt($module, x, /)\n--\n\n"
|
|
"Return the square root of x.")
|
|
FUNC1(tan, tan, 0,
|
|
"tan($module, x, /)\n--\n\n"
|
|
"Return the tangent of x (measured in radians).")
|
|
FUNC1(tanh, tanh, 0,
|
|
"tanh($module, x, /)\n--\n\n"
|
|
"Return the hyperbolic tangent of x.")
|
|
|
|
/* Precision summation function as msum() by Raymond Hettinger in
|
|
<http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/393090>,
|
|
enhanced with the exact partials sum and roundoff from Mark
|
|
Dickinson's post at <http://bugs.python.org/file10357/msum4.py>.
|
|
See those links for more details, proofs and other references.
|
|
|
|
Note 1: IEEE 754R floating point semantics are assumed,
|
|
but the current implementation does not re-establish special
|
|
value semantics across iterations (i.e. handling -Inf + Inf).
|
|
|
|
Note 2: No provision is made for intermediate overflow handling;
|
|
therefore, sum([1e+308, 1e-308, 1e+308]) returns 1e+308 while
|
|
sum([1e+308, 1e+308, 1e-308]) raises an OverflowError due to the
|
|
overflow of the first partial sum.
|
|
|
|
Note 3: The intermediate values lo, yr, and hi are declared volatile so
|
|
aggressive compilers won't algebraically reduce lo to always be exactly 0.0.
|
|
Also, the volatile declaration forces the values to be stored in memory as
|
|
regular doubles instead of extended long precision (80-bit) values. This
|
|
prevents double rounding because any addition or subtraction of two doubles
|
|
can be resolved exactly into double-sized hi and lo values. As long as the
|
|
hi value gets forced into a double before yr and lo are computed, the extra
|
|
bits in downstream extended precision operations (x87 for example) will be
|
|
exactly zero and therefore can be losslessly stored back into a double,
|
|
thereby preventing double rounding.
|
|
|
|
Note 4: A similar implementation is in Modules/cmathmodule.c.
|
|
Be sure to update both when making changes.
|
|
|
|
Note 5: The signature of math.fsum() differs from builtins.sum()
|
|
because the start argument doesn't make sense in the context of
|
|
accurate summation. Since the partials table is collapsed before
|
|
returning a result, sum(seq2, start=sum(seq1)) may not equal the
|
|
accurate result returned by sum(itertools.chain(seq1, seq2)).
|
|
*/
|
|
|
|
#define NUM_PARTIALS 32 /* initial partials array size, on stack */
|
|
|
|
/* Extend the partials array p[] by doubling its size. */
|
|
static int /* non-zero on error */
|
|
_fsum_realloc(double **p_ptr, Py_ssize_t n,
|
|
double *ps, Py_ssize_t *m_ptr)
|
|
{
|
|
void *v = NULL;
|
|
Py_ssize_t m = *m_ptr;
|
|
|
|
m += m; /* double */
|
|
if (n < m && (size_t)m < ((size_t)PY_SSIZE_T_MAX / sizeof(double))) {
|
|
double *p = *p_ptr;
|
|
if (p == ps) {
|
|
v = PyMem_Malloc(sizeof(double) * m);
|
|
if (v != NULL)
|
|
memcpy(v, ps, sizeof(double) * n);
|
|
}
|
|
else
|
|
v = PyMem_Realloc(p, sizeof(double) * m);
|
|
}
|
|
if (v == NULL) { /* size overflow or no memory */
|
|
PyErr_SetString(PyExc_MemoryError, "math.fsum partials");
|
|
return 1;
|
|
}
|
|
*p_ptr = (double*) v;
|
|
*m_ptr = m;
|
|
return 0;
|
|
}
|
|
|
|
/* Full precision summation of a sequence of floats.
|
|
|
|
def msum(iterable):
|
|
partials = [] # sorted, non-overlapping partial sums
|
|
for x in iterable:
|
|
i = 0
|
|
for y in partials:
|
|
if abs(x) < abs(y):
|
|
x, y = y, x
|
|
hi = x + y
|
|
lo = y - (hi - x)
|
|
if lo:
|
|
partials[i] = lo
|
|
i += 1
|
|
x = hi
|
|
partials[i:] = [x]
|
|
return sum_exact(partials)
|
|
|
|
Rounded x+y stored in hi with the roundoff stored in lo. Together hi+lo
|
|
are exactly equal to x+y. The inner loop applies hi/lo summation to each
|
|
partial so that the list of partial sums remains exact.
|
|
|
|
Sum_exact() adds the partial sums exactly and correctly rounds the final
|
|
result (using the round-half-to-even rule). The items in partials remain
|
|
non-zero, non-special, non-overlapping and strictly increasing in
|
|
magnitude, but possibly not all having the same sign.
|
|
|
|
Depends on IEEE 754 arithmetic guarantees and half-even rounding.
|
|
*/
|
|
|
|
/*[clinic input]
|
|
math.fsum
|
|
|
|
seq: object
|
|
/
|
|
|
|
Return an accurate floating point sum of values in the iterable seq.
|
|
|
|
Assumes IEEE-754 floating point arithmetic.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_fsum(PyObject *module, PyObject *seq)
|
|
/*[clinic end generated code: output=ba5c672b87fe34fc input=c51b7d8caf6f6e82]*/
|
|
{
|
|
PyObject *item, *iter, *sum = NULL;
|
|
Py_ssize_t i, j, n = 0, m = NUM_PARTIALS;
|
|
double x, y, t, ps[NUM_PARTIALS], *p = ps;
|
|
double xsave, special_sum = 0.0, inf_sum = 0.0;
|
|
volatile double hi, yr, lo;
|
|
|
|
iter = PyObject_GetIter(seq);
|
|
if (iter == NULL)
|
|
return NULL;
|
|
|
|
for(;;) { /* for x in iterable */
|
|
assert(0 <= n && n <= m);
|
|
assert((m == NUM_PARTIALS && p == ps) ||
|
|
(m > NUM_PARTIALS && p != NULL));
|
|
|
|
item = PyIter_Next(iter);
|
|
if (item == NULL) {
|
|
if (PyErr_Occurred())
|
|
goto _fsum_error;
|
|
break;
|
|
}
|
|
ASSIGN_DOUBLE(x, item, error_with_item);
|
|
Py_DECREF(item);
|
|
|
|
xsave = x;
|
|
for (i = j = 0; j < n; j++) { /* for y in partials */
|
|
y = p[j];
|
|
if (fabs(x) < fabs(y)) {
|
|
t = x; x = y; y = t;
|
|
}
|
|
hi = x + y;
|
|
yr = hi - x;
|
|
lo = y - yr;
|
|
if (lo != 0.0)
|
|
p[i++] = lo;
|
|
x = hi;
|
|
}
|
|
|
|
n = i; /* ps[i:] = [x] */
|
|
if (x != 0.0) {
|
|
if (! Py_IS_FINITE(x)) {
|
|
/* a nonfinite x could arise either as
|
|
a result of intermediate overflow, or
|
|
as a result of a nan or inf in the
|
|
summands */
|
|
if (Py_IS_FINITE(xsave)) {
|
|
PyErr_SetString(PyExc_OverflowError,
|
|
"intermediate overflow in fsum");
|
|
goto _fsum_error;
|
|
}
|
|
if (Py_IS_INFINITY(xsave))
|
|
inf_sum += xsave;
|
|
special_sum += xsave;
|
|
/* reset partials */
|
|
n = 0;
|
|
}
|
|
else if (n >= m && _fsum_realloc(&p, n, ps, &m))
|
|
goto _fsum_error;
|
|
else
|
|
p[n++] = x;
|
|
}
|
|
}
|
|
|
|
if (special_sum != 0.0) {
|
|
if (Py_IS_NAN(inf_sum))
|
|
PyErr_SetString(PyExc_ValueError,
|
|
"-inf + inf in fsum");
|
|
else
|
|
sum = PyFloat_FromDouble(special_sum);
|
|
goto _fsum_error;
|
|
}
|
|
|
|
hi = 0.0;
|
|
if (n > 0) {
|
|
hi = p[--n];
|
|
/* sum_exact(ps, hi) from the top, stop when the sum becomes
|
|
inexact. */
|
|
while (n > 0) {
|
|
x = hi;
|
|
y = p[--n];
|
|
assert(fabs(y) < fabs(x));
|
|
hi = x + y;
|
|
yr = hi - x;
|
|
lo = y - yr;
|
|
if (lo != 0.0)
|
|
break;
|
|
}
|
|
/* Make half-even rounding work across multiple partials.
|
|
Needed so that sum([1e-16, 1, 1e16]) will round-up the last
|
|
digit to two instead of down to zero (the 1e-16 makes the 1
|
|
slightly closer to two). With a potential 1 ULP rounding
|
|
error fixed-up, math.fsum() can guarantee commutativity. */
|
|
if (n > 0 && ((lo < 0.0 && p[n-1] < 0.0) ||
|
|
(lo > 0.0 && p[n-1] > 0.0))) {
|
|
y = lo * 2.0;
|
|
x = hi + y;
|
|
yr = x - hi;
|
|
if (y == yr)
|
|
hi = x;
|
|
}
|
|
}
|
|
sum = PyFloat_FromDouble(hi);
|
|
|
|
_fsum_error:
|
|
Py_DECREF(iter);
|
|
if (p != ps)
|
|
PyMem_Free(p);
|
|
return sum;
|
|
|
|
error_with_item:
|
|
Py_DECREF(item);
|
|
goto _fsum_error;
|
|
}
|
|
|
|
#undef NUM_PARTIALS
|
|
|
|
|
|
/* Return the smallest integer k such that n < 2**k, or 0 if n == 0.
|
|
* Equivalent to floor(lg(x))+1. Also equivalent to: bitwidth_of_type -
|
|
* count_leading_zero_bits(x)
|
|
*/
|
|
|
|
/* XXX: This routine does more or less the same thing as
|
|
* bits_in_digit() in Objects/longobject.c. Someday it would be nice to
|
|
* consolidate them. On BSD, there's a library function called fls()
|
|
* that we could use, and GCC provides __builtin_clz().
