#8267: Use sorted() to get a sorted list of dict keys.

This commit is contained in:
Georg Brandl 2010-10-15 15:31:09 +00:00
parent a81eae1fd7
commit 44c3ceb8ac
2 changed files with 5 additions and 5 deletions

View File

@ -431,9 +431,9 @@ function like this::
print "-- I'm sorry, we're all out of", kind
for arg in arguments: print arg
print "-" * 40
keys = keywords.keys()
keys.sort()
for kw in keys: print kw, ":", keywords[kw]
keys = sorted(keywords.keys())
for kw in keys:
print kw, ":", keywords[kw]
It could be called like this::

View File

@ -481,8 +481,8 @@ using a non-existent key.
The :meth:`keys` method of a dictionary object returns a list of all the keys
used in the dictionary, in arbitrary order (if you want it sorted, just apply
the :meth:`sort` method to the list of keys). To check whether a single key is
in the dictionary, use the :keyword:`in` keyword.
the :func:`sorted` function to it). To check whether a single key is in the
dictionary, use the :keyword:`in` keyword.
Here is a small example using a dictionary::