cpython/Demo/scripts/unbirthday.py

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#! /usr/local/bin/python
# Calculate your unbirthday count (see Alice in Wonderland).
# This is defined as the number of days from your birth until today
# that weren't your birthday. (The day you were born is not counted).
# Leap years make it interesting.
import sys
import time
import calendar
def main():
# Note that the range checks below also check for bad types,
# e.g. 3.14 or (). However syntactically invalid replies
# will raise an exception.
if sys.argv[1:]:
year = eval(sys.argv[1])
else:
year = input('In which year were you born? ')
if year in range(100):
print 'I\'ll assume that by', year,
year = year + 1900
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print 'you mean', year, 'and not the early Christian era'
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elif year not in range(1850, 2000):
print 'It\'s hard to believe you were born in', year
return
#
if sys.argv[2:]:
month = eval(sys.argv[2])
else:
month = input('And in which month? (1-12) ')
if month not in range(1, 13):
print 'There is no month numbered', month
return
#
if sys.argv[3:]:
day = eval(sys.argv[3])
else:
day = input('And on what day of that month? (1-31) ')
if month == 2 and calendar.isleap(year):
maxday = 29
else:
maxday = calendar.mdays[month]
if day not in range(1, maxday+1):
print 'There are no', day, 'days in that month!'
return
#
bdaytuple = (year, month, day)
bdaydate = mkdate(bdaytuple)
print 'You were born on', format(bdaytuple)
#
todaytuple = time.localtime(time.time())[:3]
todaydate = mkdate(todaytuple)
print 'Today is', format(todaytuple)
#
if bdaytuple > todaytuple:
print 'You are a time traveler. Go back to the future!'
return
#
if bdaytuple == todaytuple:
print 'You were born today. Have a nice life!'
return
#
days = todaydate - bdaydate
print 'You have lived', days, 'days'
#
age = 0
for y in range(year, todaytuple[0] + 1):
if bdaytuple < (y, month, day) <= todaytuple:
age = age + 1
#
print 'You are', age, 'years old'
#
if todaytuple[1:] == bdaytuple[1:]:
print 'Congratulations! Today is your', nth(age), 'birthday'
print 'Yesterday was your',
else:
print 'Today is your',
print nth(days - age), 'unbirthday'
def format((year, month, day)):
return '%d %s %d' % (day, calendar.month_name[month], year)
def nth(n):
if n == 1: return '1st'
if n == 2: return '2nd'
if n == 3: return '3rd'
return '%dth' % n
def mkdate((year, month, day)):
# Januari 1st, in 0 A.D. is arbitrarily defined to be day 1,
# even though that day never actually existed and the calendar
# was different then...
days = year*365 # years, roughly
days = days + (year+3)/4 # plus leap years, roughly
days = days - (year+99)/100 # minus non-leap years every century
days = days + (year+399)/400 # plus leap years every 4 centirues
for i in range(1, month):
if i == 2 and calendar.isleap(year):
days = days + 29
else:
days = days + calendar.mdays[i]
days = days + day
return days
main()