|
|
*/
|
|
|
|
static unsigned long
|
|
bit_length(unsigned long n)
|
|
{
|
|
unsigned long len = 0;
|
|
while (n != 0) {
|
|
++len;
|
|
n >>= 1;
|
|
}
|
|
return len;
|
|
}
|
|
|
|
static unsigned long
|
|
count_set_bits(unsigned long n)
|
|
{
|
|
unsigned long count = 0;
|
|
while (n != 0) {
|
|
++count;
|
|
n &= n - 1; /* clear least significant bit */
|
|
}
|
|
return count;
|
|
}
|
|
|
|
/* Integer square root
|
|
|
|
Given a nonnegative integer `n`, we want to compute the largest integer
|
|
`a` for which `a * a <= n`, or equivalently the integer part of the exact
|
|
square root of `n`.
|
|
|
|
We use an adaptive-precision pure-integer version of Newton's iteration. Given
|
|
a positive integer `n`, the algorithm produces at each iteration an integer
|
|
approximation `a` to the square root of `n >> s` for some even integer `s`,
|
|
with `s` decreasing as the iterations progress. On the final iteration, `s` is
|
|
zero and we have an approximation to the square root of `n` itself.
|
|
|
|
At every step, the approximation `a` is strictly within 1.0 of the true square
|
|
root, so we have
|
|
|
|
(a - 1)**2 < (n >> s) < (a + 1)**2
|
|
|
|
After the final iteration, a check-and-correct step is needed to determine
|
|
whether `a` or `a - 1` gives the desired integer square root of `n`.
|
|
|
|
The algorithm is remarkable in its simplicity. There's no need for a
|
|
per-iteration check-and-correct step, and termination is straightforward: the
|
|
number of iterations is known in advance (it's exactly `floor(log2(log2(n)))`
|
|
for `n > 1`). The only tricky part of the correctness proof is in establishing
|
|
that the bound `(a - 1)**2 < (n >> s) < (a + 1)**2` is maintained from one
|
|
iteration to the next. A sketch of the proof of this is given below.
|
|
|
|
In addition to the proof sketch, a formal, computer-verified proof
|
|
of correctness (using Lean) of an equivalent recursive algorithm can be found
|
|
here:
|
|
|
|
https://github.com/mdickinson/snippets/blob/master/proofs/isqrt/src/isqrt.lean
|
|
|
|
|
|
Here's Python code equivalent to the C implementation below:
|
|
|
|
def isqrt(n):
|
|
"""
|
|
Return the integer part of the square root of the input.
|
|
"""
|
|
n = operator.index(n)
|
|
|
|
if n < 0:
|
|
raise ValueError("isqrt() argument must be nonnegative")
|
|
if n == 0:
|
|
return 0
|
|
|
|
c = (n.bit_length() - 1) // 2
|
|
a = 1
|
|
d = 0
|
|
for s in reversed(range(c.bit_length())):
|
|
# Loop invariant: (a-1)**2 < (n >> 2*(c - d)) < (a+1)**2
|
|
e = d
|
|
d = c >> s
|
|
a = (a << d - e - 1) + (n >> 2*c - e - d + 1) // a
|
|
|
|
return a - (a*a > n)
|
|
|
|
|
|
Sketch of proof of correctness
|
|
------------------------------
|
|
|
|
The delicate part of the correctness proof is showing that the loop invariant
|
|
is preserved from one iteration to the next. That is, just before the line
|
|
|
|
a = (a << d - e - 1) + (n >> 2*c - e - d + 1) // a
|
|
|
|
is executed in the above code, we know that
|
|
|
|
(1) (a - 1)**2 < (n >> 2*(c - e)) < (a + 1)**2.
|
|
|
|
(since `e` is always the value of `d` from the previous iteration). We must
|
|
prove that after that line is executed, we have
|
|
|
|
(a - 1)**2 < (n >> 2*(c - d)) < (a + 1)**2
|
|
|
|
To facilitate the proof, we make some changes of notation. Write `m` for
|
|
`n >> 2*(c-d)`, and write `b` for the new value of `a`, so
|
|
|
|
b = (a << d - e - 1) + (n >> 2*c - e - d + 1) // a
|
|
|
|
or equivalently:
|
|
|
|
(2) b = (a << d - e - 1) + (m >> d - e + 1) // a
|
|
|
|
Then we can rewrite (1) as:
|
|
|
|
(3) (a - 1)**2 < (m >> 2*(d - e)) < (a + 1)**2
|
|
|
|
and we must show that (b - 1)**2 < m < (b + 1)**2.
|
|
|
|
From this point on, we switch to mathematical notation, so `/` means exact
|
|
division rather than integer division and `^` is used for exponentiation. We
|
|
use the `√` symbol for the exact square root. In (3), we can remove the
|
|
implicit floor operation to give:
|
|
|
|
(4) (a - 1)^2 < m / 4^(d - e) < (a + 1)^2
|
|
|
|
Taking square roots throughout (4), scaling by `2^(d-e)`, and rearranging gives
|
|
|
|
(5) 0 <= | 2^(d-e)a - √m | < 2^(d-e)
|
|
|
|
Squaring and dividing through by `2^(d-e+1) a` gives
|
|
|
|
(6) 0 <= 2^(d-e-1) a + m / (2^(d-e+1) a) - √m < 2^(d-e-1) / a
|
|
|
|
We'll show below that `2^(d-e-1) <= a`. Given that, we can replace the
|
|
right-hand side of (6) with `1`, and now replacing the central
|
|
term `m / (2^(d-e+1) a)` with its floor in (6) gives
|
|
|
|
(7) -1 < 2^(d-e-1) a + m // 2^(d-e+1) a - √m < 1
|
|
|
|
Or equivalently, from (2):
|
|
|
|
(7) -1 < b - √m < 1
|
|
|
|
and rearranging gives that `(b-1)^2 < m < (b+1)^2`, which is what we needed
|
|
to prove.
|
|
|
|
We're not quite done: we still have to prove the inequality `2^(d - e - 1) <=
|
|
a` that was used to get line (7) above. From the definition of `c`, we have
|
|
`4^c <= n`, which implies
|
|
|
|
(8) 4^d <= m
|
|
|
|
also, since `e == d >> 1`, `d` is at most `2e + 1`, from which it follows
|
|
that `2d - 2e - 1 <= d` and hence that
|
|
|
|
(9) 4^(2d - 2e - 1) <= m
|
|
|
|
Dividing both sides by `4^(d - e)` gives
|
|
|
|
(10) 4^(d - e - 1) <= m / 4^(d - e)
|
|
|
|
But we know from (4) that `m / 4^(d-e) < (a + 1)^2`, hence
|
|
|
|
(11) 4^(d - e - 1) < (a + 1)^2
|
|
|
|
Now taking square roots of both sides and observing that both `2^(d-e-1)` and
|
|
`a` are integers gives `2^(d - e - 1) <= a`, which is what we needed. This
|
|
completes the proof sketch.
|
|
|
|
*/
|
|
|
|
|
|
/* Approximate square root of a large 64-bit integer.
|
|
|
|
Given `n` satisfying `2**62 <= n < 2**64`, return `a`
|
|
satisfying `(a - 1)**2 < n < (a + 1)**2`. */
|
|
|
|
static uint64_t
|
|
_approximate_isqrt(uint64_t n)
|
|
{
|
|
uint32_t u = 1U + (n >> 62);
|
|
u = (u << 1) + (n >> 59) / u;
|
|
u = (u << 3) + (n >> 53) / u;
|
|
u = (u << 7) + (n >> 41) / u;
|
|
return (u << 15) + (n >> 17) / u;
|
|
}
|
|
|
|
/*[clinic input]
|
|
math.isqrt
|
|
|
|
n: object
|
|
/
|
|
|
|
Return the integer part of the square root of the input.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_isqrt(PyObject *module, PyObject *n)
|
|
/*[clinic end generated code: output=35a6f7f980beab26 input=5b6e7ae4fa6c43d6]*/
|
|
{
|
|
int a_too_large, c_bit_length;
|
|
size_t c, d;
|
|
uint64_t m, u;
|
|
PyObject *a = NULL, *b;
|
|
|
|
n = PyNumber_Index(n);
|
|
if (n == NULL) {
|
|
return NULL;
|
|
}
|
|
|
|
if (_PyLong_Sign(n) < 0) {
|
|
PyErr_SetString(
|
|
PyExc_ValueError,
|
|
"isqrt() argument must be nonnegative");
|
|
goto error;
|
|
}
|
|
if (_PyLong_Sign(n) == 0) {
|
|
Py_DECREF(n);
|
|
return PyLong_FromLong(0);
|
|
}
|
|
|
|
/* c = (n.bit_length() - 1) // 2 */
|
|
c = _PyLong_NumBits(n);
|
|
if (c == (size_t)(-1)) {
|
|
goto error;
|
|
}
|
|
c = (c - 1U) / 2U;
|
|
|
|
/* Fast path: if c <= 31 then n < 2**64 and we can compute directly with a
|
|
fast, almost branch-free algorithm. In the final correction, we use `u*u
|
|
- 1 >= m` instead of the simpler `u*u > m` in order to get the correct
|
|
result in the corner case where `u=2**32`. */
|
|
if (c <= 31U) {
|
|
m = (uint64_t)PyLong_AsUnsignedLongLong(n);
|
|
Py_DECREF(n);
|
|
if (m == (uint64_t)(-1) && PyErr_Occurred()) {
|
|
return NULL;
|
|
}
|
|
u = _approximate_isqrt(m << (62U - 2U*c)) >> (31U - c);
|
|
u -= u * u - 1U >= m;
|
|
return PyLong_FromUnsignedLongLong((unsigned long long)u);
|
|
}
|
|
|
|
/* Slow path: n >= 2**64. We perform the first five iterations in C integer
|
|
arithmetic, then switch to using Python long integers. */
|
|
|
|
/* From n >= 2**64 it follows that c.bit_length() >= 6. */
|
|
c_bit_length = 6;
|
|
while ((c >> c_bit_length) > 0U) {
|
|
++c_bit_length;
|
|
}
|
|
|
|
/* Initialise d and a. */
|
|
d = c >> (c_bit_length - 5);
|
|
b = _PyLong_Rshift(n, 2U*c - 62U);
|
|
if (b == NULL) {
|
|
goto error;
|
|
}
|
|
m = (uint64_t)PyLong_AsUnsignedLongLong(b);
|
|
Py_DECREF(b);
|
|
if (m == (uint64_t)(-1) && PyErr_Occurred()) {
|
|
goto error;
|
|
}
|
|
u = _approximate_isqrt(m) >> (31U - d);
|
|
a = PyLong_FromUnsignedLongLong((unsigned long long)u);
|
|
if (a == NULL) {
|
|
goto error;
|
|
}
|
|
|
|
for (int s = c_bit_length - 6; s >= 0; --s) {
|
|
PyObject *q;
|
|
size_t e = d;
|
|
|
|
d = c >> s;
|
|
|
|
/* q = (n >> 2*c - e - d + 1) // a */
|
|
q = _PyLong_Rshift(n, 2U*c - d - e + 1U);
|
|
if (q == NULL) {
|
|
goto error;
|
|
}
|
|
Py_SETREF(q, PyNumber_FloorDivide(q, a));
|
|
if (q == NULL) {
|
|
goto error;
|
|
}
|
|
|
|
/* a = (a << d - 1 - e) + q */
|
|
Py_SETREF(a, _PyLong_Lshift(a, d - 1U - e));
|
|
if (a == NULL) {
|
|
Py_DECREF(q);
|
|
goto error;
|
|
}
|
|
Py_SETREF(a, PyNumber_Add(a, q));
|
|
Py_DECREF(q);
|
|
if (a == NULL) {
|
|
goto error;
|
|
}
|
|
}
|
|
|
|
/* The correct result is either a or a - 1. Figure out which, and
|
|
decrement a if necessary. */
|
|
|
|
/* a_too_large = n < a * a */
|
|
b = PyNumber_Multiply(a, a);
|
|
if (b == NULL) {
|
|
goto error;
|
|
}
|
|
a_too_large = PyObject_RichCompareBool(n, b, Py_LT);
|
|
Py_DECREF(b);
|
|
if (a_too_large == -1) {
|
|
goto error;
|
|
}
|
|
|
|
if (a_too_large) {
|
|
Py_SETREF(a, PyNumber_Subtract(a, _PyLong_One));
|
|
}
|
|
Py_DECREF(n);
|
|
return a;
|
|
|
|
error:
|
|
Py_XDECREF(a);
|
|
Py_DECREF(n);
|
|
return NULL;
|
|
}
|
|
|
|
/* Divide-and-conquer factorial algorithm
|
|
*
|
|
* Based on the formula and pseudo-code provided at:
|
|
* http://www.luschny.de/math/factorial/binarysplitfact.html
|
|
*
|
|
* Faster algorithms exist, but they're more complicated and depend on
|
|
* a fast prime factorization algorithm.
