fix description of \r; thanks to Thomas Waldmann from docs@
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@ -613,7 +613,7 @@ form.
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of *pattern* in *string* by the replacement *repl*. If the pattern isn't found,
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*string* is returned unchanged. *repl* can be a string or a function; if it is
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a string, any backslash escapes in it are processed. That is, ``\n`` is
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converted to a single newline character, ``\r`` is converted to a linefeed, and
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converted to a single newline character, ``\r`` is converted to a carriage return, and
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so forth. Unknown escapes such as ``\j`` are left alone. Backreferences, such
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as ``\6``, are replaced with the substring matched by group 6 in the pattern.
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For example:
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