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Use floor division (// and __[r]floordiv__ in right-dispatch test.

This commit is contained in:
Guido van Rossum 2003-02-27 20:04:19 +00:00
parent f359410ce2
commit f389c77273
1 changed files with 23 additions and 23 deletions
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46
Lib/test/test_descr.py
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@ -3678,47 +3678,47 @@ def subclass_right_op():
# Case 1: subclass of int; this tests code in abstract.c::binary_op1()
class B(int):
def __div__(self, other):
return "B.__div__"
def __rdiv__(self, other):
return "B.__rdiv__"
def __floordiv__(self, other):
return "B.__floordiv__"
def __rfloordiv__(self, other):
return "B.__rfloordiv__"
vereq(B(1) / 1, "B.__div__")
vereq(1 / B(1), "B.__rdiv__")
vereq(B(1) // 1, "B.__floordiv__")
vereq(1 // B(1), "B.__rfloordiv__")
# Case 2: subclass of object; this is just the baseline for case 3
class C(object):
def __div__(self, other):
return "C.__div__"
def __rdiv__(self, other):
return "C.__rdiv__"
def __floordiv__(self, other):
return "C.__floordiv__"
def __rfloordiv__(self, other):
return "C.__rfloordiv__"
vereq(C() / 1, "C.__div__")
vereq(1 / C(), "C.__rdiv__")
vereq(C() // 1, "C.__floordiv__")
vereq(1 // C(), "C.__rfloordiv__")
# Case 3: subclass of new-style class; here it gets interesting
class D(C):
def __div__(self, other):
return "D.__div__"
def __rdiv__(self, other):
return "D.__rdiv__"
def __floordiv__(self, other):
return "D.__floordiv__"
def __rfloordiv__(self, other):
return "D.__rfloordiv__"
vereq(D() / C(), "D.__div__")
vereq(C() / D(), "D.__rdiv__")
vereq(D() // C(), "D.__floordiv__")
vereq(C() // D(), "D.__rfloordiv__")
# Case 4: this didn't work right in 2.2.2 and 2.3a1
class E(C):
pass
vereq(E.__rdiv__, C.__rdiv__)
vereq(E.__rfloordiv__, C.__rfloordiv__)
vereq(E() / 1, "C.__div__")
vereq(1 / E(), "C.__rdiv__")
vereq(E() / C(), "C.__div__")
vereq(C() / E(), "C.__div__") # This one would fail
vereq(E() // 1, "C.__floordiv__")
vereq(1 // E(), "C.__rfloordiv__")
vereq(E() // C(), "C.__floordiv__")
vereq(C() // E(), "C.__floordiv__") # This one would fail
def dict_type_with_metaclass():
if verbose: