mirror of https://github.com/python/cpython
528 lines
15 KiB
C
528 lines
15 KiB
C
/* -*- Mode: C; c-file-style: "python" -*- */
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#include <Python.h>
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#include <locale.h>
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/* ascii character tests (as opposed to locale tests) */
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#define ISSPACE(c) ((c) == ' ' || (c) == '\f' || (c) == '\n' || \
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(c) == '\r' || (c) == '\t' || (c) == '\v')
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#define ISDIGIT(c) ((c) >= '0' && (c) <= '9')
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/**
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* PyOS_ascii_strtod:
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* @nptr: the string to convert to a numeric value.
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* @endptr: if non-%NULL, it returns the character after
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* the last character used in the conversion.
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*
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* Converts a string to a #gdouble value.
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* This function behaves like the standard strtod() function
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* does in the C locale. It does this without actually
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* changing the current locale, since that would not be
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* thread-safe.
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*
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* This function is typically used when reading configuration
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* files or other non-user input that should be locale independent.
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* To handle input from the user you should normally use the
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* locale-sensitive system strtod() function.
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*
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* If the correct value would cause overflow, plus or minus %HUGE_VAL
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* is returned (according to the sign of the value), and %ERANGE is
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* stored in %errno. If the correct value would cause underflow,
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* zero is returned and %ERANGE is stored in %errno.
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* If memory allocation fails, %ENOMEM is stored in %errno.
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*
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* This function resets %errno before calling strtod() so that
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* you can reliably detect overflow and underflow.
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*
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* Return value: the #gdouble value.
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**/
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double
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PyOS_ascii_strtod(const char *nptr, char **endptr)
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{
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char *fail_pos;
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double val = -1.0;
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struct lconv *locale_data;
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const char *decimal_point;
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size_t decimal_point_len;
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const char *p, *decimal_point_pos;
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const char *end = NULL; /* Silence gcc */
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const char *digits_pos = NULL;
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int negate = 0;
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assert(nptr != NULL);
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fail_pos = NULL;
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locale_data = localeconv();
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decimal_point = locale_data->decimal_point;
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decimal_point_len = strlen(decimal_point);
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assert(decimal_point_len != 0);
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decimal_point_pos = NULL;
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/* We process any leading whitespace and the optional sign manually,
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then pass the remainder to the system strtod. This ensures that
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the result of an underflow has the correct sign. (bug #1725) */
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p = nptr;
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/* Skip leading space */
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while (ISSPACE(*p))
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p++;
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/* Process leading sign, if present */
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if (*p == '-') {
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negate = 1;
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p++;
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} else if (*p == '+') {
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p++;
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}
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/* What's left should begin with a digit, a decimal point, or one of
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the letters i, I, n, N. It should not begin with 0x or 0X */
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if ((!ISDIGIT(*p) &&
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*p != '.' && *p != 'i' && *p != 'I' && *p != 'n' && *p != 'N')
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||
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(*p == '0' && (p[1] == 'x' || p[1] == 'X')))
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{
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if (endptr)
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*endptr = (char*)nptr;
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errno = EINVAL;
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return val;
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}
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digits_pos = p;
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if (decimal_point[0] != '.' ||
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decimal_point[1] != 0)
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{
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while (ISDIGIT(*p))
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p++;
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if (*p == '.')
