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Issue #17041: Fix doctesting when Python is configured with the 

--without-doc-strings.
This commit is contained in:
Serhiy Storchaka 2013-01-31 16:11:28 +02:00
parent cc9e5369d3 9a11f17673
commit 3ff4571af3
2 changed files with 4 additions and 2 deletions
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3
Lib/test/test_generators.py
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@ -383,7 +383,8 @@ From the Iterators list, about the types of these things.
<class 'generator'> <class 'generator'>
>>> [s for s in dir(i) if not s.startswith('_')] >>> [s for s in dir(i) if not s.startswith('_')]
['close', 'gi_code', 'gi_frame', 'gi_running', 'send', 'throw'] ['close', 'gi_code', 'gi_frame', 'gi_running', 'send', 'throw']
>>> print(i.__next__.__doc__) >>> from test.support import HAVE_DOCSTRINGS
>>> print(i.__next__.__doc__ if HAVE_DOCSTRINGS else 'x.__next__() <==> next(x)')
x.__next__() <==> next(x) x.__next__() <==> next(x)
>>> iter(i) is i >>> iter(i) is i
True True

3
Lib/test/test_genexps.py
View File

@ -221,7 +221,8 @@ Check that generator attributes are present
>>> set(attr for attr in dir(g) if not attr.startswith('__')) >= expected >>> set(attr for attr in dir(g) if not attr.startswith('__')) >= expected
True True
>>> print(g.__next__.__doc__) >>> from test.support import HAVE_DOCSTRINGS
>>> print(g.__next__.__doc__ if HAVE_DOCSTRINGS else 'x.__next__() <==> next(x)')
x.__next__() <==> next(x) x.__next__() <==> next(x)
>>> import types >>> import types
>>> isinstance(g, types.GeneratorType) >>> isinstance(g, types.GeneratorType)