|
|
*
|
|
* Notes on the algorithm
|
|
* ----------------------
|
|
*
|
|
* factorial(n) is written in the form 2**k * m, with m odd. k and m are
|
|
* computed separately, and then combined using a left shift.
|
|
*
|
|
* The function factorial_odd_part computes the odd part m (i.e., the greatest
|
|
* odd divisor) of factorial(n), using the formula:
|
|
*
|
|
* factorial_odd_part(n) =
|
|
*
|
|
* product_{i >= 0} product_{0 < j <= n / 2**i, j odd} j
|
|
*
|
|
* Example: factorial_odd_part(20) =
|
|
*
|
|
* (1) *
|
|
* (1) *
|
|
* (1 * 3 * 5) *
|
|
* (1 * 3 * 5 * 7 * 9)
|
|
* (1 * 3 * 5 * 7 * 9 * 11 * 13 * 15 * 17 * 19)
|
|
*
|
|
* Here i goes from large to small: the first term corresponds to i=4 (any
|
|
* larger i gives an empty product), and the last term corresponds to i=0.
|
|
* Each term can be computed from the last by multiplying by the extra odd
|
|
* numbers required: e.g., to get from the penultimate term to the last one,
|
|
* we multiply by (11 * 13 * 15 * 17 * 19).
|
|
*
|
|
* To see a hint of why this formula works, here are the same numbers as above
|
|
* but with the even parts (i.e., the appropriate powers of 2) included. For
|
|
* each subterm in the product for i, we multiply that subterm by 2**i:
|
|
*
|
|
* factorial(20) =
|
|
*
|
|
* (16) *
|
|
* (8) *
|
|
* (4 * 12 * 20) *
|
|
* (2 * 6 * 10 * 14 * 18) *
|
|
* (1 * 3 * 5 * 7 * 9 * 11 * 13 * 15 * 17 * 19)
|
|
*
|
|
* The factorial_partial_product function computes the product of all odd j in
|
|
* range(start, stop) for given start and stop. It's used to compute the
|
|
* partial products like (11 * 13 * 15 * 17 * 19) in the example above. It
|
|
* operates recursively, repeatedly splitting the range into two roughly equal
|
|
* pieces until the subranges are small enough to be computed using only C
|
|
* integer arithmetic.
|
|
*
|
|
* The two-valuation k (i.e., the exponent of the largest power of 2 dividing
|
|
* the factorial) is computed independently in the main math_factorial
|
|
* function. By standard results, its value is:
|
|
*
|
|
* two_valuation = n//2 + n//4 + n//8 + ....
|
|
*
|
|
* It can be shown (e.g., by complete induction on n) that two_valuation is
|
|
* equal to n - count_set_bits(n), where count_set_bits(n) gives the number of
|
|
* '1'-bits in the binary expansion of n.
|
|
*/
|
|
|
|
/* factorial_partial_product: Compute product(range(start, stop, 2)) using
|
|
* divide and conquer. Assumes start and stop are odd and stop > start.
|
|
* max_bits must be >= bit_length(stop - 2). */
|
|
|
|
static PyObject *
|
|
factorial_partial_product(unsigned long start, unsigned long stop,
|
|
unsigned long max_bits)
|
|
{
|
|
unsigned long midpoint, num_operands;
|
|
PyObject *left = NULL, *right = NULL, *result = NULL;
|
|
|
|
/* If the return value will fit an unsigned long, then we can
|
|
* multiply in a tight, fast loop where each multiply is O(1).
|
|
* Compute an upper bound on the number of bits required to store
|
|
* the answer.
|
|
*
|
|
* Storing some integer z requires floor(lg(z))+1 bits, which is
|
|
* conveniently the value returned by bit_length(z). The
|
|
* product x*y will require at most
|
|
* bit_length(x) + bit_length(y) bits to store, based
|
|
* on the idea that lg product = lg x + lg y.
|
|
*
|
|
* We know that stop - 2 is the largest number to be multiplied. From
|
|
* there, we have: bit_length(answer) <= num_operands *
|
|
* bit_length(stop - 2)
|
|
*/
|
|
|
|
num_operands = (stop - start) / 2;
|
|
/* The "num_operands <= 8 * SIZEOF_LONG" check guards against the
|
|
* unlikely case of an overflow in num_operands * max_bits. */
|
|
if (num_operands <= 8 * SIZEOF_LONG &&
|
|
num_operands * max_bits <= 8 * SIZEOF_LONG) {
|
|
unsigned long j, total;
|
|
for (total = start, j = start + 2; j < stop; j += 2)
|
|
total *= j;
|
|
return PyLong_FromUnsignedLong(total);
|
|
}
|
|
|
|
/* find midpoint of range(start, stop), rounded up to next odd number. */
|
|
midpoint = (start + num_operands) | 1;
|
|
left = factorial_partial_product(start, midpoint,
|
|
bit_length(midpoint - 2));
|
|
if (left == NULL)
|
|
goto error;
|
|
right = factorial_partial_product(midpoint, stop, max_bits);
|
|
if (right == NULL)
|
|
goto error;
|
|
result = PyNumber_Multiply(left, right);
|
|
|
|
error:
|
|
Py_XDECREF(left);
|
|
Py_XDECREF(right);
|
|
return result;
|
|
}
|
|
|
|
/* factorial_odd_part: compute the odd part of factorial(n). */
|
|
|
|
static PyObject *
|
|
factorial_odd_part(unsigned long n)
|
|
{
|
|
long i;
|
|
unsigned long v, lower, upper;
|
|
PyObject *partial, *tmp, *inner, *outer;
|
|
|
|
inner = PyLong_FromLong(1);
|
|
if (inner == NULL)
|
|
return NULL;
|
|
outer = inner;
|
|
Py_INCREF(outer);
|
|
|
|
upper = 3;
|
|
for (i = bit_length(n) - 2; i >= 0; i--) {
|
|
v = n >> i;
|
|
if (v <= 2)
|
|
continue;
|
|
lower = upper;
|
|
/* (v + 1) | 1 = least odd integer strictly larger than n / 2**i */
|
|
upper = (v + 1) | 1;
|
|
/* Here inner is the product of all odd integers j in the range (0,
|
|
n/2**(i+1)]. The factorial_partial_product call below gives the
|
|
product of all odd integers j in the range (n/2**(i+1), n/2**i]. */
|
|
partial = factorial_partial_product(lower, upper, bit_length(upper-2));
|
|
/* inner *= partial */
|
|
if (partial == NULL)
|
|
goto error;
|
|
tmp = PyNumber_Multiply(inner, partial);
|
|
Py_DECREF(partial);
|
|
if (tmp == NULL)
|
|
goto error;
|
|
Py_DECREF(inner);
|
|
inner = tmp;
|
|
/* Now inner is the product of all odd integers j in the range (0,
|
|
n/2**i], giving the inner product in the formula above. */
|
|
|
|
/* outer *= inner; */
|
|
tmp = PyNumber_Multiply(outer, inner);
|
|
if (tmp == NULL)
|
|
goto error;
|
|
Py_DECREF(outer);
|
|
outer = tmp;
|
|
}
|
|
Py_DECREF(inner);
|
|
return outer;
|
|
|
|
error:
|
|
Py_DECREF(outer);
|
|
Py_DECREF(inner);
|
|
return NULL;
|
|
}
|
|
|
|
|
|
/* Lookup table for small factorial values */
|
|
|
|
static const unsigned long SmallFactorials[] = {
|
|
1, 1, 2, 6, 24, 120, 720, 5040, 40320,
|
|
362880, 3628800, 39916800, 479001600,
|
|
#if SIZEOF_LONG >= 8
|
|
6227020800, 87178291200, 1307674368000,
|
|
20922789888000, 355687428096000, 6402373705728000,
|
|
121645100408832000, 2432902008176640000
|
|
#endif
|
|
};
|
|
|
|
/*[clinic input]
|
|
math.factorial
|
|
|
|
x as arg: object
|
|
/
|
|
|
|
Find x!.
