traverseda
/
cpython
1
0
Fork 0
Code Issues Pull Requests Releases Wiki Activity

Speedup and simplify negative counter using count's new step argument.

This commit is contained in:
Raymond Hettinger 2009-02-21 08:58:42 +00:00
parent aa681c7b99
commit be9b765c07
1 changed files with 3 additions and 3 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

6
Lib/heapq.py
View File

@ -130,7 +130,7 @@ __all__ = ['heappush', 'heappop', 'heapify', 'heapreplace', 'merge',
'nlargest', 'nsmallest', 'heappushpop']
from itertools import islice, repeat, count, imap, izip, tee, chain
from operator import itemgetter, neg
from operator import itemgetter
import bisect
def heappush(heap, item):
@ -413,13 +413,13 @@ def nlargest(n, iterable, key=None):
# When key is none, use simpler decoration
if key is None:
it = izip(iterable, imap(neg, count())) # decorate
it = izip(iterable, count(0,-1)) # decorate
result = _nlargest(n, it)
return map(itemgetter(0), result) # undecorate
# General case, slowest method
in1, in2 = tee(iterable)
it = izip(imap(key, in1), imap(neg, count()), in2) # decorate
it = izip(imap(key, in1), count(0,-1), in2) # decorate
result = _nlargest(n, it)
return map(itemgetter(2), result) # undecorate