bpo-42450: Minor updates to the itertools recipes (GH-23555)
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@ -755,7 +755,7 @@ which incur interpreter overhead.
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"Count how many times the predicate is true"
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return sum(map(pred, iterable))
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def padnone(iterable):
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def pad_none(iterable):
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"""Returns the sequence elements and then returns None indefinitely.
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Useful for emulating the behavior of the built-in map() function.
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@ -809,7 +809,7 @@ which incur interpreter overhead.
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nexts = cycle(islice(nexts, num_active))
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def partition(pred, iterable):
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'Use a predicate to partition entries into false entries and true entries'
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"Use a predicate to partition entries into false entries and true entries"
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# partition(is_odd, range(10)) --> 0 2 4 6 8 and 1 3 5 7 9
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t1, t2 = tee(iterable)
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return filterfalse(pred, t1), filter(pred, t2)
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@ -881,7 +881,7 @@ which incur interpreter overhead.
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def random_product(*args, repeat=1):
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"Random selection from itertools.product(*args, **kwds)"
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pools = [tuple(pool) for pool in args] * repeat
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return tuple(random.choice(pool) for pool in pools)
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return tuple(map(random.choice, pools))
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def random_permutation(iterable, r=None):
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"Random selection from itertools.permutations(iterable, r)"
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@ -900,11 +900,11 @@ which incur interpreter overhead.
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"Random selection from itertools.combinations_with_replacement(iterable, r)"
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pool = tuple(iterable)
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n = len(pool)
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indices = sorted(random.randrange(n) for i in range(r))
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indices = sorted(random.choices(range(n), k=r))
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return tuple(pool[i] for i in indices)
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def nth_combination(iterable, r, index):
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'Equivalent to list(combinations(iterable, r))[index]'
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"Equivalent to list(combinations(iterable, r))[index]"
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pool = tuple(iterable)
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n = len(pool)
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if r < 0 or r > n:
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@ -2290,7 +2290,7 @@ Samuele
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... "Count how many times the predicate is true"
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... return sum(map(pred, iterable))
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>>> def padnone(iterable):
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>>> def pad_none(iterable):
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... "Returns the sequence elements and then returns None indefinitely"
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... return chain(iterable, repeat(None))
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@ -2460,7 +2460,7 @@ True
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>>> list(pairwise('a'))
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[]
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>>> list(islice(padnone('abc'), 0, 6))
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>>> list(islice(pad_none('abc'), 0, 6))
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['a', 'b', 'c', None, None, None]
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>>> list(ncycles('abc', 3))
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