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{
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decimal_point_pos = p++;
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while (ISDIGIT(*p))
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p++;
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if (*p == 'e' || *p == 'E')
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p++;
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if (*p == '+' || *p == '-')
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p++;
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while (ISDIGIT(*p))
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p++;
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end = p;
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}
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else if (strncmp(p, decimal_point, decimal_point_len) == 0)
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{
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/* Python bug #1417699 */
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if (endptr)
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*endptr = (char*)nptr;
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errno = EINVAL;
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return val;
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}
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/* For the other cases, we need not convert the decimal
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point */
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}
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/* Set errno to zero, so that we can distinguish zero results
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and underflows */
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errno = 0;
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if (decimal_point_pos)
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{
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char *copy, *c;
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/* We need to convert the '.' to the locale specific decimal
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point */
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copy = (char *)PyMem_MALLOC(end - digits_pos +
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1 + decimal_point_len);
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if (copy == NULL) {
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if (endptr)
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*endptr = (char *)nptr;
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errno = ENOMEM;
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return val;
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}
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c = copy;
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memcpy(c, digits_pos, decimal_point_pos - digits_pos);
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c += decimal_point_pos - digits_pos;
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memcpy(c, decimal_point, decimal_point_len);
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c += decimal_point_len;
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memcpy(c, decimal_point_pos + 1,
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end - (decimal_point_pos + 1));
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c += end - (decimal_point_pos + 1);
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*c = 0;
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val = strtod(copy, &fail_pos);
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if (fail_pos)
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{
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if (fail_pos > decimal_point_pos)
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fail_pos = (char *)digits_pos +
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(fail_pos - copy) -
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(decimal_point_len - 1);
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else
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fail_pos = (char *)digits_pos +
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(fail_pos - copy);
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}
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PyMem_FREE(copy);
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}
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else {
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val = strtod(digits_pos, &fail_pos);
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}
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if (fail_pos == digits_pos)
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fail_pos = (char *)nptr;
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if (negate && fail_pos != nptr)
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val = -val;
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if (endptr)
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*endptr = fail_pos;
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return val;
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}
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/* Given a string that may have a decimal point in the current
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locale, change it back to a dot. Since the string cannot get
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longer, no need for a maximum buffer size parameter. */
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Py_LOCAL_INLINE(void)
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change_decimal_from_locale_to_dot(char* buffer)
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{
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struct lconv *locale_data = localeconv();
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const char *decimal_point = locale_data->decimal_point;
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if (decimal_point[0] != '.' || decimal_point[1] != 0) {
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size_t decimal_point_len = strlen(decimal_point);
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if (*buffer == '+' || *buffer == '-')
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buffer++;
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while (isdigit(Py_CHARMASK(*buffer)))
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buffer++;
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if (strncmp(buffer, decimal_point, decimal_point_len) == 0) {
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*buffer = '.';
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buffer++;
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if (decimal_point_len > 1) {
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/* buffer needs to get smaller */
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size_t rest_len = strlen(buffer +
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(decimal_point_len - 1));
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memmove(buffer,
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buffer + (decimal_point_len - 1),
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rest_len);
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buffer[rest_len] = 0;
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}
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}
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}
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}
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/* From the C99 standard, section 7.19.6:
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The exponent always contains at least two digits, and only as many more digits
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as necessary to represent the exponent.
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*/
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#define MIN_EXPONENT_DIGITS 2
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/* Ensure that any exponent, if present, is at least MIN_EXPONENT_DIGITS
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in length. */
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Py_LOCAL_INLINE(void)
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ensure_minumim_exponent_length(char* buffer, size_t buf_size)
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{
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char *p = strpbrk(buffer, "eE");
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if (p && (*(p + 1) == '-' || *(p + 1) == '+')) {
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char *start = p + 2;
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int exponent_digit_cnt = 0;
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int leading_zero_cnt = 0;
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int in_leading_zeros = 1;
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int significant_digit_cnt;
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/* Skip over the exponent and the sign. */
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p += 2;
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/* Find the end of the exponent, keeping track of leading
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zeros. */
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while (*p && isdigit(Py_CHARMASK(*p))) {
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if (in_leading_zeros && *p == '0')
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++leading_zero_cnt;
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if (*p != '0')
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in_leading_zeros = 0;
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++p;
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++exponent_digit_cnt;
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}
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significant_digit_cnt = exponent_digit_cnt - leading_zero_cnt;
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if (exponent_digit_cnt == MIN_EXPONENT_DIGITS) {
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/* If there are 2 exactly digits, we're done,
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regardless of what they contain */
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}
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else if (exponent_digit_cnt > MIN_EXPONENT_DIGITS) {
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int extra_zeros_cnt;
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/* There are more than 2 digits in the exponent. See
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if we can delete some of the leading zeros */
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if (significant_digit_cnt < MIN_EXPONENT_DIGITS)
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significant_digit_cnt = MIN_EXPONENT_DIGITS;
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extra_zeros_cnt = exponent_digit_cnt -
