bpo-26506: hex() documentation: mention %x % int (GH-2525)

This commit is contained in:
Manvisha Kodali 2017-07-06 22:30:58 +03:00 committed by Mariatta
parent 0653fba51c
commit 67ba4fa467
1 changed files with 52 additions and 10 deletions

View File

@ -81,9 +81,24 @@ are always available. They are listed here in alphabetical order.
.. function:: bin(x)
Convert an integer number to a binary string. The result is a valid Python
expression. If *x* is not a Python :class:`int` object, it has to define an
:meth:`__index__` method that returns an integer.
Convert an integer number to a binary string prefixed with "0b". The result
is a valid Python expression. If *x* is not a Python :class:`int` object, it
has to define an :meth:`__index__` method that returns an integer. Some
examples:
>>> bin(3)
'0b11'
>>> bin(-10)
'-0b1010'
If prefix "0b" is desired or not, you can use either of the following ways.
>>> format(14, '#b'), format(14, 'b')
('0b1110', '1110')
>>> f'{14:#b}', f'{14:b}'
('0b1110', '1110')
See also :func:`format` for more information.
.. class:: bool([x])
@ -635,16 +650,26 @@ are always available. They are listed here in alphabetical order.
.. function:: hex(x)
Convert an integer number to a lowercase hexadecimal string
prefixed with "0x", for example:
Convert an integer number to a lowercase hexadecimal string prefixed with
"0x". If x is not a Python :class:`int` object, it has to define an
__index__() method that returns an integer. Some examples:
>>> hex(255)
'0xff'
>>> hex(-42)
'-0x2a'
If x is not a Python :class:`int` object, it has to define an __index__()
method that returns an integer.
If you want to convert an integer number to an uppercase or lower hexadecimal
string with prefix or not, you can use either of the following ways:
>>> '%#x' % 255, '%x' % 255, '%X' % 255
('0xff', 'ff', 'FF')
>>> format(255, '#x'), format(255, 'x'), format(255, 'X')
('0xff', 'ff', 'FF')
>>> f'{255:#x}', f'{255:x}', f'{255:X}'
('0xff', 'ff', 'FF')
See also :func:`format` for more information.
See also :func:`int` for converting a hexadecimal string to an
integer using a base of 16.
@ -878,10 +903,27 @@ are always available. They are listed here in alphabetical order.
.. function:: oct(x)
Convert an integer number to an octal string. The result is a valid Python
expression. If *x* is not a Python :class:`int` object, it has to define an
:meth:`__index__` method that returns an integer.
Convert an integer number to an octal string prefixed with "0o". The result
is a valid Python expression. If *x* is not a Python :class:`int` object, it
has to define an :meth:`__index__` method that returns an integer. For
example:
>>> oct(8)
'0o10'
>>> oct(-56)
'-0o70'
If you want to convert an integer number to octal string either with prefix
"0o" or not, you can use either of the following ways.
>>> '%#o' % 10, '%o' % 10
('0o12', '12')
>>> format(10, '#o'), format(10, 'o')
('0o12', '12')
>>> f'{10:#o}', f'{10:o}'
('0o12', '12')
See also :func:`format` for more information.
.. index::
single: file object; open() built-in function