mirror of https://github.com/python/cpython
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#! /usr/local/bin/python
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# Calculate your unbirthday count (see Alice in Wonderland).
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# This is defined as the number of days from your birth until today
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# that weren't your birthday. (The day you were born is not counted).
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# Leap years make it interesting.
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import sys
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import time
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import calendar
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def main():
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# Note that the range checks below also check for bad types,
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# e.g. 3.14 or (). However syntactically invalid replies
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# will raise an exception.
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if sys.argv[1:]:
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year = eval(sys.argv[1])
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else:
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year = input('In which year were you born? ')
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if year in range(100):
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print 'I\'ll assume that by', year,
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year = year + 1900
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print 'you mean', year, 'and not the arly Christian era'
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elif year not in range(1850, 2000):
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print 'It\'s hard to believe you were born in', year
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return
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#
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if sys.argv[2:]:
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month = eval(sys.argv[2])
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else:
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month = input('And in which month? (1-12) ')
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if month not in range(1, 13):
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print 'There is no month numbered', month
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return
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#
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if sys.argv[3:]:
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day = eval(sys.argv[3])
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else:
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day = input('And on what day of that month? (1-31) ')
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if month == 2 and calendar.isleap(year):
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maxday = 29
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else:
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maxday = calendar.mdays[month]
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if day not in range(1, maxday+1):
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print 'There are no', day, 'days in that month!'
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return
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#
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bdaytuple = (year, month, day)
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bdaydate = mkdate(bdaytuple)
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print 'You were born on', format(bdaytuple)
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#
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todaytuple = time.localtime(time.time())[:3]
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todaydate = mkdate(todaytuple)
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print 'Today is', format(todaytuple)
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#
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if bdaytuple > todaytuple:
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print 'You are a time traveler. Go back to the future!'
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return
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#
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if bdaytuple == todaytuple:
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print 'You were born today. Have a nice life!'
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return
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#
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days = todaydate - bdaydate
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print 'You have lived', days, 'days'
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#
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age = 0
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for y in range(year, todaytuple[0] + 1):
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if bdaytuple < (y, month, day) <= todaytuple:
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age = age + 1
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#
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print 'You are', age, 'years old'
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#
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if todaytuple[1:] == bdaytuple[1:]:
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print 'Congratulations! Today is your', nth(age), 'birthday'
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print 'Yesterday was your',
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else:
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print 'Today is your',
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print nth(days - age), 'unbirthday'
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def format((year, month, day)):
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return '%d %s %d' % (day, calendar.month_name[month], year)
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def nth(n):
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if n == 1: return '1st'
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if n == 2: return '2nd'
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if n == 3: return '3rd'
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return '%dth' % n
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def mkdate((year, month, day)):
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# Januari 1st, in 0 A.D. is arbitrarily defined to be day 1,
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# even though that day never actually existed and the calendar
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# was different then...
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days = year*365 # years, roughly
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days = days + (year+3)/4 # plus leap years, roughly
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days = days - (year+99)/100 # minus non-leap years every century
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days = days + (year+399)/400 # plus leap years every 4 centirues
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for i in range(1, month):
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if i == 2 and calendar.isleap(year):
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days = days + 29
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else:
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days = days + calendar.mdays[i]
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days = days + day
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return days
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main()
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