cpython/Lib/test/test_stringprep.py

97 lines
3.0 KiB
Python

# To fully test this module, we would need a copy of the stringprep tables.
# Since we don't have them, this test checks only a few codepoints.
import unittest
from test import test_support
from stringprep import *
class StringprepTests(unittest.TestCase):
def test(self):
self.failUnless(in_table_a1("\u0221"))
self.failIf(in_table_a1("\u0222"))
self.failUnless(in_table_b1("\u00ad"))
self.failIf(in_table_b1("\u00ae"))
self.failUnless(map_table_b2("\u0041"), "\u0061")
self.failUnless(map_table_b2("\u0061"), "\u0061")
self.failUnless(map_table_b3("\u0041"), "\u0061")
self.failUnless(map_table_b3("\u0061"), "\u0061")
self.failUnless(in_table_c11("\u0020"))
self.failIf(in_table_c11("\u0021"))
self.failUnless(in_table_c12("\u00a0"))
self.failIf(in_table_c12("\u00a1"))
self.failUnless(in_table_c12("\u00a0"))
self.failIf(in_table_c12("\u00a1"))
self.failUnless(in_table_c11_c12("\u00a0"))
self.failIf(in_table_c11_c12("\u00a1"))
self.failUnless(in_table_c21("\u001f"))
self.failIf(in_table_c21("\u0020"))
self.failUnless(in_table_c22("\u009f"))
self.failIf(in_table_c22("\u00a0"))
self.failUnless(in_table_c21_c22("\u009f"))
self.failIf(in_table_c21_c22("\u00a0"))
self.failUnless(in_table_c3("\ue000"))
self.failIf(in_table_c3("\uf900"))
self.failUnless(in_table_c4("\uffff"))
self.failIf(in_table_c4("\u0000"))
self.failUnless(in_table_c5("\ud800"))
self.failIf(in_table_c5("\ud7ff"))
self.failUnless(in_table_c6("\ufff9"))
self.failIf(in_table_c6("\ufffe"))
self.failUnless(in_table_c7("\u2ff0"))
self.failIf(in_table_c7("\u2ffc"))
self.failUnless(in_table_c8("\u0340"))
self.failIf(in_table_c8("\u0342"))
# C.9 is not in the bmp
# self.failUnless(in_table_c9(u"\U000E0001"))
# self.failIf(in_table_c8(u"\U000E0002"))
self.failUnless(in_table_d1("\u05be"))
self.failIf(in_table_d1("\u05bf"))
self.failUnless(in_table_d2("\u0041"))
self.failIf(in_table_d2("\u0040"))
# This would generate a hash of all predicates. However, running
# it is quite expensive, and only serves to detect changes in the
# unicode database. Instead, stringprep.py asserts the version of
# the database.
# import hashlib
# predicates = [k for k in dir(stringprep) if k.startswith("in_table")]
# predicates.sort()
# for p in predicates:
# f = getattr(stringprep, p)
# # Collect all BMP code points
# data = ["0"] * 0x10000
# for i in range(0x10000):
# if f(unichr(i)):
# data[i] = "1"
# data = "".join(data)
# h = hashlib.sha1()
# h.update(data)
# print p, h.hexdigest()
def test_main():
test_support.run_unittest(StringprepTests)
if __name__ == '__main__':
test_main()