Add keyword argument support to itertools.count().

Doc/library/itertools.rst

@@ -200,20 +200,20 @@ loops that truncate the stream.
    .. versionadded:: 2.7
 
 
-.. function:: count(n=0, step=1)
+.. function:: count(start=0, step=1)
 
    Make an iterator that returns evenly spaced values starting with *n*. Often
    used as an argument to :func:`imap` to generate consecutive data points.
    Also, used with :func:`izip` to add sequence numbers.  Equivalent to::
 
-      def count(n=0, step=1):
+      def count(start=0, step=1):
           # count(10) --> 10 11 12 13 14 ...
           # count(2.5, 0.5) -> 3.5 3.0 4.5 ...
+          n = start
           while True:
               yield n
               n += step
 
-
    .. versionchanged:: 2.7
       added *step* argument and allowed non-integer arguments.
 

Lib/test/test_itertools.py

@@ -347,6 +347,8 @@ class TestBasicOps(unittest.TestCase):
 
     def test_count_with_stride(self):
         self.assertEqual(zip('abc',count(2,3)), [('a', 2), ('b', 5), ('c', 8)])
+        self.assertEqual(zip('abc',count(start=2,step=3)),
+                         [('a', 2), ('b', 5), ('c', 8)])
         self.assertEqual(zip('abc',count(2,0)), [('a', 2), ('b', 2), ('c', 2)])
         self.assertEqual(zip('abc',count(2,1)), [('a', 2), ('b', 3), ('c', 4)])
         self.assertEqual(take(20, count(maxsize-15, 3)), take(20, range(maxsize-15, maxsize+100, 3)))

Modules/itertoolsmodule.c

@@ -3233,11 +3233,10 @@ count_new(PyTypeObject *type, PyObject *args, PyObject *kwds)
 	Py_ssize_t cnt = 0;
 	PyObject *long_cnt = NULL;
 	PyObject *long_step = NULL;
+	static char *kwlist[] = {"start", "step", 0};
 
-	if (type == &count_type && !_PyArg_NoKeywords("count()", kwds))
-		return NULL;
-
-	if (!PyArg_UnpackTuple(args, "count", 0, 2, &long_cnt, &long_step))
+	if (!PyArg_ParseTupleAndKeywords(args, kwds, "|OO:count",
+			kwlist, &long_cnt, &long_step))
 		return NULL;
 
 	if (long_cnt != NULL && !PyNumber_Check(long_cnt) ||
@@ -3353,10 +3352,10 @@ count_repr(countobject *lz)
 }
 
 PyDoc_STRVAR(count_doc,
-			 "count([firstval[, step]]) --> count object\n\
+			 "count([start[, step]]) --> count object\n\
 \n\
 Return a count object whose .next() method returns consecutive\n\
-integers starting from zero or, if specified, from firstval.\n\
+integers starting from zero or, if specified, from start.\n\
 If step is specified, counts by that interval.  Equivalent to:\n\n\
     def count(firstval=0, step=1):\n\
         x = firstval\n\