Revised the itertools quantifier recipes to match the performance of the
new builtins.
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96229b1918
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@ -461,26 +461,26 @@ def nth(iterable, n):
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"Returns the nth item"
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return list(islice(iterable, n, n+1))
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def all(seq, pred=bool):
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"Returns True if pred(x) is True for every element in the iterable"
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def all(seq, pred=None):
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"Returns True if pred(x) is true for every element in the iterable"
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for elem in ifilterfalse(pred, seq):
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return False
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return True
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def any(seq, pred=bool):
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"Returns True if pred(x) is True for at least one element in the iterable"
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def any(seq, pred=None):
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"Returns True if pred(x) is true for at least one element in the iterable"
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for elem in ifilter(pred, seq):
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return True
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return False
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def no(seq, pred=bool):
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"Returns True if pred(x) is False for every element in the iterable"
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def no(seq, pred=None):
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"Returns True if pred(x) is false for every element in the iterable"
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for elem in ifilter(pred, seq):
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return False
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return True
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def quantify(seq, pred=bool):
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"Count how many times the predicate is True in the sequence"
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def quantify(seq, pred=None):
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"Count how many times the predicate is true in the sequence"
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return sum(imap(pred, seq))
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def padnone(seq):
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@ -799,26 +799,26 @@ Samuele
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... "Returns the nth item"
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... return list(islice(iterable, n, n+1))
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>>> def all(seq, pred=bool):
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... "Returns True if pred(x) is True for every element in the iterable"
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>>> def all(seq, pred=None):
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... "Returns True if pred(x) is true for every element in the iterable"
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... for elem in ifilterfalse(pred, seq):
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... return False
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... return True
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>>> def any(seq, pred=bool):
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... "Returns True if pred(x) is True for at least one element in the iterable"
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>>> def any(seq, pred=None):
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... "Returns True if pred(x) is true for at least one element in the iterable"
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... for elem in ifilter(pred, seq):
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... return True
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... return False
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>>> def no(seq, pred=bool):
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... "Returns True if pred(x) is False for every element in the iterable"
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>>> def no(seq, pred=None):
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... "Returns True if pred(x) is false for every element in the iterable"
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... for elem in ifilter(pred, seq):
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... return False
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... return True
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>>> def quantify(seq, pred=bool):
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... "Count how many times the predicate is True in the sequence"
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>>> def quantify(seq, pred=None):
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... "Count how many times the predicate is true in the sequence"
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... return sum(imap(pred, seq))
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>>> def padnone(seq):
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