|
|
|
|
Raise a ValueError if x is negative or non-integral.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_factorial(PyObject *module, PyObject *arg)
|
|
/*[clinic end generated code: output=6686f26fae00e9ca input=6d1c8105c0d91fb4]*/
|
|
{
|
|
long x, two_valuation;
|
|
int overflow;
|
|
PyObject *result, *odd_part, *pyint_form;
|
|
|
|
if (PyFloat_Check(arg)) {
|
|
if (PyErr_WarnEx(PyExc_DeprecationWarning,
|
|
"Using factorial() with floats is deprecated",
|
|
1) < 0)
|
|
{
|
|
return NULL;
|
|
}
|
|
PyObject *lx;
|
|
double dx = PyFloat_AS_DOUBLE((PyFloatObject *)arg);
|
|
if (!(Py_IS_FINITE(dx) && dx == floor(dx))) {
|
|
PyErr_SetString(PyExc_ValueError,
|
|
"factorial() only accepts integral values");
|
|
return NULL;
|
|
}
|
|
lx = PyLong_FromDouble(dx);
|
|
if (lx == NULL)
|
|
return NULL;
|
|
x = PyLong_AsLongAndOverflow(lx, &overflow);
|
|
Py_DECREF(lx);
|
|
}
|
|
else {
|
|
pyint_form = PyNumber_Index(arg);
|
|
if (pyint_form == NULL) {
|
|
return NULL;
|
|
}
|
|
x = PyLong_AsLongAndOverflow(pyint_form, &overflow);
|
|
Py_DECREF(pyint_form);
|
|
}
|
|
|
|
if (x == -1 && PyErr_Occurred()) {
|
|
return NULL;
|
|
}
|
|
else if (overflow == 1) {
|
|
PyErr_Format(PyExc_OverflowError,
|
|
"factorial() argument should not exceed %ld",
|
|
LONG_MAX);
|
|
return NULL;
|
|
}
|
|
else if (overflow == -1 || x < 0) {
|
|
PyErr_SetString(PyExc_ValueError,
|
|
"factorial() not defined for negative values");
|
|
return NULL;
|
|
}
|
|
|
|
/* use lookup table if x is small */
|
|
if (x < (long)Py_ARRAY_LENGTH(SmallFactorials))
|
|
return PyLong_FromUnsignedLong(SmallFactorials[x]);
|
|
|
|
/* else express in the form odd_part * 2**two_valuation, and compute as
|
|
odd_part << two_valuation. */
|
|
odd_part = factorial_odd_part(x);
|
|
if (odd_part == NULL)
|
|
return NULL;
|
|
two_valuation = x - count_set_bits(x);
|
|
result = _PyLong_Lshift(odd_part, two_valuation);
|
|
Py_DECREF(odd_part);
|
|
return result;
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.trunc
|
|
|
|
x: object
|
|
/
|
|
|
|
Truncates the Real x to the nearest Integral toward 0.
|
|
|
|
Uses the __trunc__ magic method.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_trunc(PyObject *module, PyObject *x)
|
|
/*[clinic end generated code: output=34b9697b707e1031 input=2168b34e0a09134d]*/
|
|
{
|
|
_Py_IDENTIFIER(__trunc__);
|
|
PyObject *trunc, *result;
|
|
|
|
if (PyFloat_CheckExact(x)) {
|
|
return PyFloat_Type.tp_as_number->nb_int(x);
|
|
}
|
|
|
|
if (Py_TYPE(x)->tp_dict == NULL) {
|
|
if (PyType_Ready(Py_TYPE(x)) < 0)
|
|
return NULL;
|
|
}
|
|
|
|
trunc = _PyObject_LookupSpecial(x, &PyId___trunc__);
|
|
if (trunc == NULL) {
|
|
if (!PyErr_Occurred())
|
|
PyErr_Format(PyExc_TypeError,
|
|
"type %.100s doesn't define __trunc__ method",
|
|
Py_TYPE(x)->tp_name);
|
|
return NULL;
|
|
}
|
|
result = _PyObject_CallNoArg(trunc);
|
|
Py_DECREF(trunc);
|
|
return result;
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.frexp
|
|
|
|
x: double
|
|
/
|
|
|
|
Return the mantissa and exponent of x, as pair (m, e).
|
|
|
|
m is a float and e is an int, such that x = m * 2.**e.
|
|
If x is 0, m and e are both 0. Else 0.5 <= abs(m) < 1.0.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_frexp_impl(PyObject *module, double x)
|
|
/*[clinic end generated code: output=03e30d252a15ad4a input=96251c9e208bc6e9]*/
|
|
{
|
|
int i;
|
|
/* deal with special cases directly, to sidestep platform
|
|
differences */
|
|
if (Py_IS_NAN(x) || Py_IS_INFINITY(x) || !x) {
|
|
i = 0;
|
|
}
|
|
else {
|
|
x = frexp(x, &i);
|
|
}
|
|
return Py_BuildValue("(di)", x, i);
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.ldexp
|
|
|
|
x: double
|
|
i: object
|
|
/
|
|
|
|
Return x * (2**i).
|
|
|
|
This is essentially the inverse of frexp().
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_ldexp_impl(PyObject *module, double x, PyObject *i)
|
|
/*[clinic end generated code: output=b6892f3c2df9cc6a input=17d5970c1a40a8c1]*/
|
|
{
|
|
double r;
|
|
long exp;
|
|
int overflow;
|
|
|
|
if (PyLong_Check(i)) {
|
|
/* on overflow, replace exponent with either LONG_MAX
|
|
or LONG_MIN, depending on the sign. */
|
|
exp = PyLong_AsLongAndOverflow(i, &overflow);
|
|
if (exp == -1 && PyErr_Occurred())
|
|
return NULL;
|
|
if (overflow)
|
|
exp = overflow < 0 ? LONG_MIN : LONG_MAX;
|
|
}
|
|
else {
|
|
PyErr_SetString(PyExc_TypeError,
|
|
"Expected an int as second argument to ldexp.");
|
|
return NULL;
|
|
}
|
|
|
|
if (x == 0. || !Py_IS_FINITE(x)) {
|
|
/* NaNs, zeros and infinities are returned unchanged */
|
|
r = x;
|
|
errno = 0;
|
|
} else if (exp > INT_MAX) {
|
|
/* overflow */
|
|
r = copysign(Py_HUGE_VAL, x);
|
|
errno = ERANGE;
|
|
} else if (exp < INT_MIN) {
|
|
/* underflow to +-0 */
|
|
r = copysign(0., x);
|
|
errno = 0;
|
|
} else {
|
|
errno = 0;
|
|
r = ldexp(x, (int)exp);
|
|
if (Py_IS_INFINITY(r))
|
|
errno = ERANGE;
|
|
}
|
|
|
|
if (errno && is_error(r))
|
|
return NULL;
|
|
return PyFloat_FromDouble(r);
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.modf
|
|
|
|
x: double
|
|
/
|
|
|
|
Return the fractional and integer parts of x.
|
|
|
|
Both results carry the sign of x and are floats.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_modf_impl(PyObject *module, double x)
|
|
/*[clinic end generated code: output=90cee0260014c3c0 input=b4cfb6786afd9035]*/
|
|
{
|
|
double y;
|
|
/* some platforms don't do the right thing for NaNs and
|
|
infinities, so we take care of special cases directly. */
|
|
if (!Py_IS_FINITE(x)) {
|
|
if (Py_IS_INFINITY(x))
|
|
return Py_BuildValue("(dd)", copysign(0., x), x);
|
|
else if (Py_IS_NAN(x))
|
|
return Py_BuildValue("(dd)", x, x);
|
|
}
|
|
|
|
errno = 0;
|
|
x = modf(x, &y);
|
|
return Py_BuildValue("(dd)", x, y);
|
|
}
|
|
|
|
|
|
/* A decent logarithm is easy to compute even for huge ints, but libm can't
|
|
do that by itself -- loghelper can. func is log or log10, and name is
|
|
"log" or "log10". Note that overflow of the result isn't possible: an int
|
|
can contain no more than INT_MAX * SHIFT bits, so has value certainly less
|
|
than 2**(2**64 * 2**16) == 2**2**80, and log2 of that is 2**80, which is
|
|
small enough to fit in an IEEE single. log and log10 are even smaller.
|
|
However, intermediate overflow is possible for an int if the number of bits
|
|
in that int is larger than PY_SSIZE_T_MAX. */
|
|
|
|
static PyObject*
|
|
loghelper(PyObject* arg, double (*func)(double), const char *funcname)
|
|
{
|
|
/* If it is int, do it ourselves. */
|
|
if (PyLong_Check(arg)) {
|
|
double x, result;
|
|
Py_ssize_t e;
|
|
|
|
/* Negative or zero inputs give a ValueError. */
|
|
if (Py_SIZE(arg) <= 0) {
|
|
PyErr_SetString(PyExc_ValueError,
|
|
"math domain error");
|
|
return NULL;
|
|
}
|
|
|
|
x = PyLong_AsDouble(arg);
|
|
if (x == -1.0 && PyErr_Occurred()) {
|
|
if (!PyErr_ExceptionMatches(PyExc_OverflowError))
|
|
return NULL;
|
|
/* Here the conversion to double overflowed, but it's possible
|
|
to compute the log anyway. Clear the exception and continue. */
|
|
PyErr_Clear();
|
|
x = _PyLong_Frexp((PyLongObject *)arg, &e);
|
|
if (x == -1.0 && PyErr_Occurred())
|
|
return NULL;
|
|
/* Value is ~= x * 2**e, so the log ~= log(x) + log(2) * e. */
|
|
result = func(x) + func(2.0) * e;
|
|
}
|
|
else
|
|
/* Successfully converted x to a double. */
|
|
result = func(x);
|
|
return PyFloat_FromDouble(result);
|
|
}
|
|
|
|
/* Else let libm handle it by itself. */
|
|
return math_1(arg, func, 0);
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.log
|
|
|
|
x: object
|
|
[
|
|
base: object(c_default="NULL") = math.e
|
|
]
|
|
/
|
|
|
|
Return the logarithm of x to the given base.
