Issue 21424: Apply the nlargest() optimizations to nsmallest() as well.
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3a17e21755
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234fb2d503
154
Lib/heapq.py
154
Lib/heapq.py
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@ -127,7 +127,7 @@ From all times, sorting has always been a Great Art! :-)
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__all__ = ['heappush', 'heappop', 'heapify', 'heapreplace', 'merge',
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'nlargest', 'nsmallest', 'heappushpop']
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from itertools import islice, count, tee, chain
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from itertools import islice, count
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def heappush(heap, item):
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"""Push item onto heap, maintaining the heap invariant."""
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@ -179,12 +179,12 @@ def heapify(x):
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for i in reversed(range(n//2)):
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_siftup(x, i)
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def _heappushpop_max(heap, item):
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"""Maxheap version of a heappush followed by a heappop."""
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if heap and item < heap[0]:
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item, heap[0] = heap[0], item
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def _heapreplace_max(heap, item):
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"""Maxheap version of a heappop followed by a heappush."""
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returnitem = heap[0] # raises appropriate IndexError if heap is empty
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heap[0] = item
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_siftup_max(heap, 0)
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return item
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return returnitem
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def _heapify_max(x):
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"""Transform list into a maxheap, in-place, in O(len(x)) time."""
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@ -192,24 +192,6 @@ def _heapify_max(x):
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for i in reversed(range(n//2)):
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_siftup_max(x, i)
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def nsmallest(n, iterable):
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"""Find the n smallest elements in a dataset.
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Equivalent to: sorted(iterable)[:n]
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"""
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if n <= 0:
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return []
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it = iter(iterable)
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result = list(islice(it, n))
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if not result:
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return result
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_heapify_max(result)
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_heappushpop = _heappushpop_max
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for elem in it:
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_heappushpop(result, elem)
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result.sort()
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return result
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# 'heap' is a heap at all indices >= startpos, except possibly for pos. pos
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# is the index of a leaf with a possibly out-of-order value. Restore the
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# heap invariant.
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@ -327,6 +309,10 @@ try:
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from _heapq import *
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except ImportError:
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pass
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try:
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from _heapq import _heapreplace_max
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except ImportError:
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pass
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def merge(*iterables):
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'''Merge multiple sorted inputs into a single sorted output.
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@ -367,22 +353,86 @@ def merge(*iterables):
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yield v
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yield from next.__self__
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# Extend the implementations of nsmallest and nlargest to use a key= argument
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_nsmallest = nsmallest
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# Algorithm notes for nlargest() and nsmallest()
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# ==============================================
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#
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# Makes just a single pass over the data while keeping the k most extreme values
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# in a heap. Memory consumption is limited to keeping k values in a list.
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#
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# Measured performance for random inputs:
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#
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# number of comparisons
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# n inputs k-extreme values (average of 5 trials) % more than min()
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# ------------- ---------------- - ------------------- -----------------
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# 1,000 100 3,317 133.2%
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# 10,000 100 14,046 40.5%
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# 100,000 100 105,749 5.7%
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# 1,000,000 100 1,007,751 0.8%
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# 10,000,000 100 10,009,401 0.1%
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#
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# Theoretical number of comparisons for k smallest of n random inputs:
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#
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# Step Comparisons Action
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# ---- -------------------------- ---------------------------
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# 1 1.66 * k heapify the first k-inputs
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# 2 n - k compare remaining elements to top of heap
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# 3 k * (1 + lg2(k)) * ln(n/k) replace the topmost value on the heap
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# 4 k * lg2(k) - (k/2) final sort of the k most extreme values
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# Combining and simplifying for a rough estimate gives:
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# comparisons = n + k * (1 + log(n/k)) * (1 + log(k, 2))
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#
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# Computing the number of comparisons for step 3:
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# -----------------------------------------------
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# * For the i-th new value from the iterable, the probability of being in the
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# k most extreme values is k/i. For example, the probability of the 101st
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# value seen being in the 100 most extreme values is 100/101.
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# * If the value is a new extreme value, the cost of inserting it into the
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# heap is 1 + log(k, 2).
