Pickles have a number of storage formats for various sizes and kinds of
integers, but the std tests don't exercise most of them. Repair that. CAUTION: I expect this to fail on boxes with sizeof(long)==8, in the part of test_cpickle (but not test_pickle) trying to do a binary mode (not text mode) load of the embedded BINDATA pickle string. Once that hypothesized failure is confirmed, I'll fix cPickle.c.
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parent
29fd0317ba
commit
461922a005
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@ -1,26 +1,37 @@
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# test_pickle and test_cpickle both use this.
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# break into multiple strings to please font-lock-mode
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DATA = """(lp0
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DATA = """(lp1
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I0
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aL1L
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aF2.0
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aF2
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ac__builtin__
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complex
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p1
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""" \
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"""(F3.0
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F0.0
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tp2
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Rp3
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a(S'abc'
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p2
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""" + \
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"""(F3
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F0
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tRp3
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aI1
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aI-1
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aI255
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aI-255
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aI-256
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aI65535
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aI-65535
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aI-65536
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aI2147483647
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aI-2147483647
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aI-2147483648
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a""" + \
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"""(S'abc'
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p4
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g4
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""" \
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"""(i__main__
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""" + \
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"""(ipickletester
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C
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p5
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""" \
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""" + \
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"""(dp6
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S'foo'
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p7
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@ -35,7 +46,14 @@ aI5
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a.
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"""
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BINDATA = ']q\000(K\000L1L\012G@\000\000\000\000\000\000\000c__builtin__\012complex\012q\001(G@\010\000\000\000\000\000\000G\000\000\000\000\000\000\000\000tq\002Rq\003(U\003abcq\004h\004(c__main__\012C\012q\005oq\006}q\007(U\003fooq\010K\001U\003barq\011K\002ubh\006tq\012h\012K\005e.'
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BINDATA = ']q\x01(K\x00L1L\nG@\x00\x00\x00\x00\x00\x00\x00' + \
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'c__builtin__\ncomplex\nq\x02(G@\x08\x00\x00\x00\x00\x00' + \
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'\x00G\x00\x00\x00\x00\x00\x00\x00\x00tRq\x03K\x01J\xff\xff' + \
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'\xff\xffK\xffJ\x01\xff\xff\xffJ\x00\xff\xff\xffM\xff\xff' + \
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'J\x01\x00\xff\xffJ\x00\x00\xff\xffJ\xff\xff\xff\x7fJ\x01\x00' + \
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'\x00\x80J\x00\x00\x00\x80(U\x03abcq\x04h\x04(cpickletester\n' + \
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'C\nq\x05oq\x06}q\x07(U\x03fooq\x08K\x01U\x03barq\tK\x02ubh' + \
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'\x06tq\nh\nK\x05e.'
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class C:
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def __cmp__(self, other):
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c.foo = 1
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c.bar = 2
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x = [0, 1L, 2.0, 3.0+0j]
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# Append some integer test cases at cPickle.c's internal size
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# cutoffs.
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uint1max = 0xff
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uint2max = 0xffff
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int4max = 0x7fffffff
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x.extend([1, -1,
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uint1max, -uint1max, -uint1max-1,
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uint2max, -uint2max, -uint2max-1,
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int4max, -int4max, -int4max-1])
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y = ('abc', 'abc', c, c)
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x.append(y)
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x.append(y)
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