Simplify and annotate the bigcomp function, removing unused special cases.
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@ -1163,7 +1163,7 @@ sulp(U *x, BCinfo *bc)
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correctly rounded value corresponding to the original string. It
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determines which of these two values is the correct one by
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computing the decimal digits of rv + 0.5ulp and comparing them with
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the digits of s0.
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the corresponding digits of s0.
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In the following, write dv for the absolute value of the number represented
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by the input string.
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@ -1218,49 +1218,41 @@ static int
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bigcomp(U *rv, const char *s0, BCinfo *bc)
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{
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Bigint *b, *d;
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int b2, bbits, d2, dd, dig, dsign, i, j, nd, nd0, p2, p5, speccase;
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int b2, bbits, d2, dd, dig, i, j, nd, nd0, p2, p5;
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dsign = bc->dsign;
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nd = bc->nd;
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nd0 = bc->nd0;
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p5 = nd + bc->e0;
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speccase = 0;
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if (rv->d == 0.) { /* special case: value near underflow-to-zero */
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/* threshold was rounded to zero */
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b = i2b(1);
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b = i2b(0);
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if (b == NULL)
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return -1;
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p2 = Emin - P + 1;
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bbits = 1;
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word0(rv) = (P+2) << Exp_shift;
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i = 0;
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{
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speccase = 1;
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--p2;
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dsign = 0;
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goto have_i;
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}
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p2 = Emin - P + 1; /* = -1074 for IEEE 754 binary64 */
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bbits = 0;
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}
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else
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{
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else {
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b = d2b(rv, &p2, &bbits);
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if (b == NULL)
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return -1;
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p2 -= bc->scale;
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}
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p2 -= bc->scale;
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/* floor(log2(rv)) == bbits - 1 + p2 */
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/* Check for denormal case. */
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/* now rv/2^(bc->scale) = b * 2**p2, and b has bbits significant bits */
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/* Replace (b, p2) by (b << i, p2 - i), with i the largest integer such
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that b << i has at most P significant bits and p2 - i >= Emin - P +
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1. */
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i = P - bbits;
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if (i > (j = P - Emin - 1 + p2)) {
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j = p2 - (Emin - P + 1);
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if (i > j)
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i = j;
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}
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{
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b = lshift(b, ++i);
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if (b == NULL)
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return -1;
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b->x[0] |= 1;
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}
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have_i:
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/* increment i so that we shift b by an extra bit; then or-ing a 1 into
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the lsb of b gives us rv/2^(bc->scale) + 0.5ulp. */
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b = lshift(b, ++i);
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if (b == NULL)
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return -1;
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b->x[0] |= 1;
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p2 -= p5 + i;
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d = i2b(1);
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if (d == NULL) {
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@ -1363,28 +1355,12 @@ bigcomp(U *rv, const char *s0, BCinfo *bc)
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ret:
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Bfree(b);
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Bfree(d);
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if (speccase) {
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if (dd <= 0)
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rv->d = 0.;
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}
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else if (dd < 0) {
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if (!dsign) /* does not happen for round-near */
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retlow1:
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dval(rv) -= sulp(rv, bc);
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}
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else if (dd > 0) {
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if (dsign) {
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rethi1:
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dval(rv) += sulp(rv, bc);
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}
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}
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else {
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if (dd > 0)
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dval(rv) += sulp(rv, bc);
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else if (dd == 0) {
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/* Exact half-way case: apply round-even rule. */
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if (word1(rv) & 1) {
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if (dsign)
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goto rethi1;
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goto retlow1;
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}
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if (word1(rv) & 1)
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dval(rv) += sulp(rv, bc);
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}
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return 0;
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