It's ok for __hex__ or __oct__ to return unicode.
Don't insist that float('1'*10000) raises an exception.
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@ -608,8 +608,7 @@ class BuiltinTest(unittest.TestCase):
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if have_unicode:
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self.assertEqual(float(str(" 3.14 ")), 3.14)
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self.assertEqual(float(str(b" \u0663.\u0661\u0664 ",'raw-unicode-escape')), 3.14)
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# Implementation limitation in PyFloat_FromString()
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self.assertRaises(ValueError, float, str("1"*10000))
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self.assertEqual(float("1"*10000), 1e10000) # Inf on both sides
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@run_with_locale('LC_NUMERIC', 'fr_FR', 'de_DE')
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def test_float_with_comma(self):
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@ -1230,7 +1230,7 @@ builtin_hex(PyObject *self, PyObject *v)
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return NULL;
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}
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res = (*nb->nb_hex)(v);
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if (res && !PyString_Check(res)) {
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if (res && !PyString_Check(res) && !PyUnicode_Check(res)) {
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PyErr_Format(PyExc_TypeError,
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"__hex__ returned non-string (type %.200s)",
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res->ob_type->tp_name);
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@ -1430,7 +1430,7 @@ builtin_oct(PyObject *self, PyObject *v)
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return NULL;
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}
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res = (*nb->nb_oct)(v);
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if (res && !PyString_Check(res)) {
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if (res && !PyString_Check(res) && !PyUnicode_Check(res)) {
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PyErr_Format(PyExc_TypeError,
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"__oct__ returned non-string (type %.200s)",
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res->ob_type->tp_name);
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