SF 1602378 Clarify docstrings for bisect
This commit is contained in:
parent
ab8802a4f7
commit
7352cf5935
|
@ -23,8 +23,8 @@ def bisect_right(a, x, lo=0, hi=None):
|
|||
"""Return the index where to insert item x in list a, assuming a is sorted.
|
||||
|
||||
The return value i is such that all e in a[:i] have e <= x, and all e in
|
||||
a[i:] have e > x. So if x already appears in the list, i points just
|
||||
beyond the rightmost x already there.
|
||||
a[i:] have e > x. So if x already appears in the list, a.insert(x) will
|
||||
insert just after the rightmost x already there.
|
||||
|
||||
Optional args lo (default 0) and hi (default len(a)) bound the
|
||||
slice of a to be searched.
|
||||
|
@ -62,8 +62,8 @@ def bisect_left(a, x, lo=0, hi=None):
|
|||
"""Return the index where to insert item x in list a, assuming a is sorted.
|
||||
|
||||
The return value i is such that all e in a[:i] have e < x, and all e in
|
||||
a[i:] have e >= x. So if x already appears in the list, i points just
|
||||
before the leftmost x already there.
|
||||
a[i:] have e >= x. So if x already appears in the list, a.insert(x) will
|
||||
insert just before the leftmost x already there.
|
||||
|
||||
Optional args lo (default 0) and hi (default len(a)) bound the
|
||||
slice of a to be searched.
|
||||
|
|
Loading…
Reference in New Issue