math Functions: exponential function with constraints

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Dennis Mannhart 2018-11-26 14:48:57 +01:00 committed by Daniel Agar
parent 80193cd227
commit 23afb939f0
1 changed files with 51 additions and 0 deletions

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@ -152,4 +152,55 @@ const T gradual(const T &value, const T &x_low, const T &x_high, const T &y_low,
}
}
/*
* Exponential function of the form Y_out = a*b^X + c
*
* Y_max | *
* | *
* | *
* | *
* | *
* Y_middle | *
* | *
* Y_min | * *
* | __________________________________
* 0 1 2
*
*
* @param X in the range [0,2]
* @param Y_min minimum output at X = 2
* @param Y_mid middle output at X = 1
* @param Y_max maximum output at X = 0
*/
template<typename T>
const T expontialFromLimits(const T &X, const T &Y_min, const T &Y_mid, const T &Y_max)
{
T SIGMA_NORM = (T)0.001;
// If Y_mid is exactly in the middle, then just apply linear approach.
bool use_linear_approach = false;
if (((Y_max + Y_min) * (T)0.5) - Y_mid < SIGMA_NORM) {
use_linear_approach = true;
}
T Y_out;
if (use_linear_approach) {
// Y_out = m*x+q
float slope = -(Y_max - Y_min) / (T)2.0;
Y_out = slope * X + Y_max;
} else {
// Y_out = a*b^X + c with constraints Y_max = 0, Y_middle = 1, Y_min = 2
T a = -((Y_mid - Y_max) * (Y_mid - Y_max))
/ ((T)2.0 * Y_mid - Y_max - Y_min);
T c = Y_max - a;
T b = (Y_mid - c) / a;
Y_out = a * powf(b, X) + c;
}
// Y_out needs to be in between max and min
return constrain(Y_out, Y_min, Y_max);
}
} /* namespace math */