From f984a6526711513e1af035d2fcee545c51ab51fe Mon Sep 17 00:00:00 2001 From: Guido van Rossum Date: Tue, 29 Sep 1998 15:57:42 +0000 Subject: [PATCH] Fix suggested by Sjoerd (long ago!) to get a better error message when there's a syntax error. (In particular, display the correct filename). This changes the API: if there's a syntax error, the function now returns normally after dumping the error to sys.stderr. I changed Sjoerd's use of string.join(string.split(...)) with string.replace(). --- Lib/py_compile.py | 10 +++++++++- 1 file changed, 9 insertions(+), 1 deletion(-) diff --git a/Lib/py_compile.py b/Lib/py_compile.py index 98b3b21f1a9..a6d03d7b3ee 100644 --- a/Lib/py_compile.py +++ b/Lib/py_compile.py @@ -51,7 +51,15 @@ def compile(file, cfile=None, dfile=None): f.close() if codestring and codestring[-1] != '\n': codestring = codestring + '\n' - codeobject = __builtin__.compile(codestring, dfile or file, 'exec') + try: + codeobject = __builtin__.compile(codestring, dfile or file, 'exec') + except SyntaxError, detail: + import traceback, sys, string + lines = traceback.format_exception_only(SyntaxError, detail) + for line in lines: + sys.stderr.write(string.replace(line, 'File ""', + 'File "%s"' % (dfile or file))) + return if not cfile: cfile = file + (__debug__ and 'c' or 'o') fc = open(cfile, 'wb')