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# * The probabilty times the cost gives:
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# (k/i) * (1 + log(k, 2))
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# * Summing across the remaining n-k elements gives:
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# sum((k/i) * (1 + log(k, 2)) for xrange(k+1, n+1))
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# * This reduces to:
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# (H(n) - H(k)) * k * (1 + log(k, 2))
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# * Where H(n) is the n-th harmonic number estimated by:
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# gamma = 0.5772156649
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# H(n) = log(n, e) + gamma + 1.0 / (2.0 * n)
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# http://en.wikipedia.org/wiki/Harmonic_series_(mathematics)#Rate_of_divergence
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# * Substituting the H(n) formula:
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# comparisons = k * (1 + log(k, 2)) * (log(n/k, e) + (1/n - 1/k) / 2)
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#
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# Worst-case for step 3:
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# ----------------------
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# In the worst case, the input data is reversed sorted so that every new element
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# must be inserted in the heap:
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#
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# comparisons = 1.66 * k + log(k, 2) * (n - k)
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#
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# Alternative Algorithms
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# ----------------------
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# Other algorithms were not used because they:
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# 1) Took much more auxiliary memory,
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# 2) Made multiple passes over the data.
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# 3) Made more comparisons in common cases (small k, large n, semi-random input).
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# See the more detailed comparison of approach at:
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# http://code.activestate.com/recipes/577573-compare-algorithms-for-heapqsmallest
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def nsmallest(n, iterable, key=None):
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"""Find the n smallest elements in a dataset.
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Equivalent to: sorted(iterable, key=key)[:n]
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"""
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# Short-cut for n==1 is to use min() when len(iterable)>0
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if n == 1:
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it = iter(iterable)
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head = list(islice(it, 1))
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if not head:
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return []
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sentinel = object()
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if key is None:
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return [min(chain(head, it))]
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return [min(chain(head, it), key=key)]
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result = min(it, default=sentinel)
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else:
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result = min(it, default=sentinel, key=key)
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return [] if result is sentinel else [result]
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# When n>=size, it's faster to use sorted()
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try:
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@ -395,15 +445,39 @@ def nsmallest(n, iterable, key=None):
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# When key is none, use simpler decoration
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if key is None:
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it = zip(iterable, count()) # decorate
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result = _nsmallest(n, it)
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return [r[0] for r in result] # undecorate
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it = iter(iterable)
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result = list(islice(zip(it, count()), n))
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if not result:
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return result
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_heapify_max(result)
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order = n
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top = result[0][0]
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_heapreplace = _heapreplace_max
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for elem in it:
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if elem < top:
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_heapreplace(result, (elem, order))
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top = result[0][0]
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order += 1
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result.sort()
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return [r[0] for r in result]
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# General case, slowest method
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in1, in2 = tee(iterable)
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it = zip(map(key, in1), count(), in2) # decorate
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result = _nsmallest(n, it)
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return [r[2] for r in result] # undecorate
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it = iter(iterable)
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result = [(key(elem), i, elem) for i, elem in zip(range(n), it)]
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if not result:
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return result
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_heapify_max(result)
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order = n
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top = result[0][0]
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_heapreplace = _heapreplace_max
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for elem in it:
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k = key(elem)
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if k < top:
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_heapreplace(result, (k, order, elem))
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top = result[0][0]
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order += 1
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result.sort()
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return [r[2] for r in result]
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def nlargest(n, iterable, key=None):
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"""Find the n largest elements in a dataset.
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@ -442,9 +516,9 @@ def nlargest(n, iterable, key=None):
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_heapreplace = heapreplace
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for elem in it:
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if top < elem:
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order -= 1
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_heapreplace(result, (elem, order))
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top = result[0][0]
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order -= 1
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result.sort(reverse=True)
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return [r[0] for r in result]
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@ -460,9 +534,9 @@ def nlargest(n, iterable, key=None):
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for elem in it:
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k = key(elem)
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if top < k:
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order -= 1
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_heapreplace(result, (k, order, elem))
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top = result[0][0]
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order -= 1
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result.sort(reverse=True)
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return [r[2] for r in result]
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@ -13,7 +13,7 @@ c_heapq = support.import_fresh_module('heapq', fresh=['_heapq'])
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# _heapq.nlargest/nsmallest are saved in heapq._nlargest/_smallest when
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# _heapq is imported, so check them there
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func_names = ['heapify', 'heappop', 'heappush', 'heappushpop',
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'heapreplace', '_nsmallest']
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'heapreplace', '_heapreplace_max']
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class TestModules(TestCase):
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def test_py_functions(self):
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@ -84,8 +84,8 @@ Library
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- Issue #21156: importlib.abc.InspectLoader.source_to_code() is now a
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staticmethod.
