Backport r87672 and r87615, improving tests, using super() instead of direct parent references, and using __reduce__ method for pickling.
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@ -298,16 +298,16 @@ class Counter(dict):
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or multiset. Elements are stored as dictionary keys and their counts
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are stored as dictionary values.
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>>> c = Counter('abracadabra') # count elements from a string
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>>> c = Counter('abcdeabcdabcaba') # count elements from a string
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>>> c.most_common(3) # three most common elements
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[('a', 5), ('r', 2), ('b', 2)]
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[('a', 5), ('b', 4), ('c', 3)]
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>>> sorted(c) # list all unique elements
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['a', 'b', 'c', 'd', 'r']
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['a', 'b', 'c', 'd', 'e']
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>>> ''.join(sorted(c.elements())) # list elements with repetitions
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'aaaaabbcdrr'
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'aaaaabbbbcccdde'
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>>> sum(c.values()) # total of all counts
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11
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15
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>>> c['a'] # count of letter 'a'
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5
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@ -315,8 +315,8 @@ class Counter(dict):
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... c[elem] += 1 # by adding 1 to each element's count
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>>> c['a'] # now there are seven 'a'
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7
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>>> del c['r'] # remove all 'r'
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>>> c['r'] # now there are zero 'r'
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>>> del c['b'] # remove all 'b'
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>>> c['b'] # now there are zero 'b'
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0
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>>> d = Counter('simsalabim') # make another counter
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@ -355,6 +355,7 @@ class Counter(dict):
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>>> c = Counter(a=4, b=2) # a new counter from keyword args
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'''
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super().__init__()
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self.update(iterable, **kwds)
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def __missing__(self, key):
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@ -366,8 +367,8 @@ class Counter(dict):
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'''List the n most common elements and their counts from the most
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common to the least. If n is None, then list all element counts.
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>>> Counter('abracadabra').most_common(3)
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[('a', 5), ('r', 2), ('b', 2)]
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>>> Counter('abcdeabcdabcaba').most_common(3)
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[('a', 5), ('b', 4), ('c', 3)]
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'''
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# Emulate Bag.sortedByCount from Smalltalk
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@ -433,7 +434,7 @@ class Counter(dict):
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for elem, count in iterable.items():
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self[elem] = count + self_get(elem, 0)
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else:
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dict.update(self, iterable) # fast path when counter is empty
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super().update(iterable) # fast path when counter is empty
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else:
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self_get = self.get
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for elem in iterable:
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@ -445,10 +446,13 @@ class Counter(dict):
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'Like dict.copy() but returns a Counter instance instead of a dict.'
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return Counter(self)
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def __reduce__(self):
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return self.__class__, (dict(self),)
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def __delitem__(self, elem):
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'Like dict.__delitem__() but does not raise KeyError for missing values.'
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if elem in self:
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dict.__delitem__(self, elem)
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super().__delitem__(elem)
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def __repr__(self):
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if not self:
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