#687648 from Robert Schuppenies: use classic division. From me: don't use string exception; add __main__ section
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@ -68,7 +68,7 @@ def _days_in_year(year): # number of days in year
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return 365 + _is_leap(year)
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def _days_before_year(year): # number of days before year
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return year*365L + (year+3)/4 - (year+99)/100 + (year+399)/400
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return year*365L + (year+3)//4 - (year+99)//100 + (year+399)//400
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def _days_in_month(month, year): # number of days in month of year
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if month == 2 and _is_leap(year): return 29
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@ -92,9 +92,9 @@ def _num2date(n): # return date with ordinal n
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del ans.ord, ans.month, ans.day, ans.year # un-initialize it
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ans.ord = n
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n400 = (n-1)/_DI400Y # # of 400-year blocks preceding
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n400 = (n-1)//_DI400Y # # of 400-year blocks preceding
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year, n = 400 * n400, n - _DI400Y * n400
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more = n / 365
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more = n // 365
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dby = _days_before_year(more)
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if dby >= n:
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more = more - 1
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@ -104,7 +104,7 @@ def _num2date(n): # return date with ordinal n
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try: year = int(year) # chop to int, if it fits
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except (ValueError, OverflowError): pass
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month = min(n/29 + 1, 12)
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month = min(n//29 + 1, 12)
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dbm = _days_before_month(month, year)
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if dbm >= n:
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month = month - 1
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@ -174,7 +174,9 @@ def today():
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local = time.localtime(time.time())
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return Date(local[1], local[2], local[0])
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DateTestError = 'DateTestError'
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class DateTestError(Exception):
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pass
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def test(firstyear, lastyear):
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a = Date(9,30,1913)
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b = Date(9,30,1914)
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@ -220,3 +222,6 @@ def test(firstyear, lastyear):
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(fd.month,fd.day,fd.year,ld.month,ld.day,ld.year):
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raise DateTestError, ('num->date failed', y)
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y = y + 1
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if __name__ == '__main__':
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test(1850, 2150)
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