2010-03-11 18:53:45 -04:00
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#! /usr/bin/env python3
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1991-06-04 17:36:54 -03:00
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1991-12-18 09:45:17 -04:00
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# Factorize numbers.
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# The algorithm is not efficient, but easy to understand.
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# If there are large factors, it will take forever to find them,
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# because we try all odd numbers between 3 and sqrt(n)...
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1991-06-04 17:36:54 -03:00
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import sys
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from math import sqrt
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def fact(n):
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2009-10-10 18:57:03 -03:00
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if n < 1:
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raise ValueError('fact() argument should be >= 1')
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if n == 1:
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return [] # special case
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2004-07-18 02:56:09 -03:00
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res = []
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2009-10-10 18:57:03 -03:00
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# Treat even factors special, so we can use i += 2 later
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while n % 2 == 0:
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2004-07-18 02:56:09 -03:00
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res.append(2)
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2009-10-10 18:57:03 -03:00
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n //= 2
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2004-07-18 02:56:09 -03:00
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# Try odd numbers up to sqrt(n)
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2009-10-10 18:57:03 -03:00
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limit = sqrt(n+1)
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2004-07-18 02:56:09 -03:00
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i = 3
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while i <= limit:
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2009-10-10 18:57:03 -03:00
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if n % i == 0:
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2004-07-18 02:56:09 -03:00
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res.append(i)
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2009-10-10 18:57:03 -03:00
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n //= i
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2004-07-18 02:56:09 -03:00
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limit = sqrt(n+1)
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else:
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2009-10-10 18:57:03 -03:00
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i += 2
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2004-07-18 02:56:09 -03:00
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if n != 1:
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res.append(n)
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return res
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1991-06-04 17:36:54 -03:00
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def main():
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2004-07-18 02:56:09 -03:00
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if len(sys.argv) > 1:
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2009-10-10 18:57:03 -03:00
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source = sys.argv[1:]
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2004-07-18 02:56:09 -03:00
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else:
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2009-10-10 18:57:03 -03:00
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source = iter(input, '')
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for arg in source:
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2004-07-18 02:56:09 -03:00
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try:
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2009-10-10 18:57:03 -03:00
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n = int(arg)
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except ValueError:
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print(arg, 'is not an integer')
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else:
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print(n, fact(n))
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1991-06-04 17:36:54 -03:00
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2004-09-11 13:34:35 -03:00
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if __name__ == "__main__":
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main()
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