Fix for SF bug 1569998: break permitted inside try.
The compiler was checking that there was something on the fblock stack, but not that there was a loop on the stack. Fixed that and added a test for the specific syntax error. Bug fix candidate.
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@ -322,6 +322,20 @@ This is essentially a continue in a finally which should not be allowed.
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...
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SyntaxError: 'continue' not supported inside 'finally' clause (<doctest test.test_syntax[41]>, line 8)
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There is one test for a break that is not in a loop. The compiler
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uses a single data structure to keep track of try-finally and loops,
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so we need to be sure that a break is actually inside a loop. If it
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isn't, there should be a syntax error.
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>>> try:
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... print 1
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... break
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... print 2
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... finally:
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... print 3
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Traceback (most recent call last):
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...
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SyntaxError: 'break' outside loop (<doctest test.test_syntax[42]>, line 3)
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"""
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import re
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@ -187,6 +187,8 @@ static int compiler_push_fblock(struct compiler *, enum fblocktype,
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basicblock *);
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static void compiler_pop_fblock(struct compiler *, enum fblocktype,
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basicblock *);
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/* Returns true if there is a loop on the fblock stack. */
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static int compiler_in_loop(struct compiler *);
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static int inplace_binop(struct compiler *, operator_ty);
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static int expr_constant(expr_ty e);
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@ -2157,7 +2159,7 @@ compiler_visit_stmt(struct compiler *c, stmt_ty s)
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case Pass_kind:
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break;
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case Break_kind:
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if (!c->u->u_nfblocks)
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if (!compiler_in_loop(c))
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return compiler_error(c, "'break' outside loop");
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ADDOP(c, BREAK_LOOP);
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break;
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@ -3147,6 +3149,16 @@ compiler_pop_fblock(struct compiler *c, enum fblocktype t, basicblock *b)
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assert(u->u_fblock[u->u_nfblocks].fb_block == b);
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}
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static int
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compiler_in_loop(struct compiler *c) {
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int i;
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struct compiler_unit *u = c->u;
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for (i = 0; i < u->u_nfblocks; ++i) {
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if (u->u_fblock[i].fb_type == LOOP)
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return 1;
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}
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return 0;
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}
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/* Raises a SyntaxError and returns 0.
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If something goes wrong, a different exception may be raised.
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*/
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