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Re-init _Py_UnhandledKeyboardInterrupt before run. (GH-11963) 

Explicitly reinitialize this every eval *just in case* someone is
calling into an embedded Python where they don't care about an uncaught
KeyboardInterrupt exception (why didn't they leave
`config.install_signal_handlers` set to `0`?!?) but then later call
`Py_Main()` itself (which *checks* this flag and dies with a signal after
its interpreter exits).  We don't want a previous embedded interpreter's
uncaught exception to trigger an unexplained signal exit from a future
`Py_Main()` based one.
This commit is contained in:
Gregory P. Smith 2019-02-20 17:35:54 -08:00 committed by GitHub
parent 9b0c681e2d
commit d9bc543cbb
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1 changed files with 11 additions and 0 deletions
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Python/pythonrun.c
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@ -1032,6 +1032,17 @@ static PyObject *
run_eval_code_obj(PyCodeObject *co, PyObject *globals, PyObject *locals)
{
PyObject *v;
/*
* We explicitly re-initialize _Py_UnhandledKeyboardInterrupt every eval
* _just in case_ someone is calling into an embedded Python where they
* don't care about an uncaught KeyboardInterrupt exception (why didn't they
* leave config.install_signal_handlers set to 0?!?) but then later call
* Py_Main() itself (which _checks_ this flag and dies with a signal after
* its interpreter exits). We don't want a previous embedded interpreter's
* uncaught exception to trigger an unexplained signal exit from a future
* Py_Main() based one.
*/
_Py_UnhandledKeyboardInterrupt = 0;
v = PyEval_EvalCode((PyObject*)co, globals, locals);
if (!v && PyErr_Occurred() == PyExc_KeyboardInterrupt) {
_Py_UnhandledKeyboardInterrupt = 1;