Fix SF bug #689659, 64-bit int and long hash keys incompatible

On a 64-bit machine, a dictionary could contain duplicate int/long keys
if the value was > 2**32.
This commit is contained in:
Neal Norwitz 2003-02-23 23:11:41 +00:00
parent 97e3f0060c
commit d5a65a77cf
3 changed files with 14 additions and 3 deletions

View File

@ -639,6 +639,14 @@ try: d.pop(k)
except KeyError: pass
else: raise TestFailed, "{}.pop(k) doesn't raise KeyError when dictionary is empty"
# verify longs/ints get same value when key > 32 bits (for 64-bit archs)
# see SF bug #689659
x = 4503599627370496L
y = 4503599627370496
h = {x: 'anything', y: 'something else'}
if h[x] != h[y]:
raise TestFailed, "long/int key should match"
d[1] = 1
try:
for i in d:

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@ -12,7 +12,8 @@ What's New in Python 2.3 beta 1?
Core and builtins
-----------------
TBD
- On 64-bit systems, a dictionary could contain duplicate long/int keys
if the key value was larger than 2**32. See SF bug #689659.
Extension modules
-----------------

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@ -1490,11 +1490,13 @@ long_hash(PyLongObject *v)
sign = -1;
i = -(i);
}
#define LONG_BIT_SHIFT (8*sizeof(long) - SHIFT)
while (--i >= 0) {
/* Force a 32-bit circular shift */
x = ((x << SHIFT) & ~MASK) | ((x >> (32-SHIFT)) & MASK);
/* Force a native long #-bits (32 or 64) circular shift */
x = ((x << SHIFT) & ~MASK) | ((x >> LONG_BIT_SHIFT) & MASK);
x += v->ob_digit[i];
}
#undef LONG_BIT_SHIFT
x = x * sign;
if (x == -1)
x = -2;