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bpo-30004: Fix the code example of using group in Regex Howto Docs (GH-4443) (GH-4555) 

The provided code example was supposed to find repeated words, however it returned false results.
(cherry picked from commit 610e5afdcb)
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Miss Islington (bot) 2017-11-24 21:01:39 -08:00 committed by Mariatta
parent 465f3d0820
commit c02037d622
1 changed files with 3 additions and 3 deletions
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Doc/howto/regex.rst
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@ -840,7 +840,7 @@ backreferences in a RE.
For example, the following RE detects doubled words in a string. :: For example, the following RE detects doubled words in a string. ::
>>> p = re.compile(r'(\b\w+)\s+\1') >>> p = re.compile(r'\b(\w+)\s+\1\b')
>>> p.search('Paris in the the spring').group() >>> p.search('Paris in the the spring').group()
'the the' 'the the'
@ -947,9 +947,9 @@ number of the group. There's naturally a variant that uses the group name
instead of the number. This is another Python extension: ``(?P=name)`` indicates instead of the number. This is another Python extension: ``(?P=name)`` indicates
that the contents of the group called *name* should again be matched at the that the contents of the group called *name* should again be matched at the
current point. The regular expression for finding doubled words, current point. The regular expression for finding doubled words,
``(\b\w+)\s+\1`` can also be written as ``(?P<word>\b\w+)\s+(?P=word)``:: ``\b(\w+)\s+\1\b`` can also be written as ``\b(?P<word>\w+)\s+(?P=word)\b``::
>>> p = re.compile(r'(?P<word>\b\w+)\s+(?P=word)') >>> p = re.compile(r'\b(?P<word>\w+)\s+(?P=word)\b')
>>> p.search('Paris in the the spring').group() >>> p.search('Paris in the the spring').group()
'the the' 'the the'