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significant_digit_cnt;
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/* Delete extra_zeros_cnt worth of characters from the
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front of the exponent */
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assert(extra_zeros_cnt >= 0);
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/* Add one to significant_digit_cnt to copy the
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trailing 0 byte, thus setting the length */
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memmove(start,
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start + extra_zeros_cnt,
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significant_digit_cnt + 1);
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}
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else {
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/* If there are fewer than 2 digits, add zeros
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until there are 2, if there's enough room */
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int zeros = MIN_EXPONENT_DIGITS - exponent_digit_cnt;
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if (start + zeros + exponent_digit_cnt + 1
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< buffer + buf_size) {
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memmove(start + zeros, start,
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exponent_digit_cnt + 1);
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memset(start, '0', zeros);
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}
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}
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}
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}
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/* Ensure that buffer has a decimal point in it. The decimal point
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will not be in the current locale, it will always be '.' */
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Py_LOCAL_INLINE(void)
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ensure_decimal_point(char* buffer, size_t buf_size)
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{
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int insert_count = 0;
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char* chars_to_insert;
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/* search for the first non-digit character */
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char *p = buffer;
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while (*p && isdigit(Py_CHARMASK(*p)))
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++p;
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if (*p == '.') {
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if (isdigit(Py_CHARMASK(*(p+1)))) {
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/* Nothing to do, we already have a decimal
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point and a digit after it */
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}
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else {
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/* We have a decimal point, but no following
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digit. Insert a zero after the decimal. */
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++p;
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chars_to_insert = "0";
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insert_count = 1;
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}
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}
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else {
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chars_to_insert = ".0";
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insert_count = 2;
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}
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if (insert_count) {
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size_t buf_len = strlen(buffer);
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if (buf_len + insert_count + 1 >= buf_size) {
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/* If there is not enough room in the buffer
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for the additional text, just skip it. It's
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not worth generating an error over. */
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}
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else {
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memmove(p + insert_count, p,
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buffer + strlen(buffer) - p + 1);
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memcpy(p, chars_to_insert, insert_count);
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}
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}
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}
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/* Add the locale specific grouping characters to buffer. Note
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that any decimal point (if it's present) in buffer is already
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locale-specific. Return 0 on error, else 1. */
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Py_LOCAL_INLINE(int)
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add_thousands_grouping(char* buffer, size_t buf_size)
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{
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struct lconv *locale_data = localeconv();
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const char *grouping = locale_data->grouping;
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const char *thousands_sep = locale_data->thousands_sep;
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size_t thousands_sep_len = strlen(thousands_sep);
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const char *decimal_point = locale_data->decimal_point;
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char *pend = buffer + strlen(buffer); /* current end of buffer */
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char *pmax = buffer + buf_size; /* max of buffer */
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char current_grouping;
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/* Find the decimal point, if any. We're only concerned
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about the characters to the left of the decimal when
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adding grouping. */
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char *p = strstr(buffer, decimal_point);
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if (!p) {
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/* No decimal, use the entire string. */
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/* If any exponent, adjust p. */
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p = strpbrk(buffer, "eE");
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if (!p)
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/* No exponent and no decimal. Use the entire
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string. */
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p = pend;
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}
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/* At this point, p points just past the right-most character we
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want to format. We need to add the grouping string for the
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characters between buffer and p. */
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/* Starting at p and working right-to-left, keep track of
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what grouping needs to be added and insert that. */
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current_grouping = *grouping++;
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/* If the first character is 0, perform no grouping at all. */
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if (current_grouping == 0)
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return 1;
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while (p - buffer > current_grouping) {
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/* Always leave buffer and pend valid at the end of this
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loop, since we might leave with a return statement. */
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/* Is there room to insert thousands_sep_len chars?. */
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if (pmax - pend <= thousands_sep_len)
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/* No room. */
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return 0;
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/* Move the rest of the string down. */
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p -= current_grouping;
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memmove(p + thousands_sep_len,
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p,
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pend - p + 1);
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/* Adjust end pointer. */
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pend += thousands_sep_len;
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/* Copy the thousands_sep chars into the buffer. */
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memcpy(p, thousands_sep, thousands_sep_len);
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/* Move to the next grouping character, unless we're
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repeating (which is designated by a grouping of 0). */
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if (*grouping != 0) {
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current_grouping = *grouping++;
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if (current_grouping == CHAR_MAX)
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/* We're done. */
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return 1;
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}
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}
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return 1;
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}
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/* see FORMATBUFLEN in unicodeobject.c */
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#define FLOAT_FORMATBUFLEN 120
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/**
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* PyOS_ascii_formatd:
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* @buffer: A buffer to place the resulting string in
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* @buf_size: The length of the buffer.