|
|
|
|
If the base not specified, returns the natural logarithm (base e) of x.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_log_impl(PyObject *module, PyObject *x, int group_right_1,
|
|
PyObject *base)
|
|
/*[clinic end generated code: output=7b5a39e526b73fc9 input=0f62d5726cbfebbd]*/
|
|
{
|
|
PyObject *num, *den;
|
|
PyObject *ans;
|
|
|
|
num = loghelper(x, m_log, "log");
|
|
if (num == NULL || base == NULL)
|
|
return num;
|
|
|
|
den = loghelper(base, m_log, "log");
|
|
if (den == NULL) {
|
|
Py_DECREF(num);
|
|
return NULL;
|
|
}
|
|
|
|
ans = PyNumber_TrueDivide(num, den);
|
|
Py_DECREF(num);
|
|
Py_DECREF(den);
|
|
return ans;
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.log2
|
|
|
|
x: object
|
|
/
|
|
|
|
Return the base 2 logarithm of x.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_log2(PyObject *module, PyObject *x)
|
|
/*[clinic end generated code: output=5425899a4d5d6acb input=08321262bae4f39b]*/
|
|
{
|
|
return loghelper(x, m_log2, "log2");
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.log10
|
|
|
|
x: object
|
|
/
|
|
|
|
Return the base 10 logarithm of x.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_log10(PyObject *module, PyObject *x)
|
|
/*[clinic end generated code: output=be72a64617df9c6f input=b2469d02c6469e53]*/
|
|
{
|
|
return loghelper(x, m_log10, "log10");
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.fmod
|
|
|
|
x: double
|
|
y: double
|
|
/
|
|
|
|
Return fmod(x, y), according to platform C.
|
|
|
|
x % y may differ.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_fmod_impl(PyObject *module, double x, double y)
|
|
/*[clinic end generated code: output=7559d794343a27b5 input=4f84caa8cfc26a03]*/
|
|
{
|
|
double r;
|
|
/* fmod(x, +/-Inf) returns x for finite x. */
|
|
if (Py_IS_INFINITY(y) && Py_IS_FINITE(x))
|
|
return PyFloat_FromDouble(x);
|
|
errno = 0;
|
|
r = fmod(x, y);
|
|
if (Py_IS_NAN(r)) {
|
|
if (!Py_IS_NAN(x) && !Py_IS_NAN(y))
|
|
errno = EDOM;
|
|
else
|
|
errno = 0;
|
|
}
|
|
if (errno && is_error(r))
|
|
return NULL;
|
|
else
|
|
return PyFloat_FromDouble(r);
|
|
}
|
|
|
|
/*
|
|
Given an *n* length *vec* of values and a value *max*, compute:
|
|
|
|
max * sqrt(sum((x / max) ** 2 for x in vec))
|
|
|
|
The value of the *max* variable must be non-negative and
|
|
equal to the absolute value of the largest magnitude
|
|
entry in the vector. If n==0, then *max* should be 0.0.
|
|
If an infinity is present in the vec, *max* should be INF.
|
|
|
|
The *found_nan* variable indicates whether some member of
|
|
the *vec* is a NaN.
|
|
|
|
To improve accuracy and to increase the number of cases where
|
|
vector_norm() is commutative, we use a variant of Neumaier
|
|
summation specialized to exploit that we always know that
|
|
|csum| >= |x|.
|
|
|
|
The *csum* variable tracks the cumulative sum and *frac* tracks
|
|
the cumulative fractional errors at each step. Since this
|
|
variant assumes that |csum| >= |x| at each step, we establish
|
|
the precondition by starting the accumulation from 1.0 which
|
|
represents the largest possible value of (x/max)**2.
|
|
|
|
After the loop is finished, the initial 1.0 is subtracted out
|
|
for a net zero effect on the final sum. Since *csum* will be
|
|
greater than 1.0, the subtraction of 1.0 will not cause
|
|
fractional digits to be dropped from *csum*.
|
|
|
|
*/
|
|
|
|
static inline double
|
|
vector_norm(Py_ssize_t n, double *vec, double max, int found_nan)
|
|
{
|
|
double x, csum = 1.0, oldcsum, frac = 0.0;
|
|
Py_ssize_t i;
|
|
|
|
if (Py_IS_INFINITY(max)) {
|
|
return max;
|
|
}
|
|
if (found_nan) {
|
|
return Py_NAN;
|
|
}
|
|
if (max == 0.0 || n <= 1) {
|
|
return max;
|
|
}
|
|
for (i=0 ; i < n ; i++) {
|
|
x = vec[i];
|
|
assert(Py_IS_FINITE(x) && fabs(x) <= max);
|
|
x /= max;
|
|
x = x*x;
|
|
oldcsum = csum;
|
|
csum += x;
|
|
assert(csum >= x);
|
|
frac += (oldcsum - csum) + x;
|
|
}
|
|
return max * sqrt(csum - 1.0 + frac);
|
|
}
|
|
|
|
#define NUM_STACK_ELEMS 16
|
|
|
|
/*[clinic input]
|
|
math.dist
|
|
|
|
p: object
|
|
q: object
|
|
/
|
|
|
|
Return the Euclidean distance between two points p and q.
|
|
|
|
The points should be specified as sequences (or iterables) of
|
|
coordinates. Both inputs must have the same dimension.
|
|
|
|
Roughly equivalent to:
|
|
sqrt(sum((px - qx) ** 2.0 for px, qx in zip(p, q)))
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_dist_impl(PyObject *module, PyObject *p, PyObject *q)
|
|
/*[clinic end generated code: output=56bd9538d06bbcfe input=74e85e1b6092e68e]*/
|
|
{
|
|
PyObject *item;
|
|
double max = 0.0;
|
|
double x, px, qx, result;
|
|
Py_ssize_t i, m, n;
|
|
int found_nan = 0, p_allocated = 0, q_allocated = 0;
|
|
double diffs_on_stack[NUM_STACK_ELEMS];
|
|
double *diffs = diffs_on_stack;
|
|
|
|
if (!PyTuple_Check(p)) {
|
|
p = PySequence_Tuple(p);
|
|
if (p == NULL) {
|
|
return NULL;
|
|
}
|
|
p_allocated = 1;
|
|
}
|
|
if (!PyTuple_Check(q)) {
|
|
q = PySequence_Tuple(q);
|
|
if (q == NULL) {
|
|
if (p_allocated) {
|
|
Py_DECREF(p);
|
|
}
|
|
return NULL;
|
|
}
|
|
q_allocated = 1;
|
|
}
|
|
|
|
m = PyTuple_GET_SIZE(p);
|
|
n = PyTuple_GET_SIZE(q);
|
|
if (m != n) {
|
|
PyErr_SetString(PyExc_ValueError,
|
|
"both points must have the same number of dimensions");
|
|
return NULL;
|
|
|
|
}
|
|
if (n > NUM_STACK_ELEMS) {
|
|
diffs = (double *) PyObject_Malloc(n * sizeof(double));
|
|
if (diffs == NULL) {
|
|
return PyErr_NoMemory();
|
|
}
|
|
}
|
|
for (i=0 ; i<n ; i++) {
|
|
item = PyTuple_GET_ITEM(p, i);
|
|
ASSIGN_DOUBLE(px, item, error_exit);
|
|
item = PyTuple_GET_ITEM(q, i);
|
|
ASSIGN_DOUBLE(qx, item, error_exit);
|
|
x = fabs(px - qx);
|
|
diffs[i] = x;
|
|
found_nan |= Py_IS_NAN(x);
|
|
if (x > max) {
|
|
max = x;
|
|
}
|
|
}
|
|
result = vector_norm(n, diffs, max, found_nan);
|
|
if (diffs != diffs_on_stack) {
|
|
PyObject_Free(diffs);
|
|
}
|
|
if (p_allocated) {
|
|
Py_DECREF(p);
|
|
}
|
|
if (q_allocated) {
|
|
Py_DECREF(q);
|
|
}
|
|
return PyFloat_FromDouble(result);
|
|
|
|
error_exit:
|
|
if (diffs != diffs_on_stack) {
|
|
PyObject_Free(diffs);
|
|
}
|
|
if (p_allocated) {
|
|
Py_DECREF(p);
|
|
}
|
|
if (q_allocated) {
|
|
Py_DECREF(q);
|
|
}
|
|
return NULL;
|
|
}
|
|
|
|
/* AC: cannot convert yet, waiting for *args support */
|
|
static PyObject *
|
|
math_hypot(PyObject *self, PyObject *const *args, Py_ssize_t nargs)
|
|
{
|
|
Py_ssize_t i;
|
|
PyObject *item;
|
|
double max = 0.0;
|
|
double x, result;
|
|
int found_nan = 0;
|
|
double coord_on_stack[NUM_STACK_ELEMS];
|
|
double *coordinates = coord_on_stack;
|
|
|
|
if (nargs > NUM_STACK_ELEMS) {
|
|
coordinates = (double *) PyObject_Malloc(nargs * sizeof(double));
|
|
if (coordinates == NULL) {
|
|
return PyErr_NoMemory();
|
|
}
|
|
}
|
|
for (i = 0; i < nargs; i++) {
|
|
item = args[i];
|
|
ASSIGN_DOUBLE(x, item, error_exit);
|
|
x = fabs(x);
|
|
coordinates[i] = x;
|
|
found_nan |= Py_IS_NAN(x);
|
|
if (x > max) {
|
|
max = x;
|
|
}
|
|
}
|
|
result = vector_norm(nargs, coordinates, max, found_nan);
|
|
if (coordinates != coord_on_stack) {
|
|
PyObject_Free(coordinates);
|
|
}
|
|
return PyFloat_FromDouble(result);
|
|
|
|
error_exit:
|
|
if (coordinates != coord_on_stack) {
|
|
PyObject_Free(coordinates);
|
|
}
|
|
return NULL;
|
|
}
|
|
|
|
#undef NUM_STACK_ELEMS
|
|
|
|
PyDoc_STRVAR(math_hypot_doc,
|
|
"hypot(*coordinates) -> value\n\n\
|
|
Multidimensional Euclidean distance from the origin to a point.\n\
|
|
\n\
|
|
Roughly equivalent to:\n\
|
|
sqrt(sum(x**2 for x in coordinates))\n\
|
|
\n\
|
|
For a two dimensional point (x, y), gives the hypotenuse\n\
|
|
using the Pythagorean theorem: sqrt(x*x + y*y).\n\
|
|
\n\
|
|
For example, the hypotenuse of a 3/4/5 right triangle is:\n\
|
|
\n\
|
|
>>> hypot(3.0, 4.0)\n\
|
|
5.0\n\
|
|
");
|
|
|
|
/* pow can't use math_2, but needs its own wrapper: the problem is
|
|
that an infinite result can arise either as a result of overflow
|
|
(in which case OverflowError should be raised) or as a result of
|
|
e.g. 0.**-5. (for which ValueError needs to be raised.)
