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PyUnicode_IS_ASCII() macro ensures that the string is ready 

It has no sense to check if a not ready string is ASCII or not.
This commit is contained in:
Victor Stinner 2011-12-12 01:24:20 +01:00
parent c4b495497a
commit 24c74be9a3
1 changed files with 7 additions and 5 deletions
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10
Include/unicodeobject.h
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@ -424,10 +424,12 @@ PyAPI_DATA(PyTypeObject) PyUnicodeIter_Type;
#define SSTATE_INTERNED_IMMORTAL 2
/* Return true if the string contains only ASCII characters, or 0 if not. The
string may be compact (PyUnicode_IS_COMPACT_ASCII) or not. No type checks
or Ready calls are performed. */
string may be compact (PyUnicode_IS_COMPACT_ASCII) or not, but must be
ready. */
#define PyUnicode_IS_ASCII(op) \
(((PyASCIIObject*)op)->state.ascii)
(assert(PyUnicode_Check(op)), \
assert(PyUnicode_IS_READY(op)), \
((PyASCIIObject*)op)->state.ascii)
/* Return true if the string is compact or 0 if not.
No type checks or Ready calls are performed. */
@ -437,7 +439,7 @@ PyAPI_DATA(PyTypeObject) PyUnicodeIter_Type;
/* Return true if the string is a compact ASCII string (use PyASCIIObject
structure), or 0 if not. No type checks or Ready calls are performed. */
#define PyUnicode_IS_COMPACT_ASCII(op) \
(PyUnicode_IS_ASCII(op) && PyUnicode_IS_COMPACT(op))
(((PyASCIIObject*)op)->state.ascii && PyUnicode_IS_COMPACT(op))
enum PyUnicode_Kind {
/* String contains only wstr byte characters. This is only possible