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On path with known exact float, extract the double with the fast macro. (GH-21072) 

(cherry picked from commit 930f4518ae)

Co-authored-by: Raymond Hettinger <rhettinger@users.noreply.github.com>
This commit is contained in:
Miss Islington (bot) 2020-09-04 16:12:48 -07:00 committed by GitHub
parent e92219d8f8
commit 242eac1f04
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GPG Key ID: 4AEE18F83AFDEB23
1 changed files with 10 additions and 5 deletions
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15
Modules/mathmodule.c
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@ -1255,9 +1255,15 @@ static PyObject *
math_floor(PyObject *module, PyObject *number)
/*[clinic end generated code: output=c6a65c4884884b8a input=63af6b5d7ebcc3d6]*/
{
double x;
_Py_IDENTIFIER(__floor__);
if (!PyFloat_CheckExact(number)) {
if (PyFloat_CheckExact(number)) {
x = PyFloat_AS_DOUBLE(number);
}
else
{
PyObject *method = _PyObject_LookupSpecial(number, &PyId___floor__);
if (method != NULL) {
PyObject *result = _PyObject_CallNoArg(method);
@ -1266,11 +1272,10 @@ math_floor(PyObject *module, PyObject *number)
}
if (PyErr_Occurred())
return NULL;
x = PyFloat_AsDouble(number);
if (x == -1.0 && PyErr_Occurred())
return NULL;
}
double x = PyFloat_AsDouble(number);
if (x == -1.0 && PyErr_Occurred())
return NULL;
return PyLong_FromDouble(floor(x));
}