Implement round() slightly different, so that for negative ndigits no
additional errors happen in the last step. The trick is to avoid division by 0.1**n -- multiply by 10.0**n instead.
This commit is contained in:
parent
ae94cf292b
commit
1e162d3753
|
@ -1488,14 +1488,22 @@ builtin_round(self, args)
|
|||
if (!PyArg_ParseTuple(args, "d|i:round", &x, &ndigits))
|
||||
return NULL;
|
||||
f = 1.0;
|
||||
for (i = ndigits; --i >= 0; )
|
||||
i = abs(ndigits);
|
||||
while (--i >= 0)
|
||||
f = f*10.0;
|
||||
for (i = ndigits; ++i <= 0; )
|
||||
f = f*0.1;
|
||||
if (x >= 0.0)
|
||||
return PyFloat_FromDouble(floor(x*f + 0.5) / f);
|
||||
if (ndigits < 0)
|
||||
x /= f;
|
||||
else
|
||||
return PyFloat_FromDouble(ceil(x*f - 0.5) / f);
|
||||
x *= f;
|
||||
if (x >= 0.0)
|
||||
x = floor(x + 0.5);
|
||||
else
|
||||
x = ceil(x - 0.5);
|
||||
if (ndigits < 0)
|
||||
x *= f;
|
||||
else
|
||||
x /= f;
|
||||
return PyFloat_FromDouble(x);
|
||||
}
|
||||
|
||||
static PyObject *
|
||||
|
|
Loading…
Reference in New Issue