traverseda
/
cpython
1
0
Fork 0
Code Issues Pull Requests Releases Wiki Activity

Explained that os.path.basename() may return something different from the 

basename program, as suggested by Gregor Hoffleit <gregor@hoffleit.de>.

This closes bug #119485.
This commit is contained in:
Fred Drake 2000-10-26 21:38:23 +00:00
parent 4532dc1bd9
commit 3aecfc9681
1 changed files with 5 additions and 1 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

6
Doc/lib/libposixpath.tex
View File

@ -17,7 +17,11 @@ On most platforms, this is equivalent to
\begin{funcdesc}{basename}{path}
Return the base name of pathname \var{path}. This is the second half
of the pair returned by \code{split(\var{path})}.
of the pair returned by \code{split(\var{path})}. Note that the
result of this function is different from the
\UNIX{} \program{basename} program; where \program{basename} for
\code{'/foo/bar/'} returns \code{'bar'}, the \function{basename()}
function returns an empty string (\code{''}).
\end{funcdesc}
\begin{funcdesc}{commonprefix}{list}