On path with known exact float, extract the double with the fast macro. (GH-21072)
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fe2a48c605
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@ -1256,9 +1256,15 @@ static PyObject *
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math_floor(PyObject *module, PyObject *number)
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/*[clinic end generated code: output=c6a65c4884884b8a input=63af6b5d7ebcc3d6]*/
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{
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double x;
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_Py_IDENTIFIER(__floor__);
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if (!PyFloat_CheckExact(number)) {
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if (PyFloat_CheckExact(number)) {
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x = PyFloat_AS_DOUBLE(number);
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}
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else
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{
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PyObject *method = _PyObject_LookupSpecial(number, &PyId___floor__);
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if (method != NULL) {
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PyObject *result = _PyObject_CallNoArg(method);
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@ -1267,11 +1273,10 @@ math_floor(PyObject *module, PyObject *number)
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}
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if (PyErr_Occurred())
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return NULL;
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x = PyFloat_AsDouble(number);
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if (x == -1.0 && PyErr_Occurred())
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return NULL;
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}
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double x = PyFloat_AsDouble(number);
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if (x == -1.0 && PyErr_Occurred())
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return NULL;
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return PyLong_FromDouble(floor(x));
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}
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