Minor code cleanups.
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21ee10bf04
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99bf9a2567
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@ -138,7 +138,7 @@ heappop_internal(PyObject *heap, int siftup_func(PyListObject *, Py_ssize_t))
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lastelt = PyList_GET_ITEM(heap, n-1) ;
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lastelt = PyList_GET_ITEM(heap, n-1) ;
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Py_INCREF(lastelt);
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Py_INCREF(lastelt);
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if (PyList_SetSlice(heap, n-1, n, NULL) < 0) {
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if (PyList_SetSlice(heap, n-1, n, NULL)) {
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Py_DECREF(lastelt);
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Py_DECREF(lastelt);
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return NULL;
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return NULL;
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}
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}
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@ -177,7 +177,7 @@ heapreplace_internal(PyObject *args, int siftup_func(PyListObject *, Py_ssize_t)
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return NULL;
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return NULL;
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}
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}
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if (PyList_GET_SIZE(heap) < 1) {
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if (PyList_GET_SIZE(heap) == 0) {
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PyErr_SetString(PyExc_IndexError, "index out of range");
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PyErr_SetString(PyExc_IndexError, "index out of range");
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return NULL;
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return NULL;
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}
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}
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@ -222,7 +222,7 @@ heappushpop(PyObject *self, PyObject *args)
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return NULL;
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return NULL;
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}
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}
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if (PyList_GET_SIZE(heap) < 1) {
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if (PyList_GET_SIZE(heap) == 0) {
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Py_INCREF(item);
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Py_INCREF(item);
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return item;
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return item;
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}
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}
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@ -340,8 +340,8 @@ heapify_internal(PyObject *heap, int siftup_func(PyListObject *, Py_ssize_t))
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n is odd = 2*j+1, this is (2*j+1-1)/2 = j so j-1 is the largest,
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n is odd = 2*j+1, this is (2*j+1-1)/2 = j so j-1 is the largest,
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and that's again n//2-1.
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and that's again n//2-1.
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*/
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*/
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for (i=n/2-1 ; i>=0 ; i--)
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for (i = n/2 - 1 ; i >= 0 ; i--)
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if(siftup_func((PyListObject *)heap, i))
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if (siftup_func((PyListObject *)heap, i))
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return NULL;
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return NULL;
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Py_RETURN_NONE;
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Py_RETURN_NONE;
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}
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}
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