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* @format: The printf()-style format to use for the
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* code to use for converting.
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* @d: The #gdouble to convert
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*
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* Converts a #gdouble to a string, using the '.' as
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* decimal point. To format the number you pass in
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* a printf()-style format string. Allowed conversion
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* specifiers are 'e', 'E', 'f', 'F', 'g', 'G', and 'n'.
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*
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* 'n' is the same as 'g', except it uses the current locale.
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* 'Z' is the same as 'g', except it always has a decimal and
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* at least one digit after the decimal.
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*
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* Return value: The pointer to the buffer with the converted string.
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**/
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char *
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PyOS_ascii_formatd(char *buffer,
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size_t buf_size,
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const char *format,
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double d)
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{
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char format_char;
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size_t format_len = strlen(format);
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/* For type 'n', we need to make a copy of the format string, because
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we're going to modify 'n' -> 'g', and format is const char*, so we
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can't modify it directly. FLOAT_FORMATBUFLEN should be longer than
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we ever need this to be. There's an upcoming check to ensure it's
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big enough. */
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/* Issue 2264: code 'Z' requires copying the format. 'Z' is 'g', but
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also with at least one character past the decimal. */
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char tmp_format[FLOAT_FORMATBUFLEN];
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/* The last character in the format string must be the format char */
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format_char = format[format_len - 1];
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if (format[0] != '%')
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return NULL;
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/* I'm not sure why this test is here. It's ensuring that the format
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string after the first character doesn't have a single quote, a
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lowercase l, or a percent. This is the reverse of the commented-out
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test about 10 lines ago. */
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if (strpbrk(format + 1, "'l%"))
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return NULL;
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/* Also curious about this function is that it accepts format strings
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like "%xg", which are invalid for floats. In general, the
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interface to this function is not very good, but changing it is
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difficult because it's a public API. */
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if (!(format_char == 'e' || format_char == 'E' ||
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format_char == 'f' || format_char == 'F' ||
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format_char == 'g' || format_char == 'G' ||
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format_char == 'n' || format_char == 'Z'))
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return NULL;
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/* Map 'n' or 'Z' format_char to 'g', by copying the format string and
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replacing the final char with a 'g' */
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if (format_char == 'n' || format_char == 'Z') {
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if (format_len + 1 >= sizeof(tmp_format)) {
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/* The format won't fit in our copy. Error out. In
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practice, this will never happen and will be
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detected by returning NULL */
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return NULL;
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}
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strcpy(tmp_format, format);
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tmp_format[format_len - 1] = 'g';
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format = tmp_format;
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}
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/* Have PyOS_snprintf do the hard work */
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PyOS_snprintf(buffer, buf_size, format, d);
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/* Do various fixups on the return string */
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/* Get the current locale, and find the decimal point string.
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Convert that string back to a dot. Do not do this if using the
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'n' (number) format code, since we want to keep the localized
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decimal point in that case. */
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if (format_char != 'n')
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change_decimal_from_locale_to_dot(buffer);
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/* If an exponent exists, ensure that the exponent is at least
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MIN_EXPONENT_DIGITS digits, providing the buffer is large enough
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for the extra zeros. Also, if there are more than
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MIN_EXPONENT_DIGITS, remove as many zeros as possible until we get
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back to MIN_EXPONENT_DIGITS */
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ensure_minumim_exponent_length(buffer, buf_size);
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/* If format_char is 'Z', make sure we have at least one character
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after the decimal point (and make sure we have a decimal point). */
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if (format_char == 'Z')
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ensure_decimal_point(buffer, buf_size);
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/* If format_char is 'n', add the thousands grouping. */
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if (format_char == 'n')
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if (!add_thousands_grouping(buffer, buf_size))
|
|
return NULL;
|
|
|
|
return buffer;
|
|
}
|
|
|
|
double
|
|
PyOS_ascii_atof(const char *nptr)
|
|
{
|
|
return PyOS_ascii_strtod(nptr, NULL);
|
|
}
|