Branch merge
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commit
a27c8e3746
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@ -138,7 +138,7 @@ class RegisterTestCase(PyPIRCCommandTestCase):
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# let's see what the server received : we should
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# have 2 similar requests
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self.assertTrue(self.conn.reqs, 2)
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self.assertEqual(len(self.conn.reqs), 2)
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req1 = dict(self.conn.reqs[0].headers)
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req2 = dict(self.conn.reqs[1].headers)
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self.assertEqual(req2['Content-length'], req1['Content-length'])
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@ -168,7 +168,7 @@ class RegisterTestCase(PyPIRCCommandTestCase):
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del register_module.raw_input
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# we should have send a request
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self.assertTrue(self.conn.reqs, 1)
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self.assertEqual(len(self.conn.reqs), 1)
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req = self.conn.reqs[0]
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headers = dict(req.headers)
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self.assertEqual(headers['Content-length'], '608')
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@ -186,7 +186,7 @@ class RegisterTestCase(PyPIRCCommandTestCase):
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del register_module.raw_input
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# we should have send a request
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self.assertTrue(self.conn.reqs, 1)
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self.assertEqual(len(self.conn.reqs), 1)
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req = self.conn.reqs[0]
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headers = dict(req.headers)
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self.assertEqual(headers['Content-length'], '290')
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@ -178,7 +178,7 @@ def heappushpop(heap, item):
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return item
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def heapify(x):
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"""Transform list into a heap, in-place, in O(len(heap)) time."""
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"""Transform list into a heap, in-place, in O(len(x)) time."""
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n = len(x)
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# Transform bottom-up. The largest index there's any point to looking at
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# is the largest with a child index in-range, so must have 2*i + 1 < n,
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@ -368,7 +368,7 @@ def nsmallest(n, iterable, key=None):
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return [min(chain(head, it))]
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return [min(chain(head, it), key=key)]
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# When n>=size, it's faster to use sort()
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# When n>=size, it's faster to use sorted()
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try:
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size = len(iterable)
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except (TypeError, AttributeError):
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@ -406,7 +406,7 @@ def nlargest(n, iterable, key=None):
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return [max(chain(head, it))]
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return [max(chain(head, it), key=key)]
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# When n>=size, it's faster to use sort()
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# When n>=size, it's faster to use sorted()
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try:
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size = len(iterable)
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except (TypeError, AttributeError):
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@ -639,7 +639,6 @@ def get_platform():
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m = re.search(
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r'<key>ProductUserVisibleVersion</key>\s*' +
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r'<string>(.*?)</string>', f.read())
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f.close()
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if m is not None:
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macrelease = '.'.join(m.group(1).split('.')[:2])
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# else: fall back to the default behaviour
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