Issue #26130: Remove redundant variable 's' from Parser/parser.c
Patch by Oren Milman.
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parent
5a6c018b57
commit
2a65ecb780
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@ -140,21 +140,20 @@ classify(parser_state *ps, int type, const char *str)
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int n = g->g_ll.ll_nlabels;
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int n = g->g_ll.ll_nlabels;
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if (type == NAME) {
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if (type == NAME) {
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const char *s = str;
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label *l = g->g_ll.ll_label;
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label *l = g->g_ll.ll_label;
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int i;
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int i;
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for (i = n; i > 0; i--, l++) {
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for (i = n; i > 0; i--, l++) {
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if (l->lb_type != NAME || l->lb_str == NULL ||
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if (l->lb_type != NAME || l->lb_str == NULL ||
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l->lb_str[0] != s[0] ||
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l->lb_str[0] != str[0] ||
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strcmp(l->lb_str, s) != 0)
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strcmp(l->lb_str, str) != 0)
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continue;
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continue;
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#ifdef PY_PARSER_REQUIRES_FUTURE_KEYWORD
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#ifdef PY_PARSER_REQUIRES_FUTURE_KEYWORD
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#if 0
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#if 0
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/* Leaving this in as an example */
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/* Leaving this in as an example */
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if (!(ps->p_flags & CO_FUTURE_WITH_STATEMENT)) {
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if (!(ps->p_flags & CO_FUTURE_WITH_STATEMENT)) {
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if (s[0] == 'w' && strcmp(s, "with") == 0)
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if (str[0] == 'w' && strcmp(str, "with") == 0)
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break; /* not a keyword yet */
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break; /* not a keyword yet */
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else if (s[0] == 'a' && strcmp(s, "as") == 0)
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else if (str[0] == 'a' && strcmp(str, "as") == 0)
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break; /* not a keyword yet */
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break; /* not a keyword yet */
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}
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}
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#endif
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#endif
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