|
|
*/
|
|
|
|
/*[clinic input]
|
|
math.pow
|
|
|
|
x: double
|
|
y: double
|
|
/
|
|
|
|
Return x**y (x to the power of y).
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_pow_impl(PyObject *module, double x, double y)
|
|
/*[clinic end generated code: output=fff93e65abccd6b0 input=c26f1f6075088bfd]*/
|
|
{
|
|
double r;
|
|
int odd_y;
|
|
|
|
/* deal directly with IEEE specials, to cope with problems on various
|
|
platforms whose semantics don't exactly match C99 */
|
|
r = 0.; /* silence compiler warning */
|
|
if (!Py_IS_FINITE(x) || !Py_IS_FINITE(y)) {
|
|
errno = 0;
|
|
if (Py_IS_NAN(x))
|
|
r = y == 0. ? 1. : x; /* NaN**0 = 1 */
|
|
else if (Py_IS_NAN(y))
|
|
r = x == 1. ? 1. : y; /* 1**NaN = 1 */
|
|
else if (Py_IS_INFINITY(x)) {
|
|
odd_y = Py_IS_FINITE(y) && fmod(fabs(y), 2.0) == 1.0;
|
|
if (y > 0.)
|
|
r = odd_y ? x : fabs(x);
|
|
else if (y == 0.)
|
|
r = 1.;
|
|
else /* y < 0. */
|
|
r = odd_y ? copysign(0., x) : 0.;
|
|
}
|
|
else if (Py_IS_INFINITY(y)) {
|
|
if (fabs(x) == 1.0)
|
|
r = 1.;
|
|
else if (y > 0. && fabs(x) > 1.0)
|
|
r = y;
|
|
else if (y < 0. && fabs(x) < 1.0) {
|
|
r = -y; /* result is +inf */
|
|
if (x == 0.) /* 0**-inf: divide-by-zero */
|
|
errno = EDOM;
|
|
}
|
|
else
|
|
r = 0.;
|
|
}
|
|
}
|
|
else {
|
|
/* let libm handle finite**finite */
|
|
errno = 0;
|
|
r = pow(x, y);
|
|
/* a NaN result should arise only from (-ve)**(finite
|
|
non-integer); in this case we want to raise ValueError. */
|
|
if (!Py_IS_FINITE(r)) {
|
|
if (Py_IS_NAN(r)) {
|
|
errno = EDOM;
|
|
}
|
|
/*
|
|
an infinite result here arises either from:
|
|
(A) (+/-0.)**negative (-> divide-by-zero)
|
|
(B) overflow of x**y with x and y finite
|
|
*/
|
|
else if (Py_IS_INFINITY(r)) {
|
|
if (x == 0.)
|
|
errno = EDOM;
|
|
else
|
|
errno = ERANGE;
|
|
}
|
|
}
|
|
}
|
|
|
|
if (errno && is_error(r))
|
|
return NULL;
|
|
else
|
|
return PyFloat_FromDouble(r);
|
|
}
|
|
|
|
|
|
static const double degToRad = Py_MATH_PI / 180.0;
|
|
static const double radToDeg = 180.0 / Py_MATH_PI;
|
|
|
|
/*[clinic input]
|
|
math.degrees
|
|
|
|
x: double
|
|
/
|
|
|
|
Convert angle x from radians to degrees.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_degrees_impl(PyObject *module, double x)
|
|
/*[clinic end generated code: output=7fea78b294acd12f input=81e016555d6e3660]*/
|
|
{
|
|
return PyFloat_FromDouble(x * radToDeg);
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.radians
|
|
|
|
x: double
|
|
/
|
|
|
|
Convert angle x from degrees to radians.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_radians_impl(PyObject *module, double x)
|
|
/*[clinic end generated code: output=34daa47caf9b1590 input=91626fc489fe3d63]*/
|
|
{
|
|
return PyFloat_FromDouble(x * degToRad);
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.isfinite
|
|
|
|
x: double
|
|
/
|
|
|
|
Return True if x is neither an infinity nor a NaN, and False otherwise.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_isfinite_impl(PyObject *module, double x)
|
|
/*[clinic end generated code: output=8ba1f396440c9901 input=46967d254812e54a]*/
|
|
{
|
|
return PyBool_FromLong((long)Py_IS_FINITE(x));
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.isnan
|
|
|
|
x: double
|
|
/
|
|
|
|
Return True if x is a NaN (not a number), and False otherwise.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_isnan_impl(PyObject *module, double x)
|
|
/*[clinic end generated code: output=f537b4d6df878c3e input=935891e66083f46a]*/
|
|
{
|
|
return PyBool_FromLong((long)Py_IS_NAN(x));
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.isinf
|
|
|
|
x: double
|
|
/
|
|
|
|
Return True if x is a positive or negative infinity, and False otherwise.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_isinf_impl(PyObject *module, double x)
|
|
/*[clinic end generated code: output=9f00cbec4de7b06b input=32630e4212cf961f]*/
|
|
{
|
|
return PyBool_FromLong((long)Py_IS_INFINITY(x));
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.isclose -> bool
|
|
|
|
a: double
|
|
b: double
|
|
*
|
|
rel_tol: double = 1e-09
|
|
maximum difference for being considered "close", relative to the
|
|
magnitude of the input values
|
|
abs_tol: double = 0.0
|
|
maximum difference for being considered "close", regardless of the
|
|
magnitude of the input values
|
|
|
|
Determine whether two floating point numbers are close in value.
|
|
|
|
Return True if a is close in value to b, and False otherwise.
|
|
|
|
For the values to be considered close, the difference between them
|
|
must be smaller than at least one of the tolerances.
|
|
|
|
-inf, inf and NaN behave similarly to the IEEE 754 Standard. That
|
|
is, NaN is not close to anything, even itself. inf and -inf are
|
|
only close to themselves.
|
|
[clinic start generated code]*/
|
|
|
|
static int
|
|
math_isclose_impl(PyObject *module, double a, double b, double rel_tol,
|
|
double abs_tol)
|
|
/*[clinic end generated code: output=b73070207511952d input=f28671871ea5bfba]*/
|
|
{
|
|
double diff = 0.0;
|
|
|
|
/* sanity check on the inputs */
|
|
if (rel_tol < 0.0 || abs_tol < 0.0 ) {
|
|
PyErr_SetString(PyExc_ValueError,
|
|
"tolerances must be non-negative");
|
|
return -1;
|
|
}
|
|
|
|
if ( a == b ) {
|
|
/* short circuit exact equality -- needed to catch two infinities of
|
|
the same sign. And perhaps speeds things up a bit sometimes.
|
|
*/
|
|
return 1;
|
|
}
|
|
|
|
/* This catches the case of two infinities of opposite sign, or
|
|
one infinity and one finite number. Two infinities of opposite
|
|
sign would otherwise have an infinite relative tolerance.
|
|
Two infinities of the same sign are caught by the equality check
|
|
above.
|
|
*/
|
|
|
|
if (Py_IS_INFINITY(a) || Py_IS_INFINITY(b)) {
|
|
return 0;
|
|
}
|
|
|
|
/* now do the regular computation
|
|
this is essentially the "weak" test from the Boost library
|
|
*/
|
|
|
|
diff = fabs(b - a);
|
|
|
|
return (((diff <= fabs(rel_tol * b)) ||
|
|
(diff <= fabs(rel_tol * a))) ||
|
|
(diff <= abs_tol));
|
|
}
|
|
|
|
static inline int
|
|
_check_long_mult_overflow(long a, long b) {
|
|
|
|
/* From Python2's int_mul code:
|
|
|
|
Integer overflow checking for * is painful: Python tried a couple ways, but
|
|
they didn't work on all platforms, or failed in endcases (a product of
|
|
-sys.maxint-1 has been a particular pain).
|
|
|
|
Here's another way:
|
|
|
|
The native long product x*y is either exactly right or *way* off, being
|
|
just the last n bits of the true product, where n is the number of bits
|
|
in a long (the delivered product is the true product plus i*2**n for
|
|
some integer i).
|
|
|
|
The native double product (double)x * (double)y is subject to three
|
|
rounding errors: on a sizeof(long)==8 box, each cast to double can lose
|
|
info, and even on a sizeof(long)==4 box, the multiplication can lose info.
|
|
But, unlike the native long product, it's not in *range* trouble: even
|
|
if sizeof(long)==32 (256-bit longs), the product easily fits in the
|
|
dynamic range of a double. So the leading 50 (or so) bits of the double
|
|
product are correct.