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- Issue #21424: Simplified and optimized heaqp.nlargest() to make fewer
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tuple comparisons.
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- Issue #21424: Simplified and optimized heaqp.nlargest() and nmsmallest()
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to make fewer tuple comparisons.
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- Issue #21396: Fix TextIOWrapper(..., write_through=True) to not force a
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flush() on the underlying binary stream. Patch by akira.
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@ -354,88 +354,34 @@ _siftupmax(PyListObject *heap, Py_ssize_t pos)
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}
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static PyObject *
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nsmallest(PyObject *self, PyObject *args)
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_heapreplace_max(PyObject *self, PyObject *args)
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{
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PyObject *heap=NULL, *elem, *iterable, *los, *it, *oldelem;
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Py_ssize_t i, n;
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int cmp;
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PyObject *heap, *item, *returnitem;
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if (!PyArg_ParseTuple(args, "nO:nsmallest", &n, &iterable))
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if (!PyArg_UnpackTuple(args, "_heapreplace_max", 2, 2, &heap, &item))
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return NULL;
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it = PyObject_GetIter(iterable);
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if (it == NULL)
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if (!PyList_Check(heap)) {
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PyErr_SetString(PyExc_TypeError, "heap argument must be a list");
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return NULL;
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heap = PyList_New(0);
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if (heap == NULL)
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goto fail;
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for (i=0 ; i<n ; i++ ){
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elem = PyIter_Next(it);
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if (elem == NULL) {
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if (PyErr_Occurred())
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goto fail;
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else
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goto sortit;
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}
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if (PyList_Append(heap, elem) == -1) {
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Py_DECREF(elem);
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goto fail;
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}
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Py_DECREF(elem);
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}
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n = PyList_GET_SIZE(heap);
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if (n == 0)
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goto sortit;
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for (i=n/2-1 ; i>=0 ; i--)
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if(_siftupmax((PyListObject *)heap, i) == -1)
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goto fail;
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los = PyList_GET_ITEM(heap, 0);
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while (1) {
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elem = PyIter_Next(it);
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if (elem == NULL) {
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if (PyErr_Occurred())
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goto fail;
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else
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goto sortit;
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}
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cmp = PyObject_RichCompareBool(elem, los, Py_LT);
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if (cmp == -1) {
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Py_DECREF(elem);
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goto fail;
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}
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if (cmp == 0) {
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Py_DECREF(elem);
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continue;
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}
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oldelem = PyList_GET_ITEM(heap, 0);
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PyList_SET_ITEM(heap, 0, elem);
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Py_DECREF(oldelem);
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if (_siftupmax((PyListObject *)heap, 0) == -1)
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goto fail;
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los = PyList_GET_ITEM(heap, 0);
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}
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sortit:
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if (PyList_Sort(heap) == -1)
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goto fail;
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Py_DECREF(it);
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return heap;
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fail:
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Py_DECREF(it);
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Py_XDECREF(heap);
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if (PyList_GET_SIZE(heap) < 1) {
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PyErr_SetString(PyExc_IndexError, "index out of range");
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return NULL;
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}
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returnitem = PyList_GET_ITEM(heap, 0);
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Py_INCREF(item);
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PyList_SET_ITEM(heap, 0, item);
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if (_siftupmax((PyListObject *)heap, 0) == -1) {
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Py_DECREF(returnitem);
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return NULL;
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}
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return returnitem;
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}
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PyDoc_STRVAR(nsmallest_doc,
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"Find the n smallest elements in a dataset.\n\
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\n\
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Equivalent to: sorted(iterable)[:n]\n");
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PyDoc_STRVAR(heapreplace_max_doc, "Maxheap variant of heapreplace");
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static PyMethodDef heapq_methods[] = {
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{"heappush", (PyCFunction)heappush,
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METH_VARARGS, heapreplace_doc},
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{"heapify", (PyCFunction)heapify,
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METH_O, heapify_doc},
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{"nsmallest", (PyCFunction)nsmallest,
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METH_VARARGS, nsmallest_doc},
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{"_heapreplace_max",(PyCFunction)_heapreplace_max,
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METH_VARARGS, heapreplace_max_doc},
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{NULL, NULL} /* sentinel */
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};
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