mirror of https://github.com/python/cpython
275 lines
5.9 KiB
Python
275 lines
5.9 KiB
Python
from test.test_support import verify, verbose, TestFailed, sortdict
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from collections import UserDict, UserList
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def e(a, b):
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print(a, b)
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def f(*a, **k):
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print(a, sortdict(k))
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def g(x, *y, **z):
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print(x, y, sortdict(z))
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def h(j=1, a=2, h=3):
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print(j, a, h)
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f()
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f(1)
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f(1, 2)
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f(1, 2, 3)
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f(1, 2, 3, *(4, 5))
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f(1, 2, 3, *[4, 5])
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f(1, 2, 3, *UserList([4, 5]))
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f(1, 2, 3, **{'a':4, 'b':5})
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f(1, 2, 3, *(4, 5), **{'a':6, 'b':7})
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f(1, 2, 3, x=4, y=5, *(6, 7), **{'a':8, 'b':9})
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f(1, 2, 3, **UserDict(a=4, b=5))
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f(1, 2, 3, *(4, 5), **UserDict(a=6, b=7))
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f(1, 2, 3, x=4, y=5, *(6, 7), **UserDict(a=8, b=9))
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# Verify clearing of SF bug #733667
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try:
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e(c=3)
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except TypeError:
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pass
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else:
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print("should raise TypeError: e() got an unexpected keyword argument 'c'")
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try:
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g()
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except TypeError as err:
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print("TypeError:", err)
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else:
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print("should raise TypeError: not enough arguments; expected 1, got 0")
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try:
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g(*())
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except TypeError as err:
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print("TypeError:", err)
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else:
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print("should raise TypeError: not enough arguments; expected 1, got 0")
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try:
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g(*(), **{})
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except TypeError as err:
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print("TypeError:", err)
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else:
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print("should raise TypeError: not enough arguments; expected 1, got 0")
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g(1)
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g(1, 2)
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g(1, 2, 3)
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g(1, 2, 3, *(4, 5))
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class Nothing: pass
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try:
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g(*Nothing())
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except TypeError as attr:
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pass
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else:
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print("should raise TypeError")
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class Nothing:
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def __len__(self):
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return 5
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try:
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g(*Nothing())
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except TypeError as attr:
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pass
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else:
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print("should raise TypeError")
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class Nothing:
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def __len__(self):
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return 5
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def __getitem__(self, i):
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if i < 3:
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return i
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else:
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raise IndexError(i)
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g(*Nothing())
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class Nothing:
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def __init__(self):
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self.c = 0
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def __iter__(self):
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return self
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try:
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g(*Nothing())
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except TypeError as attr:
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pass
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else:
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print("should raise TypeError")
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class Nothing:
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def __init__(self):
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self.c = 0
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def __iter__(self):
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return self
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def __next__(self):
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if self.c == 4:
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raise StopIteration
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c = self.c
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self.c += 1
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return c
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g(*Nothing())
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# make sure the function call doesn't stomp on the dictionary?
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d = {'a': 1, 'b': 2, 'c': 3}
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d2 = d.copy()
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verify(d == d2)
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g(1, d=4, **d)
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print(sortdict(d))
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print(sortdict(d2))
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verify(d == d2, "function call modified dictionary")
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# what about willful misconduct?
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def saboteur(**kw):
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kw['x'] = locals() # yields a cyclic kw
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return kw
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d = {}
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kw = saboteur(a=1, **d)
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verify(d == {})
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# break the cycle
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del kw['x']
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try:
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g(1, 2, 3, **{'x':4, 'y':5})
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except TypeError as err:
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print(err)
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else:
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print("should raise TypeError: keyword parameter redefined")
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try:
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g(1, 2, 3, a=4, b=5, *(6, 7), **{'a':8, 'b':9})
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except TypeError as err:
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print(err)
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else:
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print("should raise TypeError: keyword parameter redefined")
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try:
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f(**{1:2})
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except TypeError as err:
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print(err)
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else:
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print("should raise TypeError: keywords must be strings")
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try:
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h(**{'e': 2})
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except TypeError as err:
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print(err)
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else:
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print("should raise TypeError: unexpected keyword argument: e")
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try:
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h(*h)
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except TypeError as err:
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print(err)
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else:
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print("should raise TypeError: * argument must be a tuple")
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try:
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dir(*h)
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except TypeError as err:
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print(err)
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else:
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print("should raise TypeError: * argument must be a tuple")
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try:
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None(*h)
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except TypeError as err:
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print(err)
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else:
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print("should raise TypeError: * argument must be a tuple")
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try:
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h(**h)
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except TypeError as err:
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print(err)
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else:
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print("should raise TypeError: ** argument must be a dictionary")
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try:
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dir(**h)
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except TypeError as err:
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print(err)
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else:
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print("should raise TypeError: ** argument must be a dictionary")
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try:
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None(**h)
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except TypeError as err:
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print(err)
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else:
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print("should raise TypeError: ** argument must be a dictionary")
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try:
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dir(b=1,**{'b':1})
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except TypeError as err:
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print(err)
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else:
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print("should raise TypeError: dir() got multiple values for keyword argument 'b'")
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def f2(*a, **b):
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return a, b
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d = {}
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for i in range(512):
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key = 'k%d' % i
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d[key] = i
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a, b = f2(1, *(2, 3), **d)
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print(len(a), len(b), b == d)
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class Foo:
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def method(self, arg1, arg2):
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return arg1 + arg2
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x = Foo()
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print(Foo.method(*(x, 1, 2)))
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print(Foo.method(x, *(1, 2)))
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print(Foo.method(*(1, 2, 3)))
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print(Foo.method(1, *(2, 3)))
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# A PyCFunction that takes only positional parameters should allow an
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# empty keyword dictionary to pass without a complaint, but raise a
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# TypeError if the dictionary is non-empty.
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id(1, **{})
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try:
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id(1, **{"foo": 1})
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except TypeError:
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pass
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else:
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raise TestFailed('expected TypeError; no exception raised')
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a, b, d, e, v, k = 'A', 'B', 'D', 'E', 'V', 'K'
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funcs = []
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maxargs = {}
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for args in ['', 'a', 'ab']:
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for defargs in ['', 'd', 'de']:
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for vararg in ['', 'v']:
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for kwarg in ['', 'k']:
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name = 'z' + args + defargs + vararg + kwarg
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arglist = list(args) + ['%s="%s"' % (x, x) for x in defargs]
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if vararg: arglist.append('*' + vararg)
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if kwarg: arglist.append('**' + kwarg)
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decl = (('def %s(%s): print("ok %s", a, b, d, e, v, ' +
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'type(k) is type ("") and k or sortdict(k))')
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% (name, ', '.join(arglist), name))
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exec(decl)
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func = eval(name)
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funcs.append(func)
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maxargs[func] = len(args + defargs)
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for name in ['za', 'zade', 'zabk', 'zabdv', 'zabdevk']:
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func = eval(name)
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for args in [(), (1, 2), (1, 2, 3, 4, 5)]:
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for kwargs in ['', 'a', 'd', 'ad', 'abde']:
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kwdict = {}
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for k in kwargs: kwdict[k] = k + k
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print(func.__name__, args, sortdict(kwdict), '->', end=' ')
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try: func(*args, **kwdict)
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except TypeError as err: print(err)
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