Broke down and made it work for Python 2.0 and up. (Older versions

would have required refraining from using string methods -- too
painful.)

Changed the -s option so that multiple -s options are cumulative.
This commit is contained in:
Guido van Rossum 2003-03-07 01:33:18 +00:00
parent ea7598e6f4
commit 6e31aad983
1 changed files with 25 additions and 24 deletions

View File

@ -1,4 +1,4 @@
"""Framework for measuring execution time for small code snippets.
"""Tool for measuring execution time of small code snippets.
This module avoids a number of common traps for measuring execution
times. See also Tim Peters' introduction to the Algorithms chapter in
@ -12,7 +12,7 @@ Command line usage:
Options:
-n/--number N: how many times to execute 'statement' (default: see below)
-r/--repeat N: how many times to repeat the timer (default 1)
-s/--setup S: statements executed once before 'statement' (default 'pass')
-s/--setup S: statement to be executed once initially (default 'pass')
-t/--time: use time.time() (default on Unix)
-c/--clock: use time.clock() (default on Windows)
-h/--help: print this usage message and exit
@ -20,7 +20,8 @@ Options:
A multi-line statement may be given by specifying each line as a
separate argument; indented lines are possible by enclosing an
argument in quotes and using leading spaces.
argument in quotes and using leading spaces. Multiple -s options are
treated similarly.
If -n is not given, a suitable number of loops is calculated by trying
successive powers of 10 until the total time is at least 0.2 seconds.
@ -37,27 +38,23 @@ good for this. On Unix, you can use clock() to measure CPU time.
Note: there is a certain baseline overhead associated with executing a
pass statement. The code here doesn't try to hide it, but you should
be aware of it (especially when comparing different versions of
Python). The baseline overhead is measured by invoking the program
without arguments.
be aware of it. The baseline overhead can be measured by invoking the
program without arguments.
The baseline overhead differs between Python versions! Also, to
fairly compare older Python versions to Python 2.3, you may want to
use python -O for the older versions to avoid timing SET_LINENO
instructions.
"""
# To use this module with older versions of Python, the dependency on
# the itertools module is easily removed; in the template, instead of
# itertools.repeat(None, number), use [None]*number. It's barely
# slower. Note: the baseline overhead, measured by the default
# invocation, differs for older Python versions! Also, to fairly
# compare older Python versions to Python 2.3, you may want to use
# python -O for the older versions to avoid timing SET_LINENO
# instructions.
# XXX Maybe for convenience of comparing with previous Python versions,
# itertools.repeat() should not be used at all?
import sys
import math
import time
try:
import itertools
except ImportError:
# Must be an older Python version (see timeit() below)
itertools = None
__all__ = ["Timer"]
@ -75,9 +72,8 @@ else:
# in Timer.__init__() depend on setup being indented 4 spaces and stmt
# being indented 8 spaces.
template = """
def inner(number, timer):
def inner(seq, timer):
%(setup)s
seq = itertools.repeat(None, number)
t0 = timer()
for i in seq:
%(stmt)s
@ -126,7 +122,11 @@ class Timer:
to one million. The main statement, the setup statement and
the timer function to be used are passed to the constructor.
"""
return self.inner(number, self.timer)
if itertools:
seq = itertools.repeat(None, number)
else:
seq = [None] * number
return self.inner(seq, self.timer)
def repeat(self, repeat=default_repeat, number=default_number):
"""Call timer() a few times.
@ -177,13 +177,13 @@ def main(args=None):
timer = default_timer
stmt = "\n".join(args) or "pass"
number = 0 # auto-determine
setup = "pass"
setup = []
repeat = 1
for o, a in opts:
if o in ("-n", "--number"):
number = int(a)
if o in ("-s", "--setup"):
setup = a
setup.append(a)
if o in ("-r", "--repeat"):
repeat = int(a)
if repeat <= 0:
@ -195,6 +195,7 @@ def main(args=None):
if o in ("-h", "--help"):
print __doc__,
return 0
setup = "\n".join(setup) or "pass"
t = Timer(stmt, setup, timer)
if number == 0:
# determine number so that 0.2 <= total time < 2.0