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fix typo in keyword argument 'allow_frament' should be 'allow_fragment'

This commit is contained in:
Jeremy Hylton 1998-08-25 19:45:24 +00:00
parent afd3daedde
commit 4722da6ebf
1 changed files with 6 additions and 6 deletions
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12
Lib/urlparse.py
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@ -43,8 +43,8 @@ def clear_cache():
# Return a 6-tuple: (scheme, netloc, path, params, query, fragment).
# Note that we don't break the components up in smaller bits
# (e.g. netloc is a single string) and we don't expand % escapes.
def urlparse(url, scheme = '', allow_framents = 1):
key = url, scheme, allow_framents
def urlparse(url, scheme = '', allow_fragments = 1):
key = url, scheme, allow_fragments
try:
return _parse_cache[key]
except KeyError:
@ -65,7 +65,7 @@ def urlparse(url, scheme = '', allow_framents = 1):
if i < 0:
i = len(url)
netloc, url = url[2:i], url[i:]
if allow_framents and scheme in uses_fragment:
if allow_fragments and scheme in uses_fragment:
i = string.rfind(url, '#')
if i >= 0:
url, fragment = url[:i], url[i+1:]
@ -101,13 +101,13 @@ def urlunparse((scheme, netloc, url, params, query, fragment)):
# Join a base URL and a possibly relative URL to form an absolute
# interpretation of the latter.
def urljoin(base, url, allow_framents = 1):
def urljoin(base, url, allow_fragments = 1):
if not base:
return url
bscheme, bnetloc, bpath, bparams, bquery, bfragment = \
urlparse(base, '', allow_framents)
urlparse(base, '', allow_fragments)
scheme, netloc, path, params, query, fragment = \
urlparse(url, bscheme, allow_framents)
urlparse(url, bscheme, allow_fragments)
# XXX Unofficial hack: default netloc to bnetloc even if
# schemes differ
if scheme != bscheme and not netloc and \