Issue #26130: Remove redundant variable 's' from Parser/parser.c
Patch by Oren Milman.
This commit is contained in:
parent
5a6c018b57
commit
2a65ecb780
|
@ -140,21 +140,20 @@ classify(parser_state *ps, int type, const char *str)
|
|||
int n = g->g_ll.ll_nlabels;
|
||||
|
||||
if (type == NAME) {
|
||||
const char *s = str;
|
||||
label *l = g->g_ll.ll_label;
|
||||
int i;
|
||||
for (i = n; i > 0; i--, l++) {
|
||||
if (l->lb_type != NAME || l->lb_str == NULL ||
|
||||
l->lb_str[0] != s[0] ||
|
||||
strcmp(l->lb_str, s) != 0)
|
||||
l->lb_str[0] != str[0] ||
|
||||
strcmp(l->lb_str, str) != 0)
|
||||
continue;
|
||||
#ifdef PY_PARSER_REQUIRES_FUTURE_KEYWORD
|
||||
#if 0
|
||||
/* Leaving this in as an example */
|
||||
if (!(ps->p_flags & CO_FUTURE_WITH_STATEMENT)) {
|
||||
if (s[0] == 'w' && strcmp(s, "with") == 0)
|
||||
if (str[0] == 'w' && strcmp(str, "with") == 0)
|
||||
break; /* not a keyword yet */
|
||||
else if (s[0] == 'a' && strcmp(s, "as") == 0)
|
||||
else if (str[0] == 'a' && strcmp(str, "as") == 0)
|
||||
break; /* not a keyword yet */
|
||||
}
|
||||
#endif
|
||||
|
|
Loading…
Reference in New Issue