Extend some comments on the order of values in the returns from
dict.items/keys/values/iteritems/iterkeys/itervalues().
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@ -1049,13 +1049,13 @@ arbitrary objects):
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{(6)}
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\lineiii{\var{a}.iteritems()}
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{return an iterator over (\var{key}, \var{value}) pairs}
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{(2)}
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{(2), (3)}
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\lineiii{\var{a}.iterkeys()}
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{return an iterator over the mapping's keys}
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{(2)}
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{(2), (3)}
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\lineiii{\var{a}.itervalues()}
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{return an iterator over the mapping's values}
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{(2)}
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{(2), (3)}
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\end{tableiii}
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\noindent
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@ -1067,11 +1067,17 @@ in the map.
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\item[(2)] \versionadded{2.2}
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\item[(3)] Keys and values are listed in random order. If
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\method{keys()} and \method{values()} are called with no intervening
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modifications to the dictionary, the two lists will directly
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correspond. This allows the creation of \code{(\var{value},
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\var{key})} pairs using \function{zip()}: \samp{pairs =
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zip(\var{a}.values(), \var{a}.keys())}.
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\method{items()}, \method{keys()}, \method{values()},
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\method{iteritems()}, \method{iterkeys()}, and \method{itervalues()}
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are called with no intervening modifications to the dictionary, the
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lists will directly correspond. This allows the creation of
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\code{(\var{value}, \var{key})} pairs using \function{zip()}:
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\samp{pairs = zip(\var{a}.values(), \var{a}.keys())}. The same
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relationship holds for the \method{iterkeys()} and
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\method{itervalues()} methods: \samp{pairs = zip(\var{a}.itervalues(),
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\var{a}.iterkeys())} provides the same value for \code{pairs}.
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Another way to create the same list is \samp{pairs = [(v, k) for (k,
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v) in \var{a}.iteritems()]}.
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\item[(4)] Never raises an exception if \var{k} is not in the map,
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instead it returns \var{x}. \var{x} is optional; when \var{x} is not
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