|
|
|
|
We check these two ways against each other, and declare victory if they're
|
|
approximately the same. Else, because the native long product is the only
|
|
one that can lose catastrophic amounts of information, it's the native long
|
|
product that must have overflowed.
|
|
|
|
*/
|
|
|
|
long longprod = (long)((unsigned long)a * b);
|
|
double doubleprod = (double)a * (double)b;
|
|
double doubled_longprod = (double)longprod;
|
|
|
|
if (doubled_longprod == doubleprod) {
|
|
return 0;
|
|
}
|
|
|
|
const double diff = doubled_longprod - doubleprod;
|
|
const double absdiff = diff >= 0.0 ? diff : -diff;
|
|
const double absprod = doubleprod >= 0.0 ? doubleprod : -doubleprod;
|
|
|
|
if (32.0 * absdiff <= absprod) {
|
|
return 0;
|
|
}
|
|
|
|
return 1;
|
|
}
|
|
|
|
/*[clinic input]
|
|
math.prod
|
|
|
|
iterable: object
|
|
/
|
|
*
|
|
start: object(c_default="NULL") = 1
|
|
|
|
Calculate the product of all the elements in the input iterable.
|
|
|
|
The default start value for the product is 1.
|
|
|
|
When the iterable is empty, return the start value. This function is
|
|
intended specifically for use with numeric values and may reject
|
|
non-numeric types.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_prod_impl(PyObject *module, PyObject *iterable, PyObject *start)
|
|
/*[clinic end generated code: output=36153bedac74a198 input=4c5ab0682782ed54]*/
|
|
{
|
|
PyObject *result = start;
|
|
PyObject *temp, *item, *iter;
|
|
|
|
iter = PyObject_GetIter(iterable);
|
|
if (iter == NULL) {
|
|
return NULL;
|
|
}
|
|
|
|
if (result == NULL) {
|
|
result = PyLong_FromLong(1);
|
|
if (result == NULL) {
|
|
Py_DECREF(iter);
|
|
return NULL;
|
|
}
|
|
} else {
|
|
Py_INCREF(result);
|
|
}
|
|
#ifndef SLOW_PROD
|
|
/* Fast paths for integers keeping temporary products in C.
|
|
* Assumes all inputs are the same type.
|
|
* If the assumption fails, default to use PyObjects instead.
|
|
*/
|
|
if (PyLong_CheckExact(result)) {
|
|
int overflow;
|
|
long i_result = PyLong_AsLongAndOverflow(result, &overflow);
|
|
/* If this already overflowed, don't even enter the loop. */
|
|
if (overflow == 0) {
|
|
Py_DECREF(result);
|
|
result = NULL;
|
|
}
|
|
/* Loop over all the items in the iterable until we finish, we overflow
|
|
* or we found a non integer element */
|
|
while(result == NULL) {
|
|
item = PyIter_Next(iter);
|
|
if (item == NULL) {
|
|
Py_DECREF(iter);
|
|
if (PyErr_Occurred()) {
|
|
return NULL;
|
|
}
|
|
return PyLong_FromLong(i_result);
|
|
}
|
|
if (PyLong_CheckExact(item)) {
|
|
long b = PyLong_AsLongAndOverflow(item, &overflow);
|
|
if (overflow == 0 && !_check_long_mult_overflow(i_result, b)) {
|
|
long x = i_result * b;
|
|
i_result = x;
|
|
Py_DECREF(item);
|
|
continue;
|
|
}
|
|
}
|
|
/* Either overflowed or is not an int.
|
|
* Restore real objects and process normally */
|
|
result = PyLong_FromLong(i_result);
|
|
if (result == NULL) {
|
|
Py_DECREF(item);
|
|
Py_DECREF(iter);
|
|
return NULL;
|
|
}
|
|
temp = PyNumber_Multiply(result, item);
|
|
Py_DECREF(result);
|
|
Py_DECREF(item);
|
|
result = temp;
|
|
if (result == NULL) {
|
|
Py_DECREF(iter);
|
|
return NULL;
|
|
}
|
|
}
|
|
}
|
|
|
|
/* Fast paths for floats keeping temporary products in C.
|
|
* Assumes all inputs are the same type.
|
|
* If the assumption fails, default to use PyObjects instead.
|
|
*/
|
|
if (PyFloat_CheckExact(result)) {
|
|
double f_result = PyFloat_AS_DOUBLE(result);
|
|
Py_DECREF(result);
|
|
result = NULL;
|
|
while(result == NULL) {
|
|
item = PyIter_Next(iter);
|
|
if (item == NULL) {
|
|
Py_DECREF(iter);
|
|
if (PyErr_Occurred()) {
|
|
return NULL;
|
|
}
|
|
return PyFloat_FromDouble(f_result);
|
|
}
|
|
if (PyFloat_CheckExact(item)) {
|
|
f_result *= PyFloat_AS_DOUBLE(item);
|
|
Py_DECREF(item);
|
|
continue;
|
|
}
|
|
if (PyLong_CheckExact(item)) {
|
|
long value;
|
|
int overflow;
|
|
value = PyLong_AsLongAndOverflow(item, &overflow);
|
|
if (!overflow) {
|
|
f_result *= (double)value;
|
|
Py_DECREF(item);
|
|
continue;
|
|
}
|
|
}
|
|
result = PyFloat_FromDouble(f_result);
|
|
if (result == NULL) {
|
|
Py_DECREF(item);
|
|
Py_DECREF(iter);
|
|
return NULL;
|
|
}
|
|
temp = PyNumber_Multiply(result, item);
|
|
Py_DECREF(result);
|
|
Py_DECREF(item);
|
|
result = temp;
|
|
if (result == NULL) {
|
|
Py_DECREF(iter);
|
|
return NULL;
|
|
}
|
|
}
|
|
}
|
|
#endif
|
|
/* Consume rest of the iterable (if any) that could not be handled
|
|
* by specialized functions above.*/
|
|
for(;;) {
|
|
item = PyIter_Next(iter);
|
|
if (item == NULL) {
|
|
/* error, or end-of-sequence */
|
|
if (PyErr_Occurred()) {
|
|
Py_DECREF(result);
|
|
result = NULL;
|
|
}
|
|
break;
|
|
}
|
|
temp = PyNumber_Multiply(result, item);
|
|
Py_DECREF(result);
|
|
Py_DECREF(item);
|
|
result = temp;
|
|
if (result == NULL)
|
|
break;
|
|
}
|
|
Py_DECREF(iter);
|
|
return result;
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.perm
|
|
|
|
n: object
|
|
k: object = None
|
|
/
|
|
|
|
Number of ways to choose k items from n items without repetition and with order.
|
|
|
|
Evaluates to n! / (n - k)! when k <= n and evaluates
|
|
to zero when k > n.
|
|
|
|
If k is not specified or is None, then k defaults to n
|
|
and the function returns n!.
|
|
|
|
Raises TypeError if either of the arguments are not integers.
|
|
Raises ValueError if either of the arguments are negative.
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_perm_impl(PyObject *module, PyObject *n, PyObject *k)
|
|
/*[clinic end generated code: output=e021a25469653e23 input=5311c5a00f359b53]*/
|
|
{
|
|
PyObject *result = NULL, *factor = NULL;
|
|
int overflow, cmp;
|
|
long long i, factors;
|
|
|
|
if (k == Py_None) {
|
|
return math_factorial(module, n);
|
|
}
|
|
n = PyNumber_Index(n);
|
|
if (n == NULL) {
|
|
return NULL;
|
|
}
|
|
if (!PyLong_CheckExact(n)) {
|
|
Py_SETREF(n, _PyLong_Copy((PyLongObject *)n));
|
|
if (n == NULL) {
|
|
return NULL;
|
|
}
|
|
}
|
|
k = PyNumber_Index(k);
|
|
if (k == NULL) {
|
|
Py_DECREF(n);
|
|
return NULL;
|
|
}
|
|
if (!PyLong_CheckExact(k)) {
|
|
Py_SETREF(k, _PyLong_Copy((PyLongObject *)k));
|
|
if (k == NULL) {
|
|
Py_DECREF(n);
|
|
return NULL;
|
|
}
|
|
}
|
|
|
|
if (Py_SIZE(n) < 0) {
|
|
PyErr_SetString(PyExc_ValueError,
|
|
"n must be a non-negative integer");
|
|
goto error;
|
|
}
|
|
if (Py_SIZE(k) < 0) {
|
|
PyErr_SetString(PyExc_ValueError,
|
|
"k must be a non-negative integer");
|
|
goto error;
|
|
}
|
|
|
|
cmp = PyObject_RichCompareBool(n, k, Py_LT);
|
|
if (cmp != 0) {
|
|
if (cmp > 0) {
|
|
result = PyLong_FromLong(0);
|
|
goto done;
|
|
}
|
|
goto error;
|
|
}
|
|
|
|
factors = PyLong_AsLongLongAndOverflow(k, &overflow);
|
|
if (overflow > 0) {
|
|
PyErr_Format(PyExc_OverflowError,
|
|
"k must not exceed %lld",
|
|
LLONG_MAX);
|
|
goto error;
|
|
}
|
|
else if (factors == -1) {
|
|
/* k is nonnegative, so a return value of -1 can only indicate error */
|
|
goto error;
|
|
}
|
|
|
|
if (factors == 0) {
|
|
result = PyLong_FromLong(1);
|
|
goto done;
|
|
}
|
|
|
|
result = n;
|
|
Py_INCREF(result);
|
|
if (factors == 1) {
|
|
goto done;
|
|
}
|
|
|
|
factor = n;
|
|
Py_INCREF(factor);
|
|
for (i = 1; i < factors; ++i) {
|
|
Py_SETREF(factor, PyNumber_Subtract(factor, _PyLong_One));
|
|
if (factor == NULL) {
|
|
goto error;
|
|
}
|
|
Py_SETREF(result, PyNumber_Multiply(result, factor));
|
|
if (result == NULL) {
|
|
goto error;
|
|
}
|
|
}
|
|
Py_DECREF(factor);
|
|
|
|
done:
|
|
Py_DECREF(n);
|
|
Py_DECREF(k);
|
|
return result;
|
|
|
|
error:
|
|
Py_XDECREF(factor);
|
|
Py_XDECREF(result);
|
|
Py_DECREF(n);
|
|
Py_DECREF(k);
|
|
return NULL;
|
|
}
|
|
|
|
|
|
/*[clinic input]
|
|
math.comb
|
|
|
|
n: object
|
|
k: object
|
|
/
|
|
|
|
Number of ways to choose k items from n items without repetition and without order.
