Issue #6713: Improve performance of str(n) and repr(n) for integers n

(up to 3.1 times faster in tests), by special-casing base 10 in
_PyLong_Format.
This commit is contained in:
Mark Dickinson 2009-09-16 21:23:34 +00:00
parent 3360401980
commit 0a1efd0e4c
3 changed files with 122 additions and 0 deletions

View File

@ -50,12 +50,16 @@ typedef PY_INT32_T sdigit; /* signed variant of digit */
typedef PY_UINT64_T twodigits;
typedef PY_INT64_T stwodigits; /* signed variant of twodigits */
#define PyLong_SHIFT 30
#define _PyLong_DECIMAL_SHIFT 9 /* max(e such that 10**e fits in a digit) */
#define _PyLong_DECIMAL_BASE ((digit)1000000000) /* 10 ** DECIMAL_SHIFT */
#elif PYLONG_BITS_IN_DIGIT == 15
typedef unsigned short digit;
typedef short sdigit; /* signed variant of digit */
typedef unsigned long twodigits;
typedef long stwodigits; /* signed variant of twodigits */
#define PyLong_SHIFT 15
#define _PyLong_DECIMAL_SHIFT 4 /* max(e such that 10**e fits in a digit) */
#define _PyLong_DECIMAL_BASE ((digit)10000) /* 10 ** DECIMAL_SHIFT */
#else
#error "PYLONG_BITS_IN_DIGIT should be 15 or 30"
#endif

View File

@ -12,6 +12,8 @@ What's New in Python 3.2 Alpha 1?
Core and Builtins
-----------------
- Issue #6713: Improve performance of integer -> string conversions.
- Issue #6846: Fix bug where bytearray.pop() returns negative integers.
- Issue #6750: A text file opened with io.open() could duplicate its output

View File

@ -1650,6 +1650,119 @@ divrem1(PyLongObject *a, digit n, digit *prem)
return long_normalize(z);
}
/* Convert a long integer to a base 10 string. Returns a new non-shared
string. (Return value is non-shared so that callers can modify the
returned value if necessary.) */
static PyObject *
long_to_decimal_string(PyObject *aa)
{
PyLongObject *scratch, *a;
PyObject *str;
Py_ssize_t size, strlen, size_a, i, j;
digit *pout, *pin, rem, tenpow;
Py_UNICODE *p;
int negative;
a = (PyLongObject *)aa;
if (a == NULL || !PyLong_Check(a)) {
PyErr_BadInternalCall();
return NULL;
}
size_a = ABS(Py_SIZE(a));
negative = Py_SIZE(a) < 0;
/* quick and dirty upper bound for the number of digits
required to express a in base _PyLong_DECIMAL_BASE:
#digits = 1 + floor(log2(a) / log2(_PyLong_DECIMAL_BASE))
But log2(a) < size_a * PyLong_SHIFT, and
log2(_PyLong_DECIMAL_BASE) = log2(10) * _PyLong_DECIMAL_SHIFT
> 3 * _PyLong_DECIMAL_SHIFT
*/
if (size_a > PY_SSIZE_T_MAX / PyLong_SHIFT) {
PyErr_SetString(PyExc_OverflowError,
"long is too large to format");
return NULL;
}
/* the expression size_a * PyLong_SHIFT is now safe from overflow */
size = 1 + size_a * PyLong_SHIFT / (3 * _PyLong_DECIMAL_SHIFT);
scratch = _PyLong_New(size);
if (scratch == NULL)
return NULL;
/* convert array of base _PyLong_BASE digits in pin to an array of
base _PyLong_DECIMAL_BASE digits in pout, following Knuth (TAOCP,
Volume 2 (3rd edn), section 4.4, Method 1b). */
pin = a->ob_digit;
pout = scratch->ob_digit;
size = 0;
for (i = size_a; --i >= 0; ) {
digit hi = pin[i];
for (j = 0; j < size; j++) {
twodigits z = (twodigits)pout[j] << PyLong_SHIFT | hi;
hi = z / _PyLong_DECIMAL_BASE;
pout[j] = z - (twodigits)hi * _PyLong_DECIMAL_BASE;
}
while (hi) {
pout[size++] = hi % _PyLong_DECIMAL_BASE;
hi /= _PyLong_DECIMAL_BASE;
}
/* check for keyboard interrupt */
SIGCHECK({
Py_DECREF(scratch);
return NULL;
})
}
/* pout should have at least one digit, so that the case when a = 0
works correctly */
if (size == 0)
pout[size++] = 0;
/* calculate exact length of output string, and allocate */
strlen = negative + 1 + (size - 1) * _PyLong_DECIMAL_SHIFT;
tenpow = 10;
rem = pout[size-1];
while (rem >= tenpow) {
tenpow *= 10;
strlen++;
}
str = PyUnicode_FromUnicode(NULL, strlen);
if (str == NULL) {
Py_DECREF(scratch);
return NULL;
}
/* fill the string right-to-left */
p = PyUnicode_AS_UNICODE(str) + strlen;
*p = '\0';
/* pout[0] through pout[size-2] contribute exactly
_PyLong_DECIMAL_SHIFT digits each */
for (i=0; i < size - 1; i++) {
rem = pout[i];
for (j = 0; j < _PyLong_DECIMAL_SHIFT; j++) {
*--p = '0' + rem % 10;
rem /= 10;
}
}
/* pout[size-1]: always produce at least one decimal digit */
rem = pout[i];
do {
*--p = '0' + rem % 10;
rem /= 10;
} while (rem != 0);
/* and sign */
if (negative)
*--p = '-';
/* check we've counted correctly */
assert(p == PyUnicode_AS_UNICODE(str));
Py_DECREF(scratch);
return (PyObject *)str;
}
/* Convert a long int object to a string, using a given conversion base.
Return a string object.
If base is 2, 8 or 16, add the proper prefix '0b', '0o' or '0x'. */
@ -1665,6 +1778,9 @@ _PyLong_Format(PyObject *aa, int base)
int bits;
char sign = '\0';
if (base == 10)
return long_to_decimal_string((PyObject *)a);
if (a == NULL || !PyLong_Check(a)) {
PyErr_BadInternalCall();
return NULL;