Issue 18752: Make chain.from_iterable() more visible in the documentation.
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@ -48,6 +48,7 @@ Iterator Arguments Results
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==================== ============================ ================================================= =============================================================
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:func:`accumulate` p [,func] p0, p0+p1, p0+p1+p2, ... ``accumulate([1,2,3,4,5]) --> 1 3 6 10 15``
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:func:`chain` p, q, ... p0, p1, ... plast, q0, q1, ... ``chain('ABC', 'DEF') --> A B C D E F``
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chain.from_iterable iterable p0, p1, ... plast, q0, q1, ... ``chain.from_iterable(['ABC', 'DEF']) --> A B C D E F``
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:func:`compress` data, selectors (d[0] if s[0]), (d[1] if s[1]), ... ``compress('ABCDEF', [1,0,1,0,1,1]) --> A C E F``
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:func:`dropwhile` pred, seq seq[n], seq[n+1], starting when pred fails ``dropwhile(lambda x: x<5, [1,4,6,4,1]) --> 6 4 1``
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:func:`filterfalse` pred, seq elements of seq where pred(elem) is False ``filterfalse(lambda x: x%2, range(10)) --> 0 2 4 6 8``
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@ -4,7 +4,7 @@
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/* Itertools module written and maintained
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by Raymond D. Hettinger <python@rcn.com>
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Copyright (c) 2003 Python Software Foundation.
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Copyright (c) 2003-2013 Python Software Foundation.
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All rights reserved.
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*/
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@ -4456,6 +4456,7 @@ repeat(elem [,n]) --> elem, elem, elem, ... endlessly or up to n times\n\
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Iterators terminating on the shortest input sequence:\n\
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accumulate(p[, func]) --> p0, p0+p1, p0+p1+p2\n\
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chain(p, q, ...) --> p0, p1, ... plast, q0, q1, ... \n\
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chain.from_iterable([p, q, ...]) --> p0, p1, ... plast, q0, q1, ... \n\
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compress(data, selectors) --> (d[0] if s[0]), (d[1] if s[1]), ...\n\
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dropwhile(pred, seq) --> seq[n], seq[n+1], starting when pred fails\n\
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groupby(iterable[, keyfunc]) --> sub-iterators grouped by value of keyfunc(v)\n\
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