mirror of https://github.com/python/cpython
219 lines
7.0 KiB
Python
Executable File
219 lines
7.0 KiB
Python
Executable File
# Class Date supplies date objects that support date arithmetic.
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#
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# Date(month,day,year) returns a Date object. An instance prints as,
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# e.g., 'Mon 16 Aug 1993'.
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#
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# Addition, subtraction, comparison operators, min, max, and sorting
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# all work as expected for date objects: int+date or date+int returns
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# the date `int' days from `date'; date+date raises an exception;
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# date-int returns the date `int' days before `date'; date2-date1 returns
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# an integer, the number of days from date1 to date2; int-date raises an
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# exception; date1 < date2 is true iff date1 occurs before date2 (&
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# similarly for other comparisons); min(date1,date2) is the earlier of
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# the two dates and max(date1,date2) the later; and date objects can be
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# used as dictionary keys.
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#
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# Date objects support one visible method, date.weekday(). This returns
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# the day of the week the date falls on, as a string.
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#
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# Date objects also have 4 read-only data attributes:
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# .month in 1..12
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# .day in 1..31
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# .year int or long int
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# .ord the ordinal of the date relative to an arbitrary staring point
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#
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# The Dates module also supplies function today(), which returns the
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# current date as a date object.
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#
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# Those entranced by calendar trivia will be disappointed, as no attempt
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# has been made to accommodate the Julian (etc) system. On the other
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# hand, at least this package knows that 2000 is a leap year but 2100
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# isn't, and works fine for years with a hundred decimal digits <wink>.
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# Tim Peters tim@ksr.com
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# not speaking for Kendall Square Research Corp
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# Adapted to Python 1.1 (where some hacks to overcome coercion are unnecessary)
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# by Guido van Rossum
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# vi:set tabsize=8:
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_MONTH_NAMES = [ 'January', 'February', 'March', 'April', 'May',
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'June', 'July', 'August', 'September', 'October',
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'November', 'December' ]
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_DAY_NAMES = [ 'Friday', 'Saturday', 'Sunday', 'Monday',
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'Tuesday', 'Wednesday', 'Thursday' ]
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_DAYS_IN_MONTH = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ]
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_DAYS_BEFORE_MONTH = []
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dbm = 0
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for dim in _DAYS_IN_MONTH:
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_DAYS_BEFORE_MONTH.append(dbm)
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dbm = dbm + dim
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del dbm, dim
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_INT_TYPES = type(1), type(1L)
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def _is_leap( year ): # 1 if leap year, else 0
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if year % 4 != 0: return 0
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if year % 400 == 0: return 1
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return year % 100 != 0
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def _days_in_year( year ): # number of days in year
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return 365 + _is_leap(year)
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def _days_before_year( year ): # number of days before year
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return year*365L + (year+3)/4 - (year+99)/100 + (year+399)/400
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def _days_in_month( month, year ): # number of days in month of year
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if month == 2 and _is_leap(year): return 29
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return _DAYS_IN_MONTH[month-1]
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def _days_before_month( month, year ): # number of days in year before month
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return _DAYS_BEFORE_MONTH[month-1] + (month > 2 and _is_leap(year))
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def _date2num( date ): # compute ordinal of date.month,day,year
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return _days_before_year( date.year ) + \
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_days_before_month( date.month, date.year ) + \
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date.day
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_DI400Y = _days_before_year( 400 ) # number of days in 400 years
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def _num2date( n ): # return date with ordinal n
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if type(n) not in _INT_TYPES:
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raise TypeError, 'argument must be integer: ' + `type(n)`
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ans = Date(1,1,1) # arguments irrelevant; just getting a Date obj
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del ans.ord, ans.month, ans.day, ans.year # un-initialize it
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ans.ord = n
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n400 = (n-1)/_DI400Y # # of 400-year blocks preceding
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year, n = 400 * n400, n - _DI400Y * n400
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more = n / 365
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dby = _days_before_year( more )
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if dby >= n:
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more = more - 1
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dby = dby - _days_in_year( more )
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year, n = year + more, int(n - dby)
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try: year = int(year) # chop to int, if it fits
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except (ValueError, OverflowError): pass
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month = min( n/29 + 1, 12 )
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dbm = _days_before_month( month, year )
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if dbm >= n:
