bpo-26506: hex() documentation: mention %x % int (GH-2525)
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@ -81,9 +81,24 @@ are always available. They are listed here in alphabetical order.
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.. function:: bin(x)
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Convert an integer number to a binary string. The result is a valid Python
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expression. If *x* is not a Python :class:`int` object, it has to define an
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:meth:`__index__` method that returns an integer.
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Convert an integer number to a binary string prefixed with "0b". The result
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is a valid Python expression. If *x* is not a Python :class:`int` object, it
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has to define an :meth:`__index__` method that returns an integer. Some
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examples:
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>>> bin(3)
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'0b11'
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>>> bin(-10)
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'-0b1010'
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If prefix "0b" is desired or not, you can use either of the following ways.
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>>> format(14, '#b'), format(14, 'b')
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('0b1110', '1110')
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>>> f'{14:#b}', f'{14:b}'
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('0b1110', '1110')
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See also :func:`format` for more information.
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.. class:: bool([x])
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@ -635,16 +650,26 @@ are always available. They are listed here in alphabetical order.
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.. function:: hex(x)
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Convert an integer number to a lowercase hexadecimal string
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prefixed with "0x", for example:
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Convert an integer number to a lowercase hexadecimal string prefixed with
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"0x". If x is not a Python :class:`int` object, it has to define an
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__index__() method that returns an integer. Some examples:
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>>> hex(255)
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'0xff'
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>>> hex(-42)
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'-0x2a'
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If x is not a Python :class:`int` object, it has to define an __index__()
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method that returns an integer.
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If you want to convert an integer number to an uppercase or lower hexadecimal
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string with prefix or not, you can use either of the following ways:
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>>> '%#x' % 255, '%x' % 255, '%X' % 255
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('0xff', 'ff', 'FF')
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>>> format(255, '#x'), format(255, 'x'), format(255, 'X')
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('0xff', 'ff', 'FF')
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>>> f'{255:#x}', f'{255:x}', f'{255:X}'
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('0xff', 'ff', 'FF')
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See also :func:`format` for more information.
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See also :func:`int` for converting a hexadecimal string to an
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integer using a base of 16.
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@ -878,10 +903,27 @@ are always available. They are listed here in alphabetical order.
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.. function:: oct(x)
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Convert an integer number to an octal string. The result is a valid Python
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expression. If *x* is not a Python :class:`int` object, it has to define an
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:meth:`__index__` method that returns an integer.
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Convert an integer number to an octal string prefixed with "0o". The result
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is a valid Python expression. If *x* is not a Python :class:`int` object, it
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has to define an :meth:`__index__` method that returns an integer. For
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example:
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>>> oct(8)
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'0o10'
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>>> oct(-56)
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'-0o70'
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If you want to convert an integer number to octal string either with prefix
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"0o" or not, you can use either of the following ways.
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>>> '%#o' % 10, '%o' % 10
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('0o12', '12')
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>>> format(10, '#o'), format(10, 'o')
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('0o12', '12')
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>>> f'{10:#o}', f'{10:o}'
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('0o12', '12')
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See also :func:`format` for more information.
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.. index::
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single: file object; open() built-in function
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