mirror of https://github.com/python/cpython
247 lines
9.3 KiB
Python
247 lines
9.3 KiB
Python
__all__ = ["TopologicalSorter", "CycleError"]
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_NODE_OUT = -1
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_NODE_DONE = -2
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class _NodeInfo:
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__slots__ = "node", "npredecessors", "successors"
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def __init__(self, node):
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# The node this class is augmenting.
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self.node = node
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# Number of predecessors, generally >= 0. When this value falls to 0,
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# and is returned by get_ready(), this is set to _NODE_OUT and when the
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# node is marked done by a call to done(), set to _NODE_DONE.
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self.npredecessors = 0
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# List of successor nodes. The list can contain duplicated elements as
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# long as they're all reflected in the successor's npredecessors attribute.
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self.successors = []
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class CycleError(ValueError):
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"""Subclass of ValueError raised by TopologicalSorter.prepare if cycles
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exist in the working graph.
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If multiple cycles exist, only one undefined choice among them will be reported
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and included in the exception. The detected cycle can be accessed via the second
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element in the *args* attribute of the exception instance and consists in a list
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of nodes, such that each node is, in the graph, an immediate predecessor of the
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next node in the list. In the reported list, the first and the last node will be
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the same, to make it clear that it is cyclic.
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"""
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pass
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class TopologicalSorter:
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"""Provides functionality to topologically sort a graph of hashable nodes"""
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def __init__(self, graph=None):
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self._node2info = {}
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self._ready_nodes = None
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self._npassedout = 0
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self._nfinished = 0
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if graph is not None:
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for node, predecessors in graph.items():
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self.add(node, *predecessors)
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def _get_nodeinfo(self, node):
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if (result := self._node2info.get(node)) is None:
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self._node2info[node] = result = _NodeInfo(node)
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return result
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def add(self, node, *predecessors):
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"""Add a new node and its predecessors to the graph.
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Both the *node* and all elements in *predecessors* must be hashable.
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If called multiple times with the same node argument, the set of dependencies
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will be the union of all dependencies passed in.
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It is possible to add a node with no dependencies (*predecessors* is not provided)
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as well as provide a dependency twice. If a node that has not been provided before
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is included among *predecessors* it will be automatically added to the graph with
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no predecessors of its own.
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Raises ValueError if called after "prepare".
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"""
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if self._ready_nodes is not None:
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raise ValueError("Nodes cannot be added after a call to prepare()")
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# Create the node -> predecessor edges
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nodeinfo = self._get_nodeinfo(node)
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nodeinfo.npredecessors += len(predecessors)
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# Create the predecessor -> node edges
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for pred in predecessors:
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pred_info = self._get_nodeinfo(pred)
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pred_info.successors.append(node)
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def prepare(self):
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"""Mark the graph as finished and check for cycles in the graph.
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If any cycle is detected, "CycleError" will be raised, but "get_ready" can
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still be used to obtain as many nodes as possible until cycles block more
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progress. After a call to this function, the graph cannot be modified and
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therefore no more nodes can be added using "add".
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"""
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if self._ready_nodes is not None:
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raise ValueError("cannot prepare() more than once")
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self._ready_nodes = [
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i.node for i in self._node2info.values() if i.npredecessors == 0
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]
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# ready_nodes is set before we look for cycles on purpose:
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# if the user wants to catch the CycleError, that's fine,
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# they can continue using the instance to grab as many
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# nodes as possible before cycles block more progress
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cycle = self._find_cycle()
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if cycle:
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raise CycleError(f"nodes are in a cycle", cycle)
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def get_ready(self):
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"""Return a tuple of all the nodes that are ready.
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Initially it returns all nodes with no predecessors; once those are marked
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as processed by calling "done", further calls will return all new nodes that
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have all their predecessors already processed. Once no more progress can be made,
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empty tuples are returned.
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Raises ValueError if called without calling "prepare" previously.
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"""
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if self._ready_nodes is None:
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raise ValueError("prepare() must be called first")
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# Get the nodes that are ready and mark them
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result = tuple(self._ready_nodes)
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n2i = self._node2info
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for node in result:
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n2i[node].npredecessors = _NODE_OUT
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# Clean the list of nodes that are ready and update
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# the counter of nodes that we have returned.
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self._ready_nodes.clear()
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self._npassedout += len(result)
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return result
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def is_active(self):
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"""Return ``True`` if more progress can be made and ``False`` otherwise.
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Progress can be made if cycles do not block the resolution and either there
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are still nodes ready that haven't yet been returned by "get_ready" or the
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number of nodes marked "done" is less than the number that have been returned
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by "get_ready".
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Raises ValueError if called without calling "prepare" previously.
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"""
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if self._ready_nodes is None:
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raise ValueError("prepare() must be called first")
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return self._nfinished < self._npassedout or bool(self._ready_nodes)
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def __bool__(self):
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return self.is_active()
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def done(self, *nodes):
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"""Marks a set of nodes returned by "get_ready" as processed.
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This method unblocks any successor of each node in *nodes* for being returned
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in the future by a call to "get_ready".
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Raises :exec:`ValueError` if any node in *nodes* has already been marked as
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processed by a previous call to this method, if a node was not added to the
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graph by using "add" or if called without calling "prepare" previously or if
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node has not yet been returned by "get_ready".
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"""
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if self._ready_nodes is None:
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raise ValueError("prepare() must be called first")
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n2i = self._node2info
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for node in nodes:
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# Check if we know about this node (it was added previously using add()
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if (nodeinfo := n2i.get(node)) is None:
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raise ValueError(f"node {node!r} was not added using add()")
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# If the node has not being returned (marked as ready) previously, inform the user.
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stat = nodeinfo.npredecessors
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if stat != _NODE_OUT:
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if stat >= 0:
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raise ValueError(
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f"node {node!r} was not passed out (still not ready)"
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)
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elif stat == _NODE_DONE:
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raise ValueError(f"node {node!r} was already marked done")
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else:
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assert False, f"node {node!r}: unknown status {stat}"
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# Mark the node as processed
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nodeinfo.npredecessors = _NODE_DONE
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# Go to all the successors and reduce the number of predecessors, collecting all the ones
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# that are ready to be returned in the next get_ready() call.
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for successor in nodeinfo.successors:
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successor_info = n2i[successor]
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successor_info.npredecessors -= 1
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if successor_info.npredecessors == 0:
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self._ready_nodes.append(successor)
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self._nfinished += 1
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def _find_cycle(self):
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n2i = self._node2info
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stack = []
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itstack = []
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seen = set()
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node2stacki = {}
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for node in n2i:
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if node in seen:
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continue
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while True:
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if node in seen:
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# If we have seen already the node and is in the
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# current stack we have found a cycle.
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if node in node2stacki:
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return stack[node2stacki[node] :] + [node]
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# else go on to get next successor
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else:
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seen.add(node)
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itstack.append(iter(n2i[node].successors).__next__)
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node2stacki[node] = len(stack)
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stack.append(node)
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# Backtrack to the topmost stack entry with
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# at least another successor.
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while stack:
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try:
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node = itstack[-1]()
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break
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except StopIteration:
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del node2stacki[stack.pop()]
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itstack.pop()
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else:
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break
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return None
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def static_order(self):
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"""Returns an iterable of nodes in a topological order.
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The particular order that is returned may depend on the specific
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order in which the items were inserted in the graph.
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Using this method does not require to call "prepare" or "done". If any
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cycle is detected, :exc:`CycleError` will be raised.
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"""
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self.prepare()
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while self.is_active():
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node_group = self.get_ready()
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yield from node_group
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self.done(*node_group)
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