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PyErr_Format() does not return a new reference; it always returns NULL. 

This closes SF bug #488387.
This commit is contained in:
Fred Drake 2001-12-03 16:36:43 +00:00
parent dbb53d9918
commit f07125ee53
1 changed files with 5 additions and 7 deletions
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12
Doc/api/exceptions.tex
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@ -121,11 +121,11 @@ for each thread.
\begin{cfuncdesc}{PyObject*}{PyErr_Format}{PyObject *exception,
const char *format, \moreargs}
This function sets the error indicator. \var{exception} should be a
Python exception (string or class, not an instance). \var{format}
should be a string, containing format codes, similar to
\cfunction{printf()}. The \code{width.precision} before a format
code is parsed, but the width part is ignored.
This function sets the error indicator and returns \NULL..
\var{exception} should be a Python exception (string or class, not
an instance). \var{format} should be a string, containing format
codes, similar to \cfunction{printf()}. The \code{width.precision}
before a format code is parsed, but the width part is ignored.
\begin{tableii}{c|l}{character}{Character}{Meaning}
\lineii{c}{Character, as an \ctype{int} parameter}
@ -137,8 +137,6 @@ for each thread.
An unrecognized format character causes all the rest of the format
string to be copied as-is to the result string, and any extra
arguments discarded.
A new reference is returned, which is owned by the caller.
\end{cfuncdesc}
\begin{cfuncdesc}{void}{PyErr_SetNone}{PyObject *type}