|
|
|
|
Evaluates to n! / (k! * (n - k)!) when k <= n and evaluates
|
|
to zero when k > n.
|
|
|
|
Also called the binomial coefficient because it is equivalent
|
|
to the coefficient of k-th term in polynomial expansion of the
|
|
expression (1 + x)**n.
|
|
|
|
Raises TypeError if either of the arguments are not integers.
|
|
Raises ValueError if either of the arguments are negative.
|
|
|
|
[clinic start generated code]*/
|
|
|
|
static PyObject *
|
|
math_comb_impl(PyObject *module, PyObject *n, PyObject *k)
|
|
/*[clinic end generated code: output=bd2cec8d854f3493 input=9a05315af2518709]*/
|
|
{
|
|
PyObject *result = NULL, *factor = NULL, *temp;
|
|
int overflow, cmp;
|
|
long long i, factors;
|
|
|
|
n = PyNumber_Index(n);
|
|
if (n == NULL) {
|
|
return NULL;
|
|
}
|
|
if (!PyLong_CheckExact(n)) {
|
|
Py_SETREF(n, _PyLong_Copy((PyLongObject *)n));
|
|
if (n == NULL) {
|
|
return NULL;
|
|
}
|
|
}
|
|
k = PyNumber_Index(k);
|
|
if (k == NULL) {
|
|
Py_DECREF(n);
|
|
return NULL;
|
|
}
|
|
if (!PyLong_CheckExact(k)) {
|
|
Py_SETREF(k, _PyLong_Copy((PyLongObject *)k));
|
|
if (k == NULL) {
|
|
Py_DECREF(n);
|
|
return NULL;
|
|
}
|
|
}
|
|
|
|
if (Py_SIZE(n) < 0) {
|
|
PyErr_SetString(PyExc_ValueError,
|
|
"n must be a non-negative integer");
|
|
goto error;
|
|
}
|
|
if (Py_SIZE(k) < 0) {
|
|
PyErr_SetString(PyExc_ValueError,
|
|
"k must be a non-negative integer");
|
|
goto error;
|
|
}
|
|
|
|
/* k = min(k, n - k) */
|
|
temp = PyNumber_Subtract(n, k);
|
|
if (temp == NULL) {
|
|
goto error;
|
|
}
|
|
if (Py_SIZE(temp) < 0) {
|
|
Py_DECREF(temp);
|
|
result = PyLong_FromLong(0);
|
|
goto done;
|
|
}
|
|
cmp = PyObject_RichCompareBool(temp, k, Py_LT);
|
|
if (cmp > 0) {
|
|
Py_SETREF(k, temp);
|
|
}
|
|
else {
|
|
Py_DECREF(temp);
|
|
if (cmp < 0) {
|
|
goto error;
|
|
}
|
|
}
|
|
|
|
factors = PyLong_AsLongLongAndOverflow(k, &overflow);
|
|
if (overflow > 0) {
|
|
PyErr_Format(PyExc_OverflowError,
|
|
"min(n - k, k) must not exceed %lld",
|
|
LLONG_MAX);
|
|
goto error;
|
|
}
|
|
if (factors == -1) {
|
|
/* k is nonnegative, so a return value of -1 can only indicate error */
|
|
goto error;
|
|
}
|
|
|
|
if (factors == 0) {
|
|
result = PyLong_FromLong(1);
|
|
goto done;
|
|
}
|
|
|
|
result = n;
|
|
Py_INCREF(result);
|
|
if (factors == 1) {
|
|
goto done;
|
|
}
|
|
|
|
factor = n;
|
|
Py_INCREF(factor);
|
|
for (i = 1; i < factors; ++i) {
|
|
Py_SETREF(factor, PyNumber_Subtract(factor, _PyLong_One));
|
|
if (factor == NULL) {
|
|
goto error;
|
|
}
|
|
Py_SETREF(result, PyNumber_Multiply(result, factor));
|
|
if (result == NULL) {
|
|
goto error;
|
|
}
|
|
|
|
temp = PyLong_FromUnsignedLongLong((unsigned long long)i + 1);
|
|
if (temp == NULL) {
|
|
goto error;
|
|
}
|
|
Py_SETREF(result, PyNumber_FloorDivide(result, temp));
|
|
Py_DECREF(temp);
|
|
if (result == NULL) {
|
|
goto error;
|
|
}
|
|
}
|
|
Py_DECREF(factor);
|
|
|
|
done:
|
|
Py_DECREF(n);
|
|
Py_DECREF(k);
|
|
return result;
|
|
|
|
error:
|
|
Py_XDECREF(factor);
|
|
Py_XDECREF(result);
|
|
Py_DECREF(n);
|
|
Py_DECREF(k);
|
|
return NULL;
|
|
}
|
|
|
|
|
|
static PyMethodDef math_methods[] = {
|
|
{"acos", math_acos, METH_O, math_acos_doc},
|
|
{"acosh", math_acosh, METH_O, math_acosh_doc},
|
|
{"asin", math_asin, METH_O, math_asin_doc},
|
|
{"asinh", math_asinh, METH_O, math_asinh_doc},
|
|
{"atan", math_atan, METH_O, math_atan_doc},
|
|
{"atan2", (PyCFunction)(void(*)(void))math_atan2, METH_FASTCALL, math_atan2_doc},
|
|
{"atanh", math_atanh, METH_O, math_atanh_doc},
|
|
MATH_CEIL_METHODDEF
|
|
{"copysign", (PyCFunction)(void(*)(void))math_copysign, METH_FASTCALL, math_copysign_doc},
|
|
{"cos", math_cos, METH_O, math_cos_doc},
|
|
{"cosh", math_cosh, METH_O, math_cosh_doc},
|
|
MATH_DEGREES_METHODDEF
|
|
MATH_DIST_METHODDEF
|
|
{"erf", math_erf, METH_O, math_erf_doc},
|
|
{"erfc", math_erfc, METH_O, math_erfc_doc},
|
|
{"exp", math_exp, METH_O, math_exp_doc},
|
|
{"expm1", math_expm1, METH_O, math_expm1_doc},
|
|
{"fabs", math_fabs, METH_O, math_fabs_doc},
|
|
MATH_FACTORIAL_METHODDEF
|
|
MATH_FLOOR_METHODDEF
|
|
MATH_FMOD_METHODDEF
|
|
MATH_FREXP_METHODDEF
|
|
MATH_FSUM_METHODDEF
|
|
{"gamma", math_gamma, METH_O, math_gamma_doc},
|
|
MATH_GCD_METHODDEF
|
|
{"hypot", (PyCFunction)(void(*)(void))math_hypot, METH_FASTCALL, math_hypot_doc},
|
|
MATH_ISCLOSE_METHODDEF
|
|
MATH_ISFINITE_METHODDEF
|
|
MATH_ISINF_METHODDEF
|
|
MATH_ISNAN_METHODDEF
|
|
MATH_ISQRT_METHODDEF
|
|
MATH_LDEXP_METHODDEF
|
|
{"lgamma", math_lgamma, METH_O, math_lgamma_doc},
|
|
MATH_LOG_METHODDEF
|
|
{"log1p", math_log1p, METH_O, math_log1p_doc},
|
|
MATH_LOG10_METHODDEF
|
|
MATH_LOG2_METHODDEF
|
|
MATH_MODF_METHODDEF
|
|
MATH_POW_METHODDEF
|
|
MATH_RADIANS_METHODDEF
|
|
{"remainder", (PyCFunction)(void(*)(void))math_remainder, METH_FASTCALL, math_remainder_doc},
|
|
{"sin", math_sin, METH_O, math_sin_doc},
|
|
{"sinh", math_sinh, METH_O, math_sinh_doc},
|
|
{"sqrt", math_sqrt, METH_O, math_sqrt_doc},
|
|
{"tan", math_tan, METH_O, math_tan_doc},
|
|
{"tanh", math_tanh, METH_O, math_tanh_doc},
|
|
MATH_TRUNC_METHODDEF
|
|
MATH_PROD_METHODDEF
|
|
MATH_PERM_METHODDEF
|
|
MATH_COMB_METHODDEF
|
|
{NULL, NULL} /* sentinel */
|
|
};
|
|
|
|
|
|
PyDoc_STRVAR(module_doc,
|
|
"This module provides access to the mathematical functions\n"
|
|
"defined by the C standard.");
|
|
|
|
|
|
static struct PyModuleDef mathmodule = {
|
|
PyModuleDef_HEAD_INIT,
|
|
"math",
|
|
module_doc,
|
|
-1,
|
|
math_methods,
|
|
NULL,
|
|
NULL,
|
|
NULL,
|
|
NULL
|
|
};
|
|
|
|
PyMODINIT_FUNC
|
|
PyInit_math(void)
|
|
{
|
|
PyObject *m;
|
|
|
|
m = PyModule_Create(&mathmodule);
|
|
if (m == NULL)
|
|
goto finally;
|
|
|
|
PyModule_AddObject(m, "pi", PyFloat_FromDouble(Py_MATH_PI));
|
|
PyModule_AddObject(m, "e", PyFloat_FromDouble(Py_MATH_E));
|
|
PyModule_AddObject(m, "tau", PyFloat_FromDouble(Py_MATH_TAU)); /* 2pi */
|
|
PyModule_AddObject(m, "inf", PyFloat_FromDouble(m_inf()));
|
|
#if !defined(PY_NO_SHORT_FLOAT_REPR) || defined(Py_NAN)
|
|
PyModule_AddObject(m, "nan", PyFloat_FromDouble(m_nan()));
|
|
#endif
|
|
|
|
finally:
|
|
return m;
|
|
}
|