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month = month - 1
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dbm = dbm - _days_in_month( month, year )
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ans.month, ans.day, ans.year = month, n-dbm, year
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return ans
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def _num2day( n ): # return weekday name of day with ordinal n
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return _DAY_NAMES[ int(n % 7) ]
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class Date:
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def __init__( self, month, day, year ):
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if not 1 <= month <= 12:
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raise ValueError, 'month must be in 1..12: ' + `month`
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dim = _days_in_month( month, year )
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if not 1 <= day <= dim:
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raise ValueError, 'day must be in 1..' + `dim` + ': ' + `day`
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self.month, self.day, self.year = month, day, year
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self.ord = _date2num( self )
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# don't allow setting existing attributes
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def __setattr__( self, name, value ):
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if self.__dict__.has_key(name):
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raise AttributeError, 'read-only attribute ' + name
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self.__dict__[name] = value
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def __cmp__( self, other ):
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return cmp( self.ord, other.ord )
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# define a hash function so dates can be used as dictionary keys
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def __hash__( self ):
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return hash( self.ord )
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# print as, e.g., Mon 16 Aug 1993
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def __repr__( self ):
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return '%.3s %2d %.3s ' % (
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self.weekday(),
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self.day,
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_MONTH_NAMES[self.month-1] ) + `self.year`
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# Python 1.1 coerces neither int+date nor date+int
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def __add__( self, n ):
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if type(n) not in _INT_TYPES:
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raise TypeError, 'can\'t add ' + `type(n)` + ' to date'
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return _num2date( self.ord + n )
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__radd__ = __add__ # handle int+date
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# Python 1.1 coerces neither date-int nor date-date
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def __sub__( self, other ):
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if type(other) in _INT_TYPES: # date-int
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return _num2date( self.ord - other )
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else:
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return self.ord - other.ord # date-date
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# complain about int-date
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def __rsub__( self, other ):
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raise TypeError, 'Can\'t subtract date from integer'
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def weekday( self ):
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return _num2day( self.ord )
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def today():
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import time
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local = time.localtime(time.time())
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return Date( local[1], local[2], local[0] )
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DateTestError = 'DateTestError'
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def test( firstyear, lastyear ):
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a = Date(9,30,1913)
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b = Date(9,30,1914)
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if `a` != 'Tue 30 Sep 1913':
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raise DateTestError, '__repr__ failure'
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if (not a < b) or a == b or a > b or b != b:
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raise DateTestError, '__cmp__ failure'
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if a+365 != b or 365+a != b:
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raise DateTestError, '__add__ failure'
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if b-a != 365 or b-365 != a:
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raise DateTestError, '__sub__ failure'
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try:
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x = 1 - a
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raise DateTestError, 'int-date should have failed'
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except TypeError:
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pass
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try:
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x = a + b
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raise DateTestError, 'date+date should have failed'
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except TypeError:
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pass
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if a.weekday() != 'Tuesday':
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raise DateTestError, 'weekday() failure'
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if max(a,b) is not b or min(a,b) is not a:
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raise DateTestError, 'min/max failure'
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d = {a-1:b, b:a+1}
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if d[b-366] != b or d[a+(b-a)] != Date(10,1,1913):
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raise DateTestError, 'dictionary failure'
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# verify date<->number conversions for first and last days for
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# all years in firstyear .. lastyear
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lord = _days_before_year( firstyear )
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y = firstyear
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while y <= lastyear:
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ford = lord + 1
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lord = ford + _days_in_year(y) - 1
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fd, ld = Date(1,1,y), Date(12,31,y)
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if (fd.ord,ld.ord) != (ford,lord):
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raise DateTestError, ('date->num failed', y)
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fd, ld = _num2date(ford), _num2date(lord)
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if (1,1,y,12,31,y) != \
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(fd.month,fd.day,fd.year,ld.month,ld.day,ld.year):
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raise DateTestError, ('num->date failed', y)
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y = y + 1
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