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Fixed comparison: i < k < j should be i <= k < j.

This commit is contained in:
Guido van Rossum 1992-06-03 17:58:43 +00:00
parent c7ff85d612
commit 54e39908d8
2 changed files with 2 additions and 2 deletions
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2
Doc/ref.tex
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@ -674,7 +674,7 @@ the numbers $0, 1, \ldots, n-1$. Element \verb\i\ of sequence
\index{subscription} \index{subscription}
Sequences also support slicing: \verb\a[i:j]\ selects all elements Sequences also support slicing: \verb\a[i:j]\ selects all elements
with index $k$ such that $i < k < j$. When used as an expression, with index $k$ such that $i <= k < j$. When used as an expression,
a slice is a sequence of the same type --- this implies that the a slice is a sequence of the same type --- this implies that the
index set is renumbered so that it starts at 0 again. index set is renumbered so that it starts at 0 again.
\index{slicing} \index{slicing}

2
Doc/ref/ref.tex
View File

@ -674,7 +674,7 @@ the numbers $0, 1, \ldots, n-1$. Element \verb\i\ of sequence
\index{subscription} \index{subscription}
Sequences also support slicing: \verb\a[i:j]\ selects all elements Sequences also support slicing: \verb\a[i:j]\ selects all elements
with index $k$ such that $i < k < j$. When used as an expression, with index $k$ such that $i <= k < j$. When used as an expression,
a slice is a sequence of the same type --- this implies that the a slice is a sequence of the same type --- this implies that the
index set is renumbered so that it starts at 0 again. index set is renumbered so that it starts at 0 again.
\index{slicing} \index{slicing}