Fix docstrings for itertools combinatoric functions.
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@ -71,8 +71,8 @@ Iterator Arguments Resu
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============================================== ==================== =============================================================
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:func:`product` p, q, ... [repeat=1] cartesian product, equivalent to a nested for-loop
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:func:`permutations` p[, r] r-length tuples, all possible orderings, no repeated elements
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:func:`combinations` p[, r] r-length tuples, in sorted order, no repeated elements
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:func:`combinations_with_replacement` p[, r] r-length tuples, in sorted order, with repeated elements
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:func:`combinations` p, r r-length tuples, in sorted order, no repeated elements
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:func:`combinations_with_replacement` p, r r-length tuples, in sorted order, with repeated elements
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``product('ABCD', repeat=2)`` ``AA AB AC AD BA BB BC BD CA CB CC CD DA DB DC DD``
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``permutations('ABCD', 2)`` ``AB AC AD BA BC BD CA CB CD DA DB DC``
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@ -2196,7 +2196,7 @@ empty:
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}
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PyDoc_STRVAR(combinations_doc,
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"combinations(iterable[, r]) --> combinations object\n\
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"combinations(iterable, r) --> combinations object\n\
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\n\
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Return successive r-length combinations of elements in the iterable.\n\n\
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combinations(range(4), 3) --> (0,1,2), (0,1,3), (0,2,3), (1,2,3)");
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@ -2441,7 +2441,7 @@ empty:
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}
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PyDoc_STRVAR(cwr_doc,
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"combinations_with_replacement(iterable[, r]) --> combinations_with_replacement object\n\
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"combinations_with_replacement(iterable, r) --> combinations_with_replacement object\n\
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\n\
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Return successive r-length combinations of elements in the iterable\n\
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allowing individual elements to have successive repeats.\n\
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@ -4018,8 +4018,8 @@ izip_longest(p, q, ...) --> (p[0], q[0]), (p[1], q[1]), ... \n\
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Combinatoric generators:\n\
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product(p, q, ... [repeat=1]) --> cartesian product\n\
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permutations(p[, r])\n\
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combinations(p[, r])\n\
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combinations_with_replacement(p[, r])\n\
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combinations(p, r)\n\
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combinations_with_replacement(p